On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type

It is shown that the solutions of the Sine Gordon equation with a source of the integral type can be found by the method of the inverse scattering problem for the Dirac type operator on the real line.

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Опубліковано в: :Журнал математической физики, анализа, геометрии
Дата:2006
Автори: Khasanov, A.B., Urazboev, G.U.
Формат: Стаття
Мова:English
Опубліковано: Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України 2006
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Цитувати:On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type / A.B. Khasanov, G.U. Urazboev // Журнал математической физики, анализа, геометрии. — 2006. — Т. 2, № 3. — С. 287-298. — Бібліогр.: 11 назв. — англ.

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Digital Library of Periodicals of National Academy of Sciences of Ukraine
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spelling Khasanov, A.B.
Urazboev, G.U.
2016-10-01T13:31:16Z
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2006
On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type / A.B. Khasanov, G.U. Urazboev // Журнал математической физики, анализа, геометрии. — 2006. — Т. 2, № 3. — С. 287-298. — Бібліогр.: 11 назв. — англ.
1812-9471
https://nasplib.isofts.kiev.ua/handle/123456789/106620
It is shown that the solutions of the Sine Gordon equation with a source of the integral type can be found by the method of the inverse scattering problem for the Dirac type operator on the real line.
en
Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України
Журнал математической физики, анализа, геометрии
On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type
Article
published earlier
institution Digital Library of Periodicals of National Academy of Sciences of Ukraine
collection DSpace DC
title On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type
spellingShingle On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type
Khasanov, A.B.
Urazboev, G.U.
title_short On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type
title_full On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type
title_fullStr On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type
title_full_unstemmed On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type
title_sort on the sine-gordon equation with a self-consistent source of the integral type
author Khasanov, A.B.
Urazboev, G.U.
author_facet Khasanov, A.B.
Urazboev, G.U.
publishDate 2006
language English
container_title Журнал математической физики, анализа, геометрии
publisher Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України
format Article
description It is shown that the solutions of the Sine Gordon equation with a source of the integral type can be found by the method of the inverse scattering problem for the Dirac type operator on the real line.
issn 1812-9471
url https://nasplib.isofts.kiev.ua/handle/123456789/106620
citation_txt On the Sine-Gordon Equation with a Self-Consistent Source of the Integral Type / A.B. Khasanov, G.U. Urazboev // Журнал математической физики, анализа, геометрии. — 2006. — Т. 2, № 3. — С. 287-298. — Бібліогр.: 11 назв. — англ.
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fulltext Journal of Mathematical Physics, Analysis, Geometry 2006, vol. 2, No. 3, pp. 287�298 On the Sine�Gordon Equation with a Self-Consistent Source of the Integral Type A.B. Khasanov, G.U. Urazboev Urgench State University 14 H. Olimjan Str., Urgench, 740000, Uzbekistan E-mail:ahasanov2002@mail.ru Received May 27, 2004 It is shown that the solutions of the Sine�Gordon equation with a source of the integral type can be found by the method of the inverse scattering problem for the Dirac type operator on the real line. Key words: Sine�Gordon equation, inverse scattering method, Jost solu- tions, scattering data. Mathematics Subject Classi�cation 2000: 37K40, 37K15, 35Q53, 35Q55. 1. Introduction In this paper we consider the problem of integration of the following system of equations 8< : uxt = sinu+ 1R �1 � � 2 1 � � 2 2 � d� ; L� = ��; (1) u(x; 0) = u0(x); x 2 R; (2) where L(t) = i � d dx ux 2 ux 2 � d dx � , ux = @u(x;t) @x ; uxt = @ 2 u(x;t) @x@t ; and u0(x) (�1 < x <1) is a function satisfying the conditions: 1) u0(x) � 0(mod 2�) as jxj ! 1; 1Z �1 � (1 + jxj) ��u00(x)��+ ��u000(x)��� dx <1; (3) 2) the operator L(0) does not have the points of spectral singularity (see [6]) and has only simple eigenvalues �1(0); �2(0); : : : ; �N (0). c A.B. Khasanov, G.U. Urazboev, 2006 A.B. Khasanov, G.U. Urazboev We assume that the vector function � = (�1(x; �; t); �2(x; �; t)) T is a solution of the equation L� = �� satisfying the condition �! A (�; t) � exp(�i�x) exp(i�x) � as x!1; (4) where A(�; t) is a continuous function satisfying the condition A(��; t) = A(�; t); 1Z �1 jA(�; t)j2d� <1; (5) for all nonnegative values of t. We assume that the solution u(x; t) of the problem (1)�(5) exists, possesses the required smoothness, and tends to its limits su�ciently rapidly as x! �1, i.e., for all t � 0 it satis�es the condition u(x; t) � 0(mod 2�) as jxj ! 1; 1R �1 ((1 + jxj) jux(x; t)j+ juxx(x; t)j) dx <1: (6) The main objective of this paper is to derive representations for the solutions u(x; t), �(x; �; t) within the framework of the inverse scattering method for L(t) operator. The full description of the solutions of the Sine�Gordon equation without sources was given in [1�2]. The scattering problem for L(t) operator was studied in the papers by V.E. Zakharov, A.B. Shabat [3], L.P. Nizhnik, Fam Loy Woo [4], I.S. Frolov [5], A.B. Khasanov [6] and in many others. Note that the similar problem for the KdV equation was considered in the paper [7]. In the V.K. Mel'nikov's paper [8] there was obtained evolution of the scattering dates for the selfadjoint Dirac type operator with the potential which is a solution of the NLS equation with the integral type source. Notice however that in our case operator L(t) is not self-adjoint. As it is well known, under the condition (6) the not self-adjoint operator L(t) has a �nite number of complex eigenvalues (in general multiple). Moreover, operator L(t) may have a �nite number of real points of spectral singularity. The continuous spectrum of the operator L(t) �lls up the real line, i.e., �ess(L(t)) = (�1; 1). For simplicity we suppose that operator L(t) has a �nite number of simple complex eigenvalues, and does not have points of singular spectrum. 288 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 On the Sine�Gordon Equation... 2. Scattering Problem for Zakharov�Shabat Eigenvalue Problem In this section we present some facts from the theory of the direct and inverse scattering problems for the operator L(t) (for example, see [9]). For a while in this section we omit the dependence of functions on t. We consider the eigenvalue problem� v1x + i�v1 = u0(x)v2 v2x � i�v2 = �u0(x)v1; (7) on the interval �1 < x <1. The potential u0(x) is assumed to satisfy the condition u(x) � 0(mod 2�) as jxj ! 1; 1Z �1 ((1 + jxj) ju0(x)j) dx <1: (8) We de�ne the Jost solution of the problem (7)�(8) with the following asymptotic values ' � � 1 0 � e�i� x �' � � 0 �1 � ei� x 9>>= >>; as x! �1; � � 0 1 � ei� x � � � 1 0 � e�i� x 9>>= >>; as x!1: For real � the pairs of functions f'; �'g and � ; � are the pairs of linearly independent solutions of (7), and therefore ' = a(�) � + b(�) ; �' = ��a(�) +�b(�) � ; (9) where a(�) = W f'; g � '1 2 � '2 1, b(�) = W � � ; ' , a(�)a(��) + b(�)b(��) = 1. For real � the coe�cient b(�) has the following asymptotic b(�) = O � 1 j�j � as j�j ! 1, Im� = 0. The coe�cient a(�) (�a(�)) can be analytically extended into the upper (lower) half-plane Im � > 0 (Im� < 0). The function a(�) has the asymptotic a(�) = 1 +O � 1 j�j � as j�j ! 1, Im� � 0. Besides, in the half-plane Im � > 0 (Im� < 0) the function a(�) (�a(�)) has a �nite number of zeros at the points �k � ��k � , and these points are the eigenvalues of the operator L = i d dx u 0(x) 2 u 0(x) 2 � d dx ! ; Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 289 A.B. Khasanov, G.U. Urazboev so that '(x; �k) = Ck (x; �k) ( �'(x; �k) = �Ck � (x; �k)), k = 1; 2; : : : ; N . It is clear that the function 'k � '(x; �k) is an eigenfunction of the operator L corresponding to the eigenvalue �k. We assume that the operator L does not have multiple eigenvalues. The requirement of absence of the points of spectral singularity of the operator L(t) means the absence of real zeros of function a(�). The class of the potentials satisfying a(�) 6= 0 as � 2 R1 is not empty. For example, this class contains �unre�ected� potentials, i.e., potential for which b(�) = 0. In this case the equation a(�)a(��) = 1, � 2 R1 is valid. We have the following integral representation for the function ' [9] = � 0 1 � ei� x + 1Z x K (x; s) ei� sds; (10) where the kernel K (x; s) = � K1 (x; s) K2 (x; s) � does not depend on � and is related to the potential u(x) by the formulae u0 (x) = 4K1 (x; x) ; (u0 (x)) 2 = 8 dK2 (x; x) dx : (11) Components K1(x; y), K2(x; y) of the kernel K (x; y) in the representa- tion (10), for y > x are solutions of the integral Gelfand�Levitan�Marchenko equations K1(x; y)� F (x+ y) + 1R x 1R x K1(x; z)F (z + s)F (s+ y)dsdz = 0; K2(x; y) + 1R x F (x+ s)F (s+ y)ds+ 1R x 1R x K2(x; z)F (z + s)F (s+ y)dsdz = 0; where F (x) = 1 2� 1R �1 b(�) a(�) ei�xd� � i NP j=1 Cje i�jx. Now the potential can be expressed via K1 (x; y) by the formula (11). The set of the quantities n r+ (�) = b(�) a(�) ; �k; Ck; k = 1; 2; : : : ; N o is called the scattering data for equations (7). It is worthy to remark that the vector functions hn (x) = d d� ('� Cn ) ���� � = �n _a (�n) ; n = 1; 2; : : : ; N; (12) 290 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 On the Sine�Gordon Equation... are solutions of the equations Lhn = �nhn and have the following asymp- totics hn � �Cn � 0 1 � ei�nx as x! �1; hn � � 1 0 � e�i�nx as x!1: (13) According to (13) we obtain Wf'n; hng � 'n1hn2 � 'n2hn1 = �Cn; n = 1; 2; : : : ; N: (14) It is easy to see that the following statement is true. Lemma 1. If Y (x; �) and Z (x; �) are solutions of the equations LY = �Y and LZ = �Z, then d dx (y1z2 � y2z1) = �i (� � �) (y1z2 + y2z1) ; d dx (y1z1 + y2z2) = �i (� + �) (y1z1 � y2z2) : 3. Evolution of the Scattering Data Let the potential u (x; t) of the problem (7) be a solution of the system of equations 8< : uxt = sinu+ 1R �1 (�21 � �22) d� ; L� = ��: (15) We put G(x; t) = 1R �1 (�21 � �22) d�. According to (4) �(x; �; t) = A(�; t) � � (x; �; t) + (x; �; t) � ; and therefore, by using (9), as well as the asymptotic for the Jost solution and a(�); b(�) and Riemann�Lebesgue lemma in each nonnegative t, we have G(x; t) = o(1) as x ! �1. The �rst equation of (15) can be rewritten in the form uxt = sin u+G: (16) Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 291 A.B. Khasanov, G.U. Urazboev Lemma 2. If potential u (x; t) of the problem (7) is a solution of equation (16), then the scattering data depend on t as dr+ dt = � i 2� r+ + 1 2a2 1Z �1 � G'2 2 +G'2 1 � dx; (Im� = 0) ; dCn dt = 0 @� i 2�n + 1Z �1 G 2 (hn2 n2 + hn1 n1) dx 1 ACn; d�n dt = i 1R �1 (G'2 n2 +G'2 n1) dx 4 1R �1 'n1'n2dx ; n = 1; 2; : : : ; N: P r o o f. Here we use the method of [10] (see also [11]). We set A = � i cosu 4� i sinu 4� i sinu 4� � i cos u 4� � : It is easy to see that [L;A] � LA� AL = �i � 0 sinu 2 sinu 2 0 � : (17) The operator L (t) depends on time t as a parameter and therefore @L @t = i � 0 uxt 2 uxt 2 0 � : (18) Comparing formulas (17) and (18) with the equation (16), we can see that the equation (16) is identical to the operator relation @L @t + [L;A] = iR; (19) where R = � 0 G 2 G 2 0 � . Let ' (x; �; t) be the Jost solution of the equation L' = �': 292 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 On the Sine�Gordon Equation... We di�erentiate this relation with respect to time Lt'+ L't = �'t; (20) and substitute Lt from (19) into (20). This results to (L� �) ('t � A') = �iR': (21) We seek the solutions of (21) in the form 't � A' = � (x) + � (x)': (22) To �nd �(x) and �(x) we use the equation M�x +M�x' = �R'; (23) where M = � 1 0 0 �1 � : According to (9) ̂TM' = �'̂TM = a; ̂TM = '̂TM' = 0; where '̂ = � '2 '1 � . Multiplying (23) by '̂T and ̂T we yield �x = '̂TR' a ; �x = � ̂TR' a : (24) On the basis of (6) and the asymptotic of the Jost solution we have 't � A'! � i 4� � 1 0 � e�i�x as x! �1: Therefore from (22) one gets � (x)! � i 4� ; � (x)! 0 as x! �1: By solving (24) we obtain � (x) = 1 a xZ �1 '̂TR'dx; � (x) = � 1 a xZ �1 ̂TR'dx� i 4� : Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 293 A.B. Khasanov, G.U. Urazboev Therefore the relation (22) can be rewritten in the form 't � A' = 1 a xZ �1 '̂TR'dx � + 0 @�1 a xZ �1 ̂TR'dx� i 4� 1 A': (25) Using (9) we take the limit in (25) as x!1 and obtain at = � 1Z �1 ̂TR'dx; bt = � i 2� b + 1 a 1Z �1 '̂TR'dx� b a 1Z �1 ̂TR'dx: Consequently, for Im� = 0 we get dr + dt = � i 2� r + + 1 2a2 1Z �1 � G' 2 2 +G' 2 1 � dx: We di�erentiate the relation 'n = Cn n with respect to t @' @t ���� � = �n + @' @� ���� � = �n d�n dt = dCn dt n + Cn @ @t ���� � = �n + Cn @ @� ���� � = �n d�n dt ; (26) and substitute d d� ('� Cn ) ���� � = �n from (12) into (26). This results in the following formula: @'n @t = dCn dt n +Cn @ n @t � _a (�n) hn d�n dt ; (27) where @'n @t � @' @t ���� � = �n . Similarly to the continuous spectrum case, by using (14) for the discrete spec- trum, we have @'n @t �A'n = 0 @� 1 Cn xZ �1 '̂ T nR'ndx 1 Ahn + 0 @ 1 Cn xZ �1 ĥ T nR'n dx� i 4�n 1 A'n: 294 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 On the Sine�Gordon Equation... Hence, according to (27), we have dCn dt n + Cn @ n @t � _a (�n) d�n dt hn � CnA n = � 1 Cn xR �1 '̂ T nR'ndx ! hn + 1 Cn xR �1 ĥ T nR'n dx� i 4�n ! Cn n : (28) Using (13) we pass to the limit in (28), as x!1, and obtain dCn dt = 0 @� i 2�n + 1Z �1 ĥ T nR ndx 1 ACn; d�n dt = 1R �1 '̂ T n R'n dx Cn _a (�n) : Therefore dCn dt = 0 @� i 2�n + 1Z �1 G 2 (hn2 n2 + hn1 n1) dx 1 ACn ; d�n dt = 1R �1 � G' 2 n2 +G' 2 n1 � dx 2Cn _a (�n) : Hence, according to the relation _a (�n) = � 2i Cn 1Z �1 'n1'n2dx; we have d�n dt = i 1R �1 � G' 2 n2 +G' 2 n1 � dx 4 1R �1 'n1'n2dx : Lemma 2 is proved. Let in Lemma 2 G = 1Z �1 � � 2 1 � � 2 2 � d�: Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 295 A.B. Khasanov, G.U. Urazboev According to Lemma 1 1Z �1 � � 2 1(x; �) � � 2 2(x; �) � � ' 2 1(x; �) + ' 2 2(x; �) � dx = i 2 lim R!1 � (�1(x;�)'1(x;�)+�2(x;�)'2(x;�)) 2 �+� + (�1(x;�)'2(x;�)��2(x;�)'1(x;�)) 2 ��� ����R �R : By using (4), (5), (9) and the Riemann�Lebesgue lemma, we obtain 1Z �1 � G' 2 2 +G' 2 1 � dx = 2ab 0 @�A2(�; t) + iV:p: 1Z �1 A 2(�; t) � + � d� 1 A : Similarly, 1Z �1 � G' 2 n2 +G' 2 n1 � dx = 0; 1Z �1 (Ghn2 n2 +Ghn1 n1) dx = 2i 1Z �1 A 2(�; t)�a(�; t)a(�; t) � + �n d�: By using Lemma 2 and the relation �a(�)a(�) = 1 1+r+(�)r+(��) , we have the following theorem Theorem. If the functions u (x; t), �1(�; x; t), �2(�; x; t are solutions of the problem (1)�(6), then the scattering data of the operator L (t) depend on t as dr + dt = 0 @� i 2� + �A 2(�; t) + iV:p: 1Z �1 A 2(�; t) � + � d� 1 A r + ; (Im� = 0) ; dCn dt = � i 2�n + i 1R �1 A 2(�;t) (1+r+(�;t)r+(��;t))(�+�n) ! Cn; d�n dt = 0; n = 1; 2; : : : ; N: The above relations determine completely the evolution of the scattering data for the operator L (t), which allows us to �nd the solutions of problem for (1)�(6) by using the inverse scattering problem method. In conclusion we consider the following example. Let uj t=0 = 4arctg � e 2x � ; A(�; t) = � 1 + � 2 �� 1 2 : 296 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 On the Sine�Gordon Equation... In this case r+(�; 0) = 0, �1(0) = i, C1(0) = �2i. Therefore, by using the theorem r +(�; t) = 0; �1(t) = i; C1(t) = �2i exp � � � 1 2 t � : According to the inverse scattering problem method u(x; t) = 4arctg � exp � 2x� � � 1 2 t �� ; �1(x; �) = 1p �2+1 � cos �x+ (1�e�2x+g)(cos �x�� sin �x (1+�2)ch(2x�g) � + ip �2+1 � � sin �x+ (1+e�2x+g)(sin �x+� cos �x (1+�2)ch(2x�g) � ; �2(x; �) = 1p �2+1 � cos �x� (1+e�2x+g)(cos �x�� sin �x (1+�2)ch(2x�g) � + ip �2+1 � sin �x+ (1�e�2x+g)(sin �x+� cos �x (1+�2)ch(2x�g) � ; where g(t) = (��1) t 2 . References [1] V.E. Zakharov, L.A. Takhtajan L, and L.D. Faddeev, A Complete Description of the Solutions of the Sine�Gordon Equation. � Dokl. Akad. Nauk USSR 219 (1974), No. 6, 1334�1337. (Russian) [2] M.J. Ablowitz, D.J. Kaup, A.C. Newell, and H. Segur, Method for Solving the Sine�Gordon Equation. � Phys. Rev. Lett. 30 (1973), No. 25, 1262�1264. [3] V.E. Zakharov and A.B. Shabat, Exact Theory of Two-Dimensional Self-Focusing and One-Dimensional Self-Modulation of Waves in Nonlinear Media. � JETP 61 (1971), No. 1, 44�47. (Russian) [4] L.P.Nizhnik and Fam Loy Woo, An Inverse Scattering Problem on the Semi-Axis with a Nonselfadjoint Potential Matrix. � Ukr. Mat. Zh. 26 (1974), No. 4, 469�486. (Russian) [5] I.S. Frolov, An Inverse Scattering Problem for a Dirac System on the Whole Axis. � Dokl. Akad. Nauk USSR 207 (1972), No. 1, 44�47. (Russian) [6] A.B. Khasanov, The Inverse Problem of Scattering Theory for a System of Two Nonselfadjoint First-Order Equations. � Dokl. Akad. Nauk USSR 277 (1984), No. 3, 559�562. (Russian) Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3 297 A.B. Khasanov, G.U. Urazboev [7] V.K. Mel'nikov, Integration of the Korteweg-de Vries Equation with a Source. � Inverse Probl. 6 (1990), 233�246. [8] V.K. Mel'nikov, Integration of the Nonlinear Schrodinger Equation with a Source. � Inverse Probl. 8 (1992), 133�147. [9] Mark J. Ablowitz and Harley Segur, Solitons and the Inverse Scattering Transform. � SIAM, Philadelphia, 1981. [10] V.I. Karpman and E.M. Maslov, The Structure of Tails, Appearing under Soliton Perturbations. � JETP 73 (1977), 2 (8), 537�559. (Russian) [11] G.L. Lamb, Jr., Elements of Solution Theory. A Wiley Intersci. Publ. John Wiley & Sons, New York, NY, 1980. 298 Journal of Mathematical Physics, Analysis, Geometry, 2006, vol. 2, No. 3