Conditions on a Surface F² is subset of Eⁿ to lie in E⁴
We consider a surface F² in Eⁿ with a non-degenerate ellipse of normal curvature whose plane passes through the corresponding surface point. The definition of three types of points is given in dependence of the position of the point relatively to the ellipse. If in the domain D is subset of F² all t...
Saved in:
| Date: | 2013 |
|---|---|
| Main Authors: | , |
| Format: | Article |
| Language: | English |
| Published: |
Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України
2013
|
| Series: | Журнал математической физики, анализа, геометрии |
| Online Access: | https://nasplib.isofts.kiev.ua/handle/123456789/106742 |
| Tags: |
Add Tag
No Tags, Be the first to tag this record!
|
| Journal Title: | Digital Library of Periodicals of National Academy of Sciences of Ukraine |
| Cite this: | Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ / Yu.A. Aminov, Ia. Nasiedkina // Журнал математической физики, анализа, геометрии. — 2013. — Т. 9, № 2. — С. 127-149. — Бібліогр.: 13 назв. — англ. |
Institution
Digital Library of Periodicals of National Academy of Sciences of Ukraine| id |
nasplib_isofts_kiev_ua-123456789-106742 |
|---|---|
| record_format |
dspace |
| spelling |
nasplib_isofts_kiev_ua-123456789-1067422025-02-23T19:07:43Z Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ Aminov, Yu.A. Nasiedkina, Ia. We consider a surface F² in Eⁿ with a non-degenerate ellipse of normal curvature whose plane passes through the corresponding surface point. The definition of three types of points is given in dependence of the position of the point relatively to the ellipse. If in the domain D is subset of F² all the points are of the same type, then the domain D is said also to be of this type. This classification of points and domains is linked with the classification of partial differential equations of the second order. The theorems on the surface to lie in E⁴ are proved under the fulfilment of certain boundary conditions. Some examples of the surfaces are constructed to show that the boundary conditions of the theorems are essential. Рассмотрена поверхность F² в Eⁿ с невырожденным эллипсом нормальной кривизны, плоскость которого проходит через соответствующую точку поверхности. Дано определение трех типов точек на поверхности в зависимости от расположения точки относительно этого эллипса. Если в области D из F² все точки принадлежат одному типу, то говорим, что область D также принадлежит к этому типу. Эта классификация точек и областей оказывается связанной с классификацией дифференциальных уравнений в частных производных второго порядка. Доказаны теоремы о принадлежности поверхности к E⁴ при выполнении определенных краевых условий. Построены примеры поверхностей, показывающие, что краевые условия существенны. 2013 Article Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ / Yu.A. Aminov, Ia. Nasiedkina // Журнал математической физики, анализа, геометрии. — 2013. — Т. 9, № 2. — С. 127-149. — Бібліогр.: 13 назв. — англ. 1812-9471 https://nasplib.isofts.kiev.ua/handle/123456789/106742 en Журнал математической физики, анализа, геометрии application/pdf Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України |
| institution |
Digital Library of Periodicals of National Academy of Sciences of Ukraine |
| collection |
DSpace DC |
| language |
English |
| description |
We consider a surface F² in Eⁿ with a non-degenerate ellipse of normal curvature whose plane passes through the corresponding surface point. The definition of three types of points is given in dependence of the position of the point relatively to the ellipse. If in the domain D is subset of F² all the points are of the same type, then the domain D is said also to be of this type. This classification of points and domains is linked with the classification of partial differential equations of the second order. The theorems on the surface to lie in E⁴ are proved under the fulfilment of certain boundary conditions. Some examples of the surfaces are constructed to show that the boundary conditions of the theorems are essential. |
| format |
Article |
| author |
Aminov, Yu.A. Nasiedkina, Ia. |
| spellingShingle |
Aminov, Yu.A. Nasiedkina, Ia. Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ Журнал математической физики, анализа, геометрии |
| author_facet |
Aminov, Yu.A. Nasiedkina, Ia. |
| author_sort |
Aminov, Yu.A. |
| title |
Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ |
| title_short |
Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ |
| title_full |
Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ |
| title_fullStr |
Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ |
| title_full_unstemmed |
Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ |
| title_sort |
conditions on a surface f² is subset of eⁿ to lie in e⁴ |
| publisher |
Фізико-технічний інститут низьких температур ім. Б.І. Вєркіна НАН України |
| publishDate |
2013 |
| url |
https://nasplib.isofts.kiev.ua/handle/123456789/106742 |
| citation_txt |
Conditions on a Surface F² is subset of Eⁿ to lie in E⁴ / Yu.A. Aminov, Ia. Nasiedkina // Журнал математической физики, анализа, геометрии. — 2013. — Т. 9, № 2. — С. 127-149. — Бібліогр.: 13 назв. — англ. |
| series |
Журнал математической физики, анализа, геометрии |
| work_keys_str_mv |
AT aminovyua conditionsonasurfacef2issubsetofentolieine4 AT nasiedkinaia conditionsonasurfacef2issubsetofentolieine4 |
| first_indexed |
2025-11-24T14:31:15Z |
| last_indexed |
2025-11-24T14:31:15Z |
| _version_ |
1849682481324752896 |
| fulltext |
Journal of Mathematical Physics, Analysis, Geometry
2013, vol. 9, No. 2, pp. 127–149
Conditions on a Surface F 2 ⊂ En to lie in E4
Yu.A. Aminov and Ia. Nasiedkina
Mathematics Division, B. Verkin Institute for Low Temperature Physics and Engineering
National Academy of Sciences of Ukraine
47 Lenin Ave., Kharkiv 61103, Ukraine
E-mail: aminov@ilt.kharkov.ua
Received May 30, 2011, revised January 30, 2012
We consider a surface F 2 in En with a non-degenerate ellipse of normal
curvature whose plane passes through the corresponding surface point. The
definition of three types of points is given in dependence of the position of
the point relatively to the ellipse. If in the domain D ⊂ F 2 all the points
are of the same type, then the domain D is said also to be of this type. This
classification of points and domains is linked with the classification of partial
differential equations of the second order. The theorems on the surface to
lie in E4 are proved under the fulfilment of certain boundary conditions.
Some examples of the surfaces are constructed to show that the boundary
conditions of the theorems are essential.
Key words: an ellipse of normal curvature, asymptotic lines, character-
istics, boundary conditions.
Mathematics Subject Classification 2000: 53A05.
1. Introduction
Conditions for a two-dimensional surface in E4 to lie in a hyperplane E3 are
well known [1, p. 146]. In this paper we consider the surface F 2 in En with
non-degenerate ellipse of normal curvature such that the plane of this ellipse for
each point x of the surface passes through this point x. This condition means that
the point codimension of the surface is equal to 2. Notice that the condition on
the plane is fulfilled for all surfaces lying in E4. We say that the point x ∈ F 2
is of
1) hyperbolic type if x lies outside the ellipse of normal curvature,
2) parabolic type if x lies on this ellipse,
3) elliptic type if x lies inside this ellipse.
This paper is prepared with the support of grants from National Academy of Sciences of
Ukraine and Russian Foundation for Basic Researches, 2012.
c© Yu.A. Aminov and Ia. Nasiedkina, 2013
Yu.A. Aminov and Ia. Nasiedkina
If all points of some domain G of a surface are of one of the types, then
the domain G is said also to be of this type. If the domain G has the points
of different types, then it is said to be of mixed type. Below we will connect
this splitting into types with the classification of differential equations in partial
derivatives of the second order. We will also give the conditions on the surfaces
F 2 ⊂ En of types 1)–3), under which F 2 is also to lie in some E4.
2. About the Surfaces of Hyperbolic Type in En
Let us consider the surface F 2 with the non-degenerate ellipse of normal
curvature in the space En such that all points x ∈ F 2 are of hyperbolic type.
We recall the definition of the normal curvature ellipse.
Denote by kn(τ) the vector of normal curvature of F 2 determined by the
tangent vector τ ∈ Tx at every point x ∈ F 2. The vector kn(τ) is in the normal
space Nx. Let the start of this vector lie at the point x. Then the set of end-points
of vectors kn(τ), when τ rotates in Tx, forms the indicatrix of normal curvature.
This set is a closed plane curve, namely an ellipse, perhaps degenerated at a
segment or a point.
If τ is defined by the differentials of du1, du2, and Lα
ijduiduj are the second
fundamental forms with respect to the unit normals nα, α = 1, . . . , n− 2, then
kn(τ) =
Lα
ijduiduj
ds2
nα,
where ds2 = gijduiduj is the metric form.
In a normal space Nx, we introduce the Cartesian coordinates Xα with origin
at the point x and basic vectors nα. Then the coordinates of the point M of the
indicatrix have the form
Xα =
Lα
ijduiduj
gijduiduj
. (1)
On the surface F 2 we construct geometrically some net of curves. In this
case, through the point x it is possible to draw two straight lines tangent to
the ellipse. We denote the points of contacts by P and Q. Each of this points
corresponds to the vector of normal curvature knP or knQ. In the tangent plane
of F 2 for the vector knP there exists a tangent direction such that the vector of
normal curvature for this direction coincides with knP . We have this direction
at each point of the considering domain and hence we have the field of tangent
directions. This field generates some family of integral curves which we call
characteristics. With the help of the vector knQ we get another family of curves
— also characteristics. The curves of these two families are not tangent to each
other. On the surface, these families form some net of curves which we will call
specially hyperbolic net.
128 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
Theorem 1. Let the surface F 2 ⊂ En of the class C4 with non-degenerate
ellipse of normal curvature be of hyperbolic type. And let D be a triangular
domain on F 2 bounded by two characteristics — curves η1 and η2 from different
families of the specially hyperbolic net beginning at the point x, and some curve
γ of the class C2 which crosses η1, η2 and is not tangent to the characteristics.
Assume that there exists some hyperplane E4 such that both the curve γ ⊂ E4
and the tangent surface strip along γ lie in E4.
Then the whole domain D lies in E4.
P r o o f. On the surface of the domain D introduce some coordinates u1, u2
of the class C4. Then the fundamental forms of F 2 are the following:
ds2 = gijduiduj ,
IIα = Lα
ijduiduj .
The normals to F 2 will be chosen as follows. Let the vectors n1, n2 define the plane
of the ellipse. Other normals nk, k = 3, 4, . . . , n − 2, are taken to be orthogonal
to this plane. Hence Lk
ij = 0, k = 3, 4, . . . , n− 2.
The Gauss decomposition has the form
rij = Γk
ijrk + Lα
ijnα.
Consider this decomposition for i = 1, j = 2
r12 = Γk
12rk + Lα
12nα.
Due to the choice of normals, we have
r12 = Γk
12rk + L1
12n1 + L2
12n2. (2)
Lemma 1. The coefficients L̄1
12, and L̄2
12 in the special hyperbolic system of
coordinates are equal to zero.
P r o o f. We construct a new system of the coordinates ξ, η such that the
coordinate lines are the characteristics. In this system, the coefficients of the
second fundamental forms L̄α
12 are
L
α
12 = Lα
ij
∂ui
∂ξ
∂uj
∂η
, α = 1, 2.
Take a straight line which does not cross the ellipse when passing through x.
Then the normal n1 is the direction vector of this straight line, and n2 is a vector
orthogonal to n1. We suppose that n2 is directed to the half-plane where the
ellipse lies.
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 129
Yu.A. Aminov and Ia. Nasiedkina
Let M be an arbitrary point outside the ellipse. Then its coordinate Y > 0.
For the non-zero shift du1, du2, we have
Y =
L2
ijduiduj
ds2
> 0.
If ϕ is the angle between the strait line xM and n1, then
ctgϕ =
X
Y
=
L1
ijduiduj
L2
ijduiduj
.
The extremal value of the angle ϕ will be attained when the straight line
xM is the tangent of the ellipse. If the ellipse is non-degenerate, then we have
two extremal values of ϕ and two straight lines xM that are tangents of the
ellipse. As in the case with the main directions of the 2-dimensional surface in
E3, for determining the corresponding directions in the tangent plane of F 2, it is
necessary to solve the equation
|L1
ij − λL2
ij | = 0.
Let λ1 and λ2 be the roots of this equation, and τ = {τ i}, ν = {νi} be
two directions {du1, du2} in the tangent plane of F 2 corresponding to λ1 and λ2.
Then the following system takes place:
(L1
11 − λ1L
2
11)τ
1 + (L1
12 − λ1L
2
12)τ
2 = 0,
(L1
11 − λ1L
2
12)τ
1 + (L1
22 − λ1L
2
22)τ
2 = 0,
(L1
11 − λ2L
2
11)ν
1 + (L1
12 − λ2L
2
12)ν
2 = 0,
(L1
12 − λ2L
2
12)ν
1 + (L1
22 − λ2L
2
22)ν
2 = 0.
Multiply the first equation on ν1, the second equation on ν2, and take their
sum to obtain
L1
ijτ
iνj − λ1L
2
ijτ
iνj = 0.
Similarly, for the third and fourth equations we have
L1
ijτ
iνj − λ2L
2
ijτ
iνj = 0.
Therefore,
(λ1 − λ2)L2
ijτ
iνj = 0.
Because (λ1 − λ2) 6= 0, we have L2
ijτ
iνj = 0 and L1
ijτ
iνj = 0. We take the
functions η(u1, u2) and ξ(u1, u2) such that the lines η = const are the integral
130 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
curves of the vector field τ , and the lines ξ = const are the integral curves of the
field ν. Then,
ηu1 = −qτ2, ξu1 = −pν2,
ηu2 = qτ1, ξu2 = pν1,
with some functions p 6= 0 and q 6= 0.
Let us write the transformation from the coordinates ξ, η to u1, u2
u1 = u1(ξ, η),
u2 = u2(ξ, η).
If J = J
(
u1,u2
ξ,η
)
is the Jacobian of the transformation, then
ξu1 =
1
J
∂u2
∂η
, ηu1 = − 1
J
∂u2
∂ξ
, τ1 =
1
qJ
∂u1
∂ξ
, ν1 = − 1
pJ
∂u1
∂η
,
ξu2 = − 1
J
∂u1
∂η
, ηu2 =
1
J
∂u1
∂ξ
, τ2 =
1
qJ
∂u2
∂ξ
, ν2 = − 1
pJ
∂u2
∂η
.
Hence,
0 = Lα
ijτ
iνj = − 1
pqJ2
Lα
ij
∂ui
∂ξ
∂uj
∂η
= − 1
pqJ2
L̄α
12.
Therefore, L̄α
12 = 0.
Lemma 1 is proved.
Lemma 2. The surface F 2 with respect to the coordinates ξ, η belongs to the
regularity class C2.
P r o o f. For the proof of this lemma we will need the result of the following
lemma.
Lemma 3. Suppose F 2 has the regularity of the class C4 with respect to the
coordinates (u1, u2). Then the coefficients Lα
ij = (rij , nα) have the regularity of
the class C2.
P r o o f. First, we will find the regularity class of the normals nα, α =
3, . . . , n − 2 . As the plane of the ellipse passes through x, the vectors rij lie
in the 4-dimensional space spanned by ru1 , ru2 , n1, n2. Therefore, five vectors
ru1 , ru2 , ru1u1 , ru1u2 , ru2u2 are linearly dependent. As the ellipse of normal curva-
ture is non-degenerate, there exist four linearly independent vectors between the
first and the second derivatives of r, for example, ru1 , ru2 , ru1u2 , ru2u2 . Let the
normal nα have the coordinates ξj , j = 1, . . . , n. To determine the normals, we
can write the following system:
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 131
Yu.A. Aminov and Ia. Nasiedkina
(ru1 , nα) = x1u1
ξ1 + x2u1
ξ2 + . . . + xnu1
ξn = 0,
(ru2 , nα) = x1u2
ξ1 + x2u2
ξ2 + . . . + xnu2
ξn = 0,
(ru1u2 , nα) = x1u1u2
ξ1 + x2u1u2
ξ2 + . . . + xnu1u2
ξn = 0,
(ru2u2 , nα) = x1u2u2
ξ1 + x2u2u2
ξ2 + . . . + xnu2u2
ξn = 0.
The equations of this system are linearly independent. Let, for example, the
determinant be not equal to zero
∆ =
∣∣∣∣∣∣∣∣
x1u1
. . . x4u1
x1u2
. . . x4u2
x1u1u2
. . . x4u1u2
x1u2u2
. . . x4u1u2
∣∣∣∣∣∣∣∣
6= 0.
By solving the system of the linear equations, we get
ξ1 = ∆−1(ξ5A1 + ξ6A2 + . . . + ξnAn−4),
ξ2 = ∆−1(ξ5B1 + ξ6B2 + . . . + ξnBn−4),
ξ3 = ∆−1(ξ5C1 + ξ6C2 + . . . + ξnCn−4),
ξ4 = ∆−1(ξ5D1 + ξ6D2 + . . . + ξnDn−4),
where ∆, Ai, Bi, Ci, Di are some minors of the regularity of the class C2. Setting
the values ξ5, . . . , ξn, we get the n − 4 normals. Hence, the normals nα, α =
3, . . . , n − 2 have the regularity of the class C2. To obtain the regular fields of
the normals n1, n2, we write the system
(ruk
, ni) = 0, i = 1, 2,
(nα, ni) = 0, α = 3, . . . , n− 2.
As in the above, we get that ni, i = 1, 2 belong to the class C2. Hence, Lα
ij ∈ C2.
Remark that in the given construction the vectors nj may not be orthogonal
to each other. But it is not difficult to check that the process of orthogonality
gives new normals of the same class of regularity. Lemma 3 is proved.
Continue the proof of Lemma 2.
From the equation |L1
ij − λL2
ij | = 0 and Lemma 3 it follows that λi ∈ C2.
Therefore, the fields τ and ν are of the class C2. We have the system of differential
equations of the first order
ξu1ν
1 + ξu2ν
2 = 0,
ηu1τ
1 + ηu2τ
2 = 0.
132 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
The coefficients of this system are of the class C2. Then, by the theorem on
the regular dependence of solutions of an ordinary differential equation on initial
data (see, for example, [10, p. 92 § 2] and for the existence of the solution see
[10, p. 255], the functions ξ, η also belong to the class C2. Lemma 2 is proved.
Equation (2) can be written in the canonical form
rξη = Γ1
12rξ + Γ2
12rη. (3)
Both the considering curve γ and the surface strip lie in some space E4. Let n0
be a constant vector from a normal space orthogonal to E4. Denote U = (r, n0).
From (3) it follows that
Uξη = Γ1
12Uξ + Γ2
12Uη. (4)
We suppose that the origin of the Cartesian coordinate in En lies in E4. The
conditions of the theorem imply that
U |γ = 0,
Uν |γ = 0,
where Uν is the derivative on F 2 at the direction orthogonal to γ.
According to the theorem on the uniqueness of solutions in the theory of
differential equations of the second order of hyperbolic type (see [2, p. 439], [3,
p. 65]), we may conclude that U(ξ, η) ≡ 0 in the domain D. It means that D
lies in the hyperplane orthogonal to n0. If we take n0 as an arbitrary constant
vector in the space orthogonal to E4, then the domain D lies in E4.
3. About the Surfaces of Parabolic Type in En
Consider the case when every point x ∈ F 2 lies on the ellipse of normal
curvature corresponding to this point. In the plane Tx, which is tangent to the
surface F 2, there exists the direction τ for which kn(τ) = 0. The integral curves
of the field of the vectors τ are asymptotic curves in the usual sense of differential
geometry.
Introduce a system of the coordinates (ξ, η) on the surface with a family of
asymptotic lines as ξ-lines. The second family of the coordinate η-lines can be
taken arbitrarily as a regular family of curves crossing asymptotic lines transver-
sally. For example, we can take the family of orthogonal trajectories of the family
of asymptotic lines. Then the vector position r of F 2 is
r = r(ξ, η).
Write the Gauss decomposition with i = j = 1,
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 133
Yu.A. Aminov and Ia. Nasiedkina
r11 = Γk
11rk + Lα
11nα.
As the ξ-lines are asymptotic, Lα
11 = 0, α = 1, . . . , n− 2. For r(ξ, η), we have
the parabolic equation
r11 = Γk
11rk.
Theorem 2. Let the analytical surface F 2 ⊂ En with the ellipse of normal
curvature of non-degenerate type be of parabolic type. Let the domain D ⊂ F 2
be some strip bounded by two asymptotic curves. Suppose that some curve γ,
crossing transversally all asymptotic lines in the strip and the tangent surface
strip along γ lie in the some subspace E4.
Then D also lies in this subspace E4.
P r o o f. For proving, we introduce the function U = (r, n0), where n0 is the
normal vector from the space orthogonal to E4. We get the equation
Uξξ = Γ1
11Uξ + Γ2
11Uη. (5)
Suppose that γ is given by the equation ξ = 0. Conditions on the curve γ
give zero conditions for the Cauchy problem
U(0, η) = 0,
Uξ(0, η) = 0.
By the Cauchy–Kovalevskaya theorem [11, p. 22], in the neighborhood of γ
(that is, ξ = 0) there exists only one solution U ≡ 0. Hence, by the analyticity
of F 2, the domain D lies in the subspace orthogonal to n0. By the arbitrariness
of n0, D lies in E4.
In the theory of parabolic differential equations there are other uniqueness
theorems. We can formulate and prove the theorem not supposing analyticity of
the surface, but imposing additional conditions.
Theorem 3. Let the surface F 2 ⊂ En of the regularity class C5 with non-
degenerate ellipse of normal curvature be of parabolic type. Let the domain D ⊂
F 2 be bounded by two asymptotic lines and by two curves γ and γ1 crossing the
asymptotic lines transversally. Suppose that the geodesic curvature of asymptotic
lines in D is nonnegative. Let the curve γ lie in some E4 together with the tangent
surface strip along γ. Then the whole domain D lies in E4.
134 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
P r o o f. For the proof of this theorem, we use the theorem on the uniqueness
of solutions for differential equations of parabolic type proved by E.M. Landis [4],
where the equation
∂2U
∂x2
= a(t, x)
∂U
∂t
+ b(t, x)
∂U
∂x
+ c(t, x)U (6)
is considered in some domain G. On the coefficients of this equation the following
conditions are imposed:
1. The modules of the coefficients are limited by 1,
2. The coefficient a(t, x) has a derivative with respect to t, the coefficient
b(t, x) has a derivative with respect to x, and
∣∣∣∣
∂a
∂t
∣∣∣∣ < 1,
∣∣∣∣
∂b
∂x
∣∣∣∣ < 1.
3. In the domain G a ≥ 0, c ≥ 0.
4. The solution U(x, t) of (6) in G is of the class C2.
In [4], the following uniqueness theorem is proved.
Theorem 4. Let G be a part of the strip Π = t1 < t < t2 situated between
two non-crossing curves Γ1 and Γ2 with one-to-one projections on the t-axis and
connecting the opposite sides of Π. Let U(x, t) be a solution of (6) belonging to
C1 in D̄. Suppose that Γ2 is a smooth curve, and
U |Γ2=
∂U
∂n
|Γ2= 0.
Then in G
U ≡ 0.
Here ∂U
∂n is a derivative in the direction orthogonal to Γ2.
Give an explanation of the nonnegative geodesic curvature of asymptotic line.
If the coordinates ξ, η are introduced in D, then on the basic curve η = 0 the
vector of the curvature is directed inside D. The curvature vector of asymptotic
lines inside D builds an acute angle or π
2 with positive direction of the η-line.
To apply the Landis theorem, we have to verify the conditions on the coef-
ficients. We put x = ξ and t = η. Then the coefficients from Condition 3 in
Theorem 4 are a(t, x) = Γ2
11, b(t, x) = Γ1
11, and c(t, x) = 0 in our case. Remark
that Γk
ij ∈ C2 and, hence, in the domain D both the functions and the derivatives
are limited. The boundedness condition of modules by 1 can be satisfied by a
new parametrization of the coordinate lines.
Remark that Γ2
11 is connected with the geodesic curvature of asymptotic line.
Indeed,
Γ2
11 =
1
2W 2
(2g11
∂g12
∂ξ
− g12
∂g11
∂ξ
− g11
∂g11
∂η
),
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 135
Yu.A. Aminov and Ia. Nasiedkina
where gij are the coefficients of the metric, and W =
√
g11g22 − g2
12. The geodesic
curvature 1
ρg
can be written as (see [5, § 83, 127]
1
ρg
=
1
2Wg
3
2
11
(2g11
∂g12
∂ξ
− g12
∂g11
∂ξ
− g11
∂g11
∂η
).
Comparing these two expressions, we have
Γ2
11 =
g
3
2
11
W
1
ρg
. (7)
Hence, the sign Γ2
11 depends on the sign of 1
ρg
. By Condition 3 in Theorem
3, the coefficient a(x, t) ≥ 0 is satisfied if 1
ρg
≥ 0. The boundary conditions on
γ will coincide with the boundary conditions of Landis’ theorem [4] if we take γ
instead of Γ2.
Thus, in D we have U(ξ, η) ≡ 0. Therefore, D ⊂ E4.
In the theory of parabolic equations, differential equations are usually written
in the form of the generalized heat equations, namely with the derivative chosen
with respect to t (see [6]). This theorem will be used for proving the theorem
bellow.
Determine a non-closed contour Ω. Suppose the point C has the coordinates
(a, T ); the point A has the coordinates (a, 0); the point B has the coordinates
(b, 0) and the point K has the coordinates (b, T ) (here we suppose that a < b, T >
0). Then the contour Ω consists of the intercepts of coordinate lines. Consider
the domain D with the boundary CABKC.
Theorem 5. Suppose that F 2 ⊂ En of the class C5 with non-degenerate
ellipse of normal curvature is of parabolic type. Let the contour Ω be situated in
some space of E4. Let the geodesic curvature of asymptotic lines in D be positive.
Then the whole domain D lies in E4.
P r o o f. Begin with considering the contour Ω.
The intercept AB is an asymptotic line of F 2 and, consequently, the tangent
surface strip along AB lies in E4 automatically. Although, on CA and BK the
condition on the tangent surface strip is absent.
The contour Ω consists of an intercept of the coordinate line η = 0 and two
intercepts of the coordinate η-lines. Rewrite Eq. (5) in the form of the generalized
heat equation
Uη =
1
Γ2
11
Uξξ +
Γ1
11
Γ2
11
Uξ. (8)
By the condition 1
ρg
> 0 and (7), we have Γ2
11 6= 0. Hence the coefficients of
this equation have the regularity of the class C2. For (8), we apply the uniqueness
136 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
theorem for parabolic equations (see [6]) and obtain that U ≡ 0 in D. The
Theorem 5 is proved.
Consider now an infinitely long strip bounded by two complete asymptotic
lines. We suppose that a system of the coordinates (ξ, η) in this strip can be
introduced by using the family of asymptotic lines and the second family of
the lines crossing the curves of the first family transversally. For example, it is
possible to construct an orthogonal coordinates system where the strip is bounded
by the basic curve Γ : η = 0 and by the curve Γ1: η = T which is said to be
free. Let the parameter ξ be the arc length on Γ. Define the width of the strip.
Every point P ⊂ Γ1 has some coordinates (ξ, T ). Let l(ξ) be the shortest distance
between P and Γ along F 2. The number l(ξ) is called the variable width of the
strip.
Theorem 6. Suppose that F 2 ⊂ En of the class C5 with non-degenerate
ellipse of normal curvature is of parabolic type. Suppose that D is an infinite strip
between two complete asymptotic lines Γ and Γ1. Suppose that the asymptotic
lines in D have a positive geodesic curvature, and the following conditions in D
are fulfilled: ∣∣∣∣
1
Γ2
11
∣∣∣∣ ≤ M,
∣∣∣∣
Γ1
11
Γ2
11
∣∣∣∣ ≤ M(|ξ|+ 1),
|l(ξ)| ≤ Beβξ2
, B, β > 0,
where M, B, and β are some positive numbers. If the basic curve Γ lies in some
E4, then the whole domain D lies in E4.
P r o o f. We apply Theorem 7 from [8, p. 63], which is a generalization
of A.N. Tikhonov’s theorem from [9] proved for the classical heat equation. Let
x = (x1, . . . , xn) be a varying point in En. Suppose that in the domain D,
the function U(x, t) has continuous second derivatives with respect to x and
continuous first derivatives with respect to the parameter t. The theorem is
formulated as follows.
Theorem 7. Let L be a parabolic operator
L(U) =
n∑
i,j=1
aij(x, t)
∂2U
∂ui∂uj
+
n∑
i,j=1
bi(t, x)
∂U
∂xi
+ c(x, t)U − ∂U
∂t
,
where ∑
aij(x, t)ξiξj > 0
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 137
Yu.A. Aminov and Ia. Nasiedkina
for all vectors ξ = {ξi} 6= 0 with continuous coefficients in Rn × (0, T ], and the
following conditions be satisfied:
|aij(x, t)| ≤ M,
|bi(x, t)| ≤ M(|x|+ 1),
|c(x, t)| ≤ M(|x|2 + 1).
Then there exists not more than one solution of the equation
L(U) = f(x, t)
in Rn × (0, T ] such that U(x, 0) = ϕ(x) in Rn and whenever
|U(x, t)| ≤ Bexpβ|x|2, B, β > 0, (9)
where M,B and β are some positive constants.
Remark that for the heat equation (9), the condition from [9] is essential.
Namely, if |U(x, t)| ≤ Beβ(x2+ε) and ε > 0, then the uniqueness theorem is not
true.
Apply this theorem to Eq. (8) under the conditions f(x, t) = 0, φ(x) = 0.
Remark that |U(ξ, η)| is equal to a distance from the corresponding point of the
surface to E4. By the condition of Theorem 6, we have
|U(ξ, η)| ≤ l(ξ) ≤ Beβξ2
.
Consequently, all conditions of Theorem 7 are fulfilled. Hence, under the
given boundary conditions and limitations imposed on the coefficients, Eq. (8)
has the unique solution U(ξ, η) ≡ 0. Thus, D lies in E4. Finally, Theorem 6 is
proved.
Give a few examples of the surface strips whose metrics satisfy the conditions
of Theorem 6:
1) A universal covering of a ring on a plane between two concentric circles.
The exterior contour is taken as a basic curve. The metric of the plane can be
written in the form ds2 = η2dξ2 + dη2. Then Γ1
11 = 0, Γ2
11 = −η, and Eq. (8)
takes the form uη = − 1
ηuξξ.
2) A ring on a half-sphere.
3) A strip on the Lobachevsky plane to be considered below in Sec. 5.
4) A local convex infinitely long curve γ with the radius position ρ(ξ) on the
plane. The curvature k of γ satisfies the restrictions 0 < k1 ≤ k ≤ k2, where
k1, k2 are constants. The strip consists of the family of parallel curves. The vector
position of a point in the plane has the form r(ξ, η) = ρ(ξ) + ην(ξ), where ν(ξ)
138 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
is a unit normal to γ. The metric form of the plane is ds2 = (1− ηk)2dξ2 + dη2.
Introduce the restrictions on η: 0 < η < 1−ε
k2
, where 0 < ε < 1 and |kξ| ≤ M =
const. Then,
∣∣∣∣
1
Γ2
11
∣∣∣∣ ≤
1
εk1
,
∣∣∣∣
Γ1
11
Γ2
11
∣∣∣∣ ≤
∣∣∣∣
(1− ε)kξ
k2ε2k1
∣∣∣∣ ≤ M1 = const.
Thus all conditions of Theorem 6 for this strip are fulfilled.
4. On the Surfaces of Elliptic Type in En
Theorem 8. Let the domain D be homeomorphic to a disk and be of elliptic
type. Assume that the surface has the regularity of the class C4,α. Suppose the
boundary of D is a curve γ ∈ C1 which lies in some E4. Then the whole domain
D lies in E4.
P r o o f. In contrast to the theorems from Sections 1–3, the condition that
the tangent surface strip along γ lies in E4 is not necessary.
Theorem 8 can be proved by using the theory of elliptic equations or some
geometrical considerations.
First we are to obtain an elliptic equation for the vector position r(x1, x2) of
F 2 with the coordinates x1, x2. Suppose that the coordinates x1, x2 are intro-
duced in the whole simply connected domain D. Write the Gauss expansions by
using the covariant derivatives
r,ij = Lα
ijnα.
Recall that Lα
ij ≡ 0, α = 3, . . . , n−2 because the plane of the ellipse of normal
curvature passes through x ∈ F 2. Multiply the right- and the left-sides of the
Gauss equations by some numbers Ωij
r,ij Ωji = Lα
ijΩ
jinα.
Assume that Ωji have the following properties: Lα
ijΩ
ji = 0, α = 1, 2 and
Ωij = Ωji. Then we obtain the equation for the vector position r(x1, x2)
r,11 Ω11 + 2r,12 Ω12 + r,22 Ω22 = 0. (10)
Write Ωij in terms of the coefficients Lα
ij
Ω11 =
∣∣∣∣
L1
12 L1
22
L2
12 L2
22
∣∣∣∣ , Ω12 = −1
2
∣∣∣∣
L1
11 L1
22
L2
11 L2
22
∣∣∣∣ , Ω22 =
∣∣∣∣
L1
11 L1
12
L2
11 L2
12
∣∣∣∣ .
For Eq. (10) to be elliptic, the inequality
(Ω12)2 − Ω11Ω22 < 0,
should be fulfilled.
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 139
Yu.A. Aminov and Ia. Nasiedkina
Determine the sign of (Ω12)2 − Ω11Ω22 which depends on disposition of the
point x relatively to the ellipse. We use a special system of coordinates on F 2
and obtain the law of transformation for (Ω12)2 − Ω11Ω22 under the transition
from x1, x2 to the coordinates u1, u2. Then, by the law of transformation of Ωji
to Ωij , determine
Ωij = J3Ωαβ ∂ui
∂xα
∂uj
∂xβ
,
where J(x1,x2
u1,u2 ) is a Jacobian of transformation. The obtained Ωij are said to be
relative tensors with weight 3 (see [13, p. 237]).
Consider, for example, the expressions
Ω11 =
∣∣∣∣∣
L
1
12 L
1
22
L
2
12 L
2
22
∣∣∣∣∣ ,
where L
σ
ij are the coefficients of the second quadratic form in a new coordinate
system. The coordinates transformation influences on the coefficients of the sec-
ond quadratic form in the following way:
L
σ
ij = Lσ
αβ
∂xα
∂ui
∂xβ
∂uj
.
Consequently,
Ω11 =
∣∣∣∣∣
L1
αβ
∂xα
∂u1
∂xβ
∂u2 L1
γδ
∂xγ
∂u2
∂xδ
∂u2
L2
αβ
∂xα
∂u1
∂xβ
∂u2 L2
γδ
∂xγ
∂u2
∂xδ
∂u2
∣∣∣∣∣
= J
{∣∣∣∣
L1
11 L1
21
L2
11 L2
21
∣∣∣∣
(
∂x1
∂u2
)2
+
∣∣∣∣
L1
11 L1
22
L2
11 L2
22
∣∣∣∣
∂x1
∂u2
∂x2
∂u2
+
∣∣∣∣
L1
12 L1
22
L2
12 L2
22
∣∣∣∣
(
∂x2
∂u2
)2
}
.
Substitute the determinants consisting of Lσ
ij by Ωij and use the derivatives
∂uβ
∂xj instead of ∂xi
∂uα . We obtain
Ω11 = J3
(
Ω22
(
∂u1
∂x2
)2
+ 2Ω12 ∂u1
∂x2
∂u1
∂x1
+ Ω11
(
∂u1
∂x1
)2
)
= J3Ωαβ ∂u1
∂xα
∂u1
∂xβ
.
For the ellipticity to be preserved, the expression (Ω12)2−Ω11Ω22 should not
change its sign when transforming from one coordinate system to another
∣∣∣∣∣
Ω11 Ω12
Ω12 Ω22
∣∣∣∣∣ = J6
∣∣∣∣∣
Ωαβ ∂u1
∂xα
∂u1
∂xβ Ωγδ ∂u1
∂xγ
∂u2
∂xδ
Ωαβ ∂u2
∂xα
∂u1
∂xβ Ωγδ ∂u2
∂xγ
∂u2
∂xδ
∣∣∣∣∣
140 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
= J5 ∂u1
∂xβ
∂u2
∂xδ
(
Ω1βΩ2δ − Ω2βΩ1δ
)
= J4
(
Ω11Ω22 − (Ω12)2
)
. (11)
At it is seen from the last relation, the sign of (11) is not changed.
It is easy to ascertain that under the rotation of normal basis n1, n2, the sign
of the numbers Ωij is not changed.
On the surface, take some point x0. In the neighborhood of x0, construct
special orthogonal coordinate system in the following way. If at the point x0 the
ellipse of normal curvature is not a circle, then take a vector of normal curvature
whose end-point lies at one of summits of the ellipse (for example, at the largest
one). Let the vector τ in the tangent plane be corresponding to the vector of
normal curvature. Draw the coordinate u1-curve on F 2 tangential to τ at x0 and
thus get the family of the u1-lines, namely the first family. If the ellipse of normal
curvature is a circle, then τ can be taken arbitrarily. Taking the orthogonal
trajectories of the first family, we get the second family of the coordinate lines.
Chose the normals n1, n2 at x0 to be parallel to the axes of the ellipse (if it
is not a circle), and take them arbitrarily in opposite case. Additionally, put
g11 = g22 = 1 at x0. Under this choice of the coordinates and normals, at x0 we
have
L1
11 = α + a, L2
11 = β,
L1
12 = 0, L2
12 = b,
L1
22 = α− a, L2
22 = β,
where α and β are the coordinates of the origin of the ellipse, and a, b are its
half-axes.
Consequently, at x0 we get
(Ω12)2 − Ω11Ω22 =
(∣∣∣∣
α + a α− a
β β
∣∣∣∣
2
− 4
∣∣∣∣
0 α− a
b β
∣∣∣∣
∣∣∣∣
α + a 0
β b
∣∣∣∣
)
=
4(β2a2 − b2a2 + α2b2) < 0.
Geometrically, this inequality means that x0 lies inside the ellipse. If we
introduce the function
F (X1, X2) =
(X1 − α)2
a2
+
(X2 − β)2
b2
− 1
on the plane of the ellipse, then F = 0 for the points of this ellipse and F < 0 for
the point x0 which has the coordinates X1 = 0,X2 = 0. Hence
α2
a2
+
β2
b2
− 1 < 0.
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 141
Yu.A. Aminov and Ia. Nasiedkina
From Eq. (11), we obtain the elliptic equation for U = (r, n0),
U11Ω11 + 2U12Ω12 + U22Ω22 = 0.
Subsequently, from the uniqueness theorem for elliptic differential equations
(see [2, p. 334], [12, p. 109]) there follows Theorem 8.
By using another way of proving Theorem 8 proposed by A.A. Borisenko, an
(n − 1)-dimensional sphere Sn−1 with the center in E4 containing the domain
D is considered. This is a generalization of the method first suggested by A.V.
Pogorelov.
Introduce the Cartesian coordinates in En y1, . . . , yn such that the
axes y1, . . . , y4 lie in E4, and y5, . . . , yn are orthogonal to E4. Consider the
family of ellipsoids, obtained from Sn−1 by being compressed along the axes
y5, . . . , yn to E4. If the domain D does not lie in E4, then at some moment of
compression one ellipsoid touches D at some inner point x. The vectors of normal
curvature at this point for every tangent vector are directed inside the ellipsoid.
Consequently, the point x lies outside the ellipse of normal curvature. It means
that x is of hyperbolic type which contradicts the theorem conditions.
5. Examples of Surfaces in E5 with the Plane of Normal
Curvature Ellipse Passing through a Point of a Surface
We show the way of constructing the surfaces in E5 with non-degenerate
ellipse of normal curvature whose plane passes through the point x. The surfaces
are constructed with a sufficiently large arbitrariness.
The following theorem shows that the boundary conditions imposed on the
previous theorems are essential.
Theorem 9. Let Γ ⊂ E5 be a curve of the regularity class C5 with the curva-
tures ki 6= 0, i = 1, . . . , 4. Then through Γ it is possible to draw a surface of the
regularity class C2 whose ellipse of normal curvature is non-degenerate and the
plane passes through the point x of this surface.
P r o o f. If k4 6= 0, then neither the curve Γ nor the surface containing Γ lies
in E4. The plane of the ellipse of normal curvature of every ruled surface in E5
passes through the point x. Moreover, every ruled surface with non-degenerate
ellipse of normal curvature is of parabolic type. Our construction provides non-
degeneracy of this ellipse.
If the vector position of the curve Γ is ρ(s), where s is the arc length, then in
E5 we take the vector position of the ruled surface
r(s, t) = ρ(s) + tξ3(s).
Here ξi are the vectors of natural basis of Γ.
142 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
Calculate the first and second fundamental forms for this surface. We have
rs = ξ1 + t(−k2ξ2 + ξ4k3),
rt = ξ3.
From here it is seen that g11 = 1 + t2(k2
2 + k2
3), g12 = 0, g22 = 1.
Further,
rss = ξ1tk1k2 + ξ2(k1 − tk′2) + ξ3(−tk2
2 − tk2
3) + ξ4tk
′
3 + ξ5k3k4t,
rst = −ξ2k2 + ξ4k3,
rtt = 0.
Write the normals to the surface
n1 = λ[
−k2ξ2 + k3ξ4
k2
2 + k2
3
− tξ1], λ =
√
k2
2 + k2
3
1 + t2(k2
2 + k2
3)
,
n2 =
k3ξ2 + k2ξ4√
k2
3 + k2
2
,
n3 = ξ5.
Calculate the coefficients of the second quadratic forms of the surface
L1
11 = (n1, rss) = λ(−t2k1k2 − k1k2 − tk′2k2 − tk3k
′
3
k2
3 + k2
2
),
L1
12 = λ,
Lα
22 = 0, α = 1, 2, 3,
L2
11 =
(k1 − k′2t)k3 + k2k
′
3t√
k2
3 + k2
2
,
L2
12 = 0, L3
11 = k4k3t, L3
12 = 0.
Check whether the normal curvature ellipse at the points of the curve Γ is
non-degenerate.
The coordinates of the ellipse are given by equation (1). On the surface F 2,
consider the first fundamental form dl2. At t = 0, we have dl2 = (ds)2 + (dt)2.
Then for the ellipse of normal curvature we get
cosϕ =
ds√
(ds)2 + (dt)2
, sinϕ =
dt√
(ds)2 + (dt)2
.
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 143
Yu.A. Aminov and Ia. Nasiedkina
Here the angle ϕ is formed by the direction τ and the coordinate line s. For
the coordinates of indicatrix we can write
Xα(ϕ) = Lα
11cos 2ϕ + 2Lα
12sinϕ cosϕ + Lα
22sin
2ϕ.
After transformation of this expression, we have
Xα(ϕ) =
Lα
11 + Lα
22
2
+
Lα
11 − Lα
22
2
cos 2ϕ + Lα
12sin 2ϕ.
Recall that Lα
22 = 0. Let us introduce the vectors
M =
L1
11
L2
11
L3
11
, N =
L1
12
L2
12
L3
12
.
For the normal curvature ellipse at the points of the curve Γ not to degenerate
into a segment of a straight line, it is necessary and sufficient for the vectors M
and N be non-collinear. Hence, the minor, composed of the components of these
vectors, is not equal to zero
∣∣∣∣
L1
11 L1
12
L2
11 L2
12
∣∣∣∣ =
∣∣∣∣
L1
11 L1
12
L2
11 0
∣∣∣∣ = k1k3 6= 0.
On a continuity, the ellipse of normal curvature will also be non-degenerate
in some neighborhood of the curve Γ.
Theorem 9 is proved.
Give another example of the surface of parabolic type. Suppose that the
metric of surface is the metric of the Lobachevsky plane in the Poincaré interpre-
tation
ds2 =
dξ2 + dη2
η2
.
Suppose also that asymptotic lines are horocycles η = const. For this metrics
we have Γ1
11 = 0, Γ2
11 = 1
η . Then Eq. (5) has the form
rη = ηrξξ.
If replacing t = η2
2 , ξ = x, then this equation can be written in a classical
form of the classical heat conduction equation
rxx = rt. (12)
Thus, the classical object, namely the Lobachevsky plane, leads to the classical
heat conduction equation.
144 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
Let some continuous limited curve in E5 with the vector position ρ = ρ(x),
−∞ < x < +∞ be given. Applying the Poisson formula (see [6, p. 225], or [7,
p. 481]), we can define the surface F 2 ⊂ E5
r(x, t) =
1
2
√
π
+∞∫
−∞
1√
t
e−
(x−ξ)2
4t ρ(ξ)dξ,
where r(x, 0) = ρ(x).
Thus, we can state that except the ruled surfaces there are also other surfaces
of parabolic type whose vector positions satisfy heat equation (12). Therefore,
Lα
11 = 0. Hence, a curve t = const is an asymptotic line on the surface. It means
that the surface is of parabolic type.
6. About the Surfaces in E5 in the Explicit Form
In this section, we consider the surface in E5 given in the explicit form. The
plane of the ellipse of normal curvature for the point x is to pass through this
point. Let e1, . . . , e5 be the fixed basis in E5 with the Cartesian coordinates
x1, x2, u, v, w.
Then the surface F 2 ⊂ E5 is given as follow:
u = u(x1, x2),
v = v(x1, x2),
w = w(x1, x2).
Write the vector position and its derivatives in the form
r =
x1
x2
u(x1, x2)
v(x1, x2)
w(x1, x2)
, rx1 =
1
0
u1
v1
w1
, rx2 =
0
1
u2
v2
w2
, rxixj =
0
0
uij
vij
wij
.
Write the normals n1, n2, n3 of F 2 in terms of the coordinates
n1 = {ξi}, n2 = {ηi}, n3 = {ζi}, i = 1, . . . , 5.
The system of equations for the normal n1 is the following:
ξα + uαξ3 + vαξ4 + wαξ5 = 0, (13)
where α = 1, 2. The similar systems also exist for n2 and n3.
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 145
Yu.A. Aminov and Ia. Nasiedkina
It is obvious that
L1
ij = ξ3uij + ξ4vij + ξ5wij ,
L2
ij = η3uij + η4vij + η5wij , (14)
L3
ij = ζ3uij + ζ4vij + ζ5wij
are the coefficients of the second fundamental forms.
Lemma 4. If the plane of the ellipse of normal curvature is defined and it
passes through the point x of the surface, then
∆ =
∣∣∣∣∣∣
L1
11 L2
11 L3
11
L1
12 L2
12 L3
12
L1
22 L2
22 L3
22
∣∣∣∣∣∣
= 0.
On contrary, if ∆ = 0, then the plane of this ellipse passes through the point x.
P r o o f. The vector of normal curvature can be rewritten as
kn = (L1
11n1 + L2
11n2 + L3
11n3)
(du1)2
ds2
+ 2(L1
12n1 + L2
12n2 + L3
12n3)
du1du2
ds2
+(L1
22n1 + L2
22n2 + L3
22n3)
(du2)2
ds2
.
The expressions in brackets, i.e., Nkl =
∑
α
Lα
klnα k, l = 1, 2, are vectors. It is
known that the end of the vector kn describes a flat curve, namely, an ellipse. As
the plane of normal curvature ellipse passes through the point x of the surface,
the vectors Nkl are coplanar. Hence we have
∆ =
∣∣∣∣∣∣
L1
11 L2
11 L3
11
L1
12 L2
12 L3
12
L1
22 L2
22 L3
22
∣∣∣∣∣∣
= 0. (15)
On contrary, if ∆ = 0, then three vectors Nkl are linearly dependent. There-
fore, kn for all du1, du2 lies in one plane passing through the point x.
The lemma is proved.
Lemma 5. For a surface in the explicit form, the equation ∆ = 0 gives
∣∣∣∣∣∣
u11 v11 w11
u12 v12 w12
u22 v22 w22
∣∣∣∣∣∣
= 0. (16)
146 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
P r o o f. In the determinant ∆, substitute the expressions for the coefficients
of the second quadratic forms (14) to get
∆ =
∣∣∣∣∣∣
ξ3u11 + ξ4v11 + ξ5w11 η3u11 + η4v11 + η5w11 ζ3u11 + ζ4v11 + ζ5w11
ξ3u12 + ξ4v12 + ξ5w12 η3u12 + η4v12 + η5w12 ζ3u12 + ζ4v12 + ζ5w12
ξ3u22 + ξ4v22 + ξ5w22 η3u22 + η4v22 + η5w22 ζ3u22 + ζ4v22 + ζ5w22
∣∣∣∣∣∣
= 0.
This determinant can be written in the form of the product of two determinants
∣∣∣∣∣∣
u11 v11 w11
u12 v12 w12
u22 v22 w22
∣∣∣∣∣∣
∣∣∣∣∣∣
ξ3 η3 ζ3
ξ4 η4 ζ4
ξ5 η5 ζ5
∣∣∣∣∣∣
= 0.
The second determinant can not be equal to zero. If the determinant
∣∣∣∣∣∣
ξ3 η3 ζ3
ξ4 η4 ζ4
ξ5 η5 ζ5
∣∣∣∣∣∣
is equal to zero, then from Eqs. (13) it follows that the normals n1, n2, n3 are
linearly dependent. Therefore, Eq. (16) is proved.
Equations (15) and (16) allow to construct a number of simple examples of the
surfaces in E5, where the plane of the ellipse of normal curvature passes through
the corresponding point of the surface.
Let the surface be of the form
r =
x1
x2
u
v
w
=
x1
x2
u(x1, x2)
v = 1
2(c1x
2
1 + c2x1x2 + c3x
2
2)
w = 1
2(d1x
2
1 + d2x1x2 + d3x
2
2)
.
We find the derivatives
rx1x1 =
0
0
u11
c1
d1
, rx2x2 =
0
0
u22
c3
d3
.
Construct two classes of surfaces. For the relations d3 = −d1, c3 = −c1 and
u11 + u22=0, we get the Laplace equation
rx1x1 + rx2x2 = 0. (17)
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 147
Yu.A. Aminov and Ia. Nasiedkina
At d3 = d1, c3 = c1, u11 − u22 = 0, we have the wave equation
rx1x1 − rx2x2 = 0. (18)
Write the Gauss expansions
rx1x1 = Γi
11ri + Lα
11nα,
rx2x2 = Γi
22ri + Lα
22nα.
From the Gauss equations, the linear independence of the normals nα, and
the Laplace equation (17), we get the conditions on the coefficients of the second
fundamental forms
Lα
11 = −Lα
22,
and from the wave equation (18), we obtain the relations
Lα
11 = Lα
22, α = 1, 2, 3.
From the last two equations and (15) it follows that for both classes of surfaces,
the plane of the ellipse of normal curvature passes through a point of the surface.
References
[1] Yu.A. Aminov, Geometry of Submanifolds. Naukova dumka, Kiev, 2002.
[2] R. Curant, Partial Differential Equations. Mir, Moscow, 1964.
[3] B.L. Rozhdestvensky and N.N. Yanenko, Systems of the Quasilinear Equations and
their Applications to Gas Dynamics. Nauka, Moscow, 1968.
[4] E.M. Landis, Some Questions about Qualitative Theory of Elliptic and Parabolic
Equations. — Russ. Math. Surv. 14:1 (1959), 21–85.
[5] W. Blaschke, Differential Geometry. M–L., ONTI, 1935.
[6] A.N. Tikhonov and A.A. Samarsky, Equations of Mathematical Physics. Nauka,
Moscow, 1972.
[7] S.G. Mikhlin, Course of Mathematical Physics. Nauka, Moscow, 1968.
[8] A. Fridman, The Partial Defferential Equations of Parabolic Type. Mir, Moscow,
1968.
[9] A. Tychonoff, Theoremes d’unicite pour l’equation de la chaleur. — Mat. Sb. 42
(1935), No. 2, 199–216.
[10] I.G. Petrovsky, Lectures on the Theory of Ordinary Differential Equations. Publ.
house of the Moscow university, 1984.
148 Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2
Conditions on a Surface F 2 ⊂ En to lie in E4
[11] I.G. Petrovsky, Lectures on Partial Defferential Equations. Nauka, Moscow, 1961.
[12] Yu.V. Egorov and M.A. Shubin, Linear Partial Differential Equations. Foundations
of the Classical Theory. — Itogi Nauki i Tekhniki. Ser. Sovrem. Probl. Mat. Fund.
Napr. 30 (1988), 5–255.
[13] P.K. Rashevsky, Riemannian Geometry and Tensor Analysis. Nauka, Moscow, 1967.
Journal of Mathematical Physics, Analysis, Geometry, 2013, vol. 9, No. 2 149
|