t-Unique Reductions for Mészáros's Subdivision Algebra

• Опубліковано в: : Symmetry, Integrability and Geometry: Methods and Applications
• Дата: 2018
• Автор: Grinberg, D.
• Формат: Стаття
• Мова: Англійська
• Опубліковано: Інститут математики НАН України 2018
• Онлайн доступ: https://nasplib.isofts.kiev.ua/handle/123456789/209772
• Назва журналу: Digital Library of Periodicals of National Academy of Sciences of Ukraine
• Цитувати: t-Unique Reductions for Mészáros's Subdivision Algebra / D. Grinberg // Symmetry, Integrability and Geometry: Methods and Applications. — 2018. — Т. 14. — Бібліогр.: 30 назв. — англ.

Fix a commutative ring k, two elements β ∈ k and α ∈ k, and a positive integer n. Let X be the polynomial ring over k in the n(n−1)/2 indeterminates xᵢ,ⱼ for all 1 ≤ i < j ≤ n. Consider the ideal J of X generated by all polynomials of the form xᵢ,ⱼxⱼ,ₖ−xᵢ,ₖ(xᵢ,ⱼ+xⱼ,ₖ+β)−α for 1 ≤ i< j < k ≤ n. The quotient algebra X/J (at least for a certain choice of k, β, and α) has been introduced by Karola Mészáros in [Trans. Amer. Math. Soc. 363 (2011), 4359-4382] as a commutative analogue of Anatol Kirillov's quasi-classical Yang-Baxter algebra. A monomial in X is said to be pathless if it has no divisors of the form xᵢ,ⱼxⱼ,ₖ with 1 ≤ i < j < k ≤n. The residue classes of these pathless monomials span the k-module X/J, but (in general) are k-linearly dependent. More combinatorially: reducing a given p∈X modulo the ideal J by applying replacements of the form xᵢ,ⱼxⱼ,ₖ↦xᵢ,ₖ(xᵢ,ⱼ+xⱼ,ₖ+β)+α always eventually leads to a k-linear combination of pathless monomials, but the result may depend on the choices made in the process. More recently, the study of Grothendieck polynomials has led Laura Escobar and Karola Mészáros [Algebraic Combin. 1 (2018), 395-414] to defining a k-algebra homomorphism D from X into the polynomial ring k[t₁,t₂,…,tₙ₋₁] that sends each xᵢ,ⱼ to tᵢ. We show the following fact (generalizing a conjecture of Mészáros): If p ∈ X, and if q ∈ X is a k-linear combination of pathless monomials satisfying p ≡ q mod J, then D(q) does not depend on q (as long as β, α, and p are fixed). Thus, the above way of reducing a p ∈ X modulo J may lead to different results, but all of them become identical once D is applied. We also find an actual basis of the k-module X/J, using what we call forkless monomials.