New Combinatorial Formulae for Nested Bethe Vectors

We give new combinatorial formulae for vector-valued weight functions (off-shell nested Bethe vectors) for the evaluation modules over the Yangian Y(₄). The case of Y(ₙ) for an arbitrary n is considered in [Lett. Math. Phys. 115 (2025), 12, 20 pages, arXiv:2402.15717].

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Опубліковано в: :Symmetry, Integrability and Geometry: Methods and Applications
Дата:2025
Автори: Kosmakov, Maksim, Tarasov, Vitaly
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Мова:Англійська
Опубліковано: Інститут математики НАН України 2025
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Цитувати:New Combinatorial Formulae for Nested Bethe Vectors. Maksim Kosmakov and Vitaly Tarasov. SIGMA 21 (2025), 060, 28 pages

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Digital Library of Periodicals of National Academy of Sciences of Ukraine
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author Kosmakov, Maksim
Tarasov, Vitaly
author_facet Kosmakov, Maksim
Tarasov, Vitaly
citation_txt New Combinatorial Formulae for Nested Bethe Vectors. Maksim Kosmakov and Vitaly Tarasov. SIGMA 21 (2025), 060, 28 pages
collection DSpace DC
container_title Symmetry, Integrability and Geometry: Methods and Applications
description We give new combinatorial formulae for vector-valued weight functions (off-shell nested Bethe vectors) for the evaluation modules over the Yangian Y(₄). The case of Y(ₙ) for an arbitrary n is considered in [Lett. Math. Phys. 115 (2025), 12, 20 pages, arXiv:2402.15717].
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fulltext Symmetry, Integrability and Geometry: Methods and Applications SIGMA 21 (2025), 060, 28 pages New Combinatorial Formulae for Nested Bethe Vectors Maksim KOSMAKOV a and Vitaly TARASOV b a) Department of Mathematical Sciences, University of Cincinnati, P.O. Box 210025, Cincinnati, OH 45221, USA E-mail: kosmakmm@ucmail.uc.edu b) Department of Mathematical Sciences, Indiana University Indianapolis, 402 North Blackford St, Indianapolis, IN 46202-3216, USA E-mail: vtarasov@iu.edu Received January 08, 2025, in final form July 08, 2025; Published online July 22, 2025 https://doi.org/10.3842/SIGMA.2025.060 Abstract. We give new combinatorial formulae for vector-valued weight functions (off- shell nested Bethe vectors) for the evaluation modules over the Yangian Y (gl4). The case of Y (gln) for an arbitrary n is considered in [Lett. Math. Phys. 115 (2025), 12, 20 pages, arXiv:2402.15717]. Key words: Bethe ansatz; Yangian; weight functions 2020 Mathematics Subject Classification: 17B37; 81R50; 82B23 1 Introduction In this paper we will give new combinatorial formulae for vector-valued weight functions for evaluation modules over the Yangian Y (gln). The weight functions, also known as (off-shell) nested Bethe vectors, play an important role in the theory of quantum integrable models and representation theory of Lie algebras and quantum groups. Initially, they appeared in the framework of the nested algebraic Bethe ansatz as a tool to find eigenvectors and eigenvalues of transfer matrices of lattice integrable models associated with higher rank Lie algebras [6, 7], see [21, 22] for a review of the algebraic Bethe ansatz. The results of [6] has been extended to higher transfer matrices in [11]. Furthermore, the vector-valued weight functions were used to construct hypergeometric so- lutions of the quantized (difference) Knizhnik–Zamolodchikov equations [10, 28]. They also showed up in several related problems [3, 12, 24, 26]. In a more recent development, the weight functions were connected to the stable envelopes for particular Nakajima quiver varieties, the cotangent bundles of partial flag varieties [15, 16, 17, 18, 27]. For various applications, it is important to have expressions for vector-valued weight functions for tensor products of evaluation modules over Y (gln). Such expressions can be obtained in two steps. The first step is to consider weight functions for a single evaluation module, and the second step is to combine expressions for individual evaluation modules into an expression for the whole tensor product. In this paper, we will focus on the first step. The second step is fairly standard and is not specifically discussed here. By definition, an evaluation Y (gln)-module is a gln-module equipped with the action of Y (gln) via the evaluation homomorphism Y (gln) → U(gln), see Section 2. The goal is to expand the vector-valued weight function for the evaluation Y (gln)-module in a basis coming from the representation theory of gln and find expressions for the coordinates. For Verma modules mailto:kosmakmm@ucmail.uc.edu mailto:vtarasov@iu.edu https://doi.org/10.3842/SIGMA.2025.060 2 M. Kosmakov and V. Tarasov over gln, such kind of expressions are given in [25]. In this paper, we give a generalization of formulae from [25]. Combinatorial formulae for the vector-valued weight functions associated with the differential Knizhnik–Zamolodchikov equations were developed in [1, 8, 9, 14, 19, 20]. The expressions for weight functions in [25] are based on recursions induced by the standard embeddings of Lie algebras, gl1 ⊕ gln−1 ⊂ gln and gln−1 ⊕ gl1 ⊂ gln. The recursions allow one to write down weight functions for Y (gln) via weight functions for Y (gln−1). This results in formulae for coordinates of weight functions in bases of Verma gln-modules of the form{∏ i>j e mij ij v, mij ∈ Z≥0 } , (1.1) where eij are the standard generators of gln, see (2.7), v is the highest weight vector, and some ordering of noncommuting factors is imposed. The ordering is determined by the in-between part of the involved chain of embeddings gl1 ⊕ · · · ⊕ gl1 ⊂ · · · ⊂ gln. For instance, the chain gl1 ⊕ · · · ⊕ gl1 ⊂ · · · ⊂ gln−2 ⊕ gl1 ⊕ gl1 ⊂ gln−1 ⊕ gl1 ⊂ gln yields the ordering e⊛ij is to the left of e⊛kl if i > k or i = k, j > l, (1.2) while the chain gl1 ⊕ · · · ⊕ gl1 ⊂ · · · ⊂ gl1 ⊕ gl1 ⊕ gln−2 ⊂ gl1 ⊕ gln−1 ⊂ gln yields the ordering e⊛ij is to the left of e⊛kl if j < l or j = l, i < k. (1.3) For example for n = 4, the product e43e42e41e32e31e21 obeys ordering (1.2), while the product e21e31e41e32e42e43 obeys ordering (1.3). However, some natural orderings of noncommuting factors in (1.1) important for applications do not show up in the formulae established in [25], see, for instance, [8]. The first nontrivial example occurs at n = 4 and is given by the basis{ em32 32 em31 31 em42 42 em41 41 em21 21 em43 43 v, mij ∈ Z≥0 } . (1.4) To make the set of covered orderings wider, one can consider recursions based on more general embeddings glm ⊕ gln−m ⊂ gln with 1 < m < n− 1. (1.5) For instance, the embedding gl2 ⊕ gl2 ⊂ gl4 yields example (1.4). In this paper, we will work out example (1.4) in detail with the main result given by Theorem 5.7. We consider the general case in [5]. We would like to present the gl4 case separately in order to explain calculations more clearly without introducing too cumbersome notation and to make the exposition paper more accessible. For the same purpose, we show explicitly intermediate steps in the proofs that commonly might be tacit for the sake of making a paper shorter. In particular, we give in Appendix A a proof of Proposition 5.1. Although this statement has a long history, going back to [4], numerous applications, and is explained in several lecture courses, see [22], its straightforward proof is not easily available in the literature. New Combinatorial Formulae for Nested Bethe Vectors 3 At the same time we point out that the proof of Theorem 5.7 in this paper extends almost in a straightforward way to the proof of [5, Theorem 5.5] in the general gln case. In particular, the proof of the key Proposition 6.3 in [5] is literally the same as the proof of Proposition 5.6 in this paper. Unlike [25], we will consider only the case of weight functions for Yangian modules (the rational case). It turns out that dealing with weight functions for modules over the quantum loop algebra Uq ( g̃ln ) , the trigonometric case, hits an obstacle of essential noncommutativity of q-analogues of the generators eij , i > j. This obstacle does not show up for the embeddings gl1 ⊕ gln−1 ⊂ gln and gln−1 ⊕ gl1 ⊂ gln explored in [25], but reveals itself for embeddings (1.5). For instance, the obstacle in example (1.4) comes from the relation e42e31 − e31e42 = ( q − q−1 ) e32e41 that holds in the trigonometric case. There is an alternative approach to get explicit expressions for the vector-valued weight functions in the trigonometric case, see [2, 3, 13], based on considering composed currents and half-currents in the quantum affine algebra and their projections on two Borel subalgebras of different kind. This approach allows one to recover combinatorial expression for vector- valued weight functions in evaluation modules in the trigonometric case obtained in [25]. It is an interesting open question whether the composed currents approach can be helpful to obtain trigonometric analogues of new combinatorial expressions for vector-valued weight functions developed in this paper. 2 Notations We will be using the standard superscript notation for embeddings of tensor factors into tensor products. For a tensor product of vector spaces V1⊗V2⊗· · ·⊗Vk and an operator A ∈ End(Vi), denote A(i) = 1⊗(i−1) ⊗A⊗ 1⊗(k−i) ∈ End(V1 ⊗ V2 ⊗ · · · ⊗ Vk). Also, if B ∈ End(Vj), i ̸= j, denote (A⊗B)(ij) = A(i)B(j), etc. Fix a positive integer n. All over the paper we identify elements of End Cn with n×nmatrices using the standard basis of Cn. That is, for L ∈ EndCn we have L = ( Lab )n a,b=1 , where Lab are the entries of L. Entries of matrices acting in the tensor products (Cn)⊗k are naturally labeled by multiindices. For instance, if M ∈ End(Cn ⊗ Cn), then M = ( Mab cd )n a,b,c,d=1 . The rational R-matrix is R(u) ∈ End(Cn ⊗ Cn), R(u) = 1 + 1 u n∑ a,b=1 Eab ⊗ Eba, (2.1) where Eab ∈ End (Cn) is the matrix with the only nonzero entry equal to 1 at the intersection of the a-th row and b-th column. The entries of R(u) are Rabcd(u) = δacδbd + 1 u δadδbc. The R-matrix satisfies the Yang–Baxter equation R(12)(u− v)R(13)(u)R(23)(v) = R(23)(v)R(13)(u)R(12)(u− v). (2.2) 4 M. Kosmakov and V. Tarasov The Yangian Y (gln) is a unital associative algebra with generators ( T ab ){s} , a, b = 1, . . . , n, and s = 1, 2, . . . . Organize them into generating series T ab (u) = δab + ∞∑ s=1 ( T ab ){s} u−s, a, b = 1, . . . , n. (2.3) The defining relations in Y (gln) are (u− v) [ T ab (u), T c d (v) ] = T ad (u)T c b (v)− T ad (v)T c b (u) (2.4) for all a, b, c, d = 1, . . . , n. Combine series (2.3) into a matrix T (u) = ∑n a,b=1Eab ⊗ T ab (u) with entries in Y (gln). Then relations (2.4) amount to the following equality: R(12)(u− v)T (1)(u)T (2)(v) = T (2)(v)T (1)(u)R(12)(u− v), where T (1)(u) = ∑n a,b=1Eab ⊗ 1⊗ T ab (u) and T (2)(v) = ∑n a,b=1 1⊗ Eab ⊗ T ab (v). The Yangian Y (gln) is a Hopf algebra. In terms of generating series (2.3), the coproduct ∆: Y (gln) → Y (gln)⊗ Y (gln) reads as follows: ∆ ( T ab (u) ) = n∑ c=1 T cb (u)⊗ T ac (u), a, b = 1, . . . , n. (2.5) Denote by ∆̃: Y (gln) → Y (gln)⊗ Y (gln) the opposite coproduct ∆̃ ( T ab (u) ) = n∑ c=1 T ac (u)⊗ T cb (u), a, b = 1, . . . , n. (2.6) There is a one-parameter family of automorphisms ρx : Y (gln) → Y (gln) defined in terms of the series T (u) by the rule ρxT (u) = T (u − x), where in the right-hand side, each expression (u− x)−s has to be expanded as a power series in u−1. Denote by eab, a, b = 1, . . . , n, the standard generators of the Lie algebra gln, [eab, ecd] = eadδbc − ecbδad. (2.7) A vector v in a gln-module is called singular of weight ( Λ1, . . . ,Λn ) if eabv = 0 for all a < b and eaav = Λav for all a = 1, . . . , n. The Yangian Y (gln) contains the universal enveloping algebra U(gln) as a Hopf subalgebra. The embedding is given by the rule eab 7→ ( T ba ){1} for all a, b = 1, . . . , n. We identify U(gln) with its image in Y (gln) under this embedding. The evaluation homomorphism ϵ : Y (gln) → U(gln) is given by the rule ϵ : (T ab )(u) 7→ δab + ebau −1 for all a, b = 1, . . . , n. Both the automorphisms ρx and the homomorphism ϵ restricted to the subalgebra U(gln) are the identity maps. For a gln-module V , denote by V (x) the Y (gln)-module induced from V by the homomor- phism ϵ ◦ ρx. The module V (x) is called an evaluation module over Y (gln). A vector v in a Y (gln)-module is called singular with respect to the action of Y (gln) if T ab (u)v = 0 for all 1 ≤ b < a ≤ n. A singular vector v that is an eigenvector for the action of T 1 1 (u), . . . , T n n (u) is called a weight singular vector, and the respective eigenvalues are denoted by 〈 T 1 1 (u)v 〉 , . . . , ⟨Tnn (u)v⟩. Example. Let V be a gln-module and v ∈ V be a gln-singular vector of weight ( Λ1, . . . ,Λn ) . Then v is a weight singular vector with respect to the action of Y (gln) in the evaluation mod- ule V (x) and ⟨T aa (u)v⟩ = 1 + Λa(u− x)−1, a = 1, . . . , n. New Combinatorial Formulae for Nested Bethe Vectors 5 For k < n, we consider two embeddings of the algebra Y (glk) into Y (gln), called ϕk and ψk: ϕk ( T ⟨k⟩(u) )a b = ( T ⟨n⟩(u) )a b , ψk ( T ⟨k⟩(u) )a b = ( T ⟨n⟩(u) )a+n−k b+n−k (u), (2.8) with a, b = 1, . . . , k. Here ( T ⟨k⟩(u) )a b and ( T ⟨n⟩(u) )a b are series T ab (u) for the algebras Y (glk) and Y (gln), respectively. 3 Combinatorial formulae for rational weight functions Fix a collection of nonnegative integers ξ1, ξ2, . . . , ξn−1. Set ξ = (ξ1, ξ2, . . . , ξn−1) and ξa = ξ1 + · · ·+ ξa, a = 1, . . . , n− 1. Consider the variables tai , a = 1, . . . , n− 1, i = 1, . . . , ξa. We will also write ta = ( ta1, . . . , t a ξa ) , t = ( t1, . . . , tn−1 ) . We will use the ordered product notation for any noncommuting factors X1, . . . , Xk, →∏ 1≤i≤k Xi = X1X2 · · ·Xk, ←∏ 1≤i≤k Xi = XkXk−1 · · ·X1. Consider the vector space (Cn)⊗ξn−1 and define [j] T ( tj ) = →∏ 1≤k≤ξj T (ξj−1+k) ( tjk ) , [k,j] R ( tk, tj ) = →∏ 1≤i≤ξk ( ←∏ 1≤l≤ξj R(ξk−1+i,ξj−1+l) ( tki − tjl )) , where we consider T (ξj−1+k) ( tjk ) as a matrix with noncommuting entries belonging to Y (gln). For the expression T̂ξ(t) = [1] T ( t1 ) · · · [n−1] T ( tn−1 ) ←∏ 1≤i≤n−1 ( ←∏ 1≤j<i [i,j] R ( ti, tj )) , (3.1) denote by Bξ(t) the following entry Bξ(t) = ( T̂ξ(t) )1ξ1 ,2ξ2 ,...,n−1ξn−1 2ξ1 ,3ξ2 ,...,nξn−1 , where 1ξ1 ,2ξ2 , . . . , (n − 1)ξn−1 = 1, 1, . . . , 1︸ ︷︷ ︸ ξ1 , 2, 2, . . . , 2︸ ︷︷ ︸ ξ2 , . . . , n− 1, n− 1, . . . , n− 1︸ ︷︷ ︸ ξn−1 , 2ξ1 ,3ξ2 , . . . ,nξn−1 = 2, 2, . . . , 2︸ ︷︷ ︸ ξ1 , 3, 3, . . . , 3︸ ︷︷ ︸ ξ2 , . . . , n, n, . . . , n︸ ︷︷ ︸ ξn−1 . To indicate the dependence on n, if necessary, we will write B⟨n⟩ξ (t). Example. Let n = 2 and ξ = (ξ1). Then B⟨2⟩ξ (t) = T 1 2 ( t11 ) . . . T 1 2 ( t1ξ1 ) . Abusing notation, we will farther write B⟨2⟩ξ1 (t) instead of B⟨2⟩ξ (t). 6 M. Kosmakov and V. Tarasov Example. Let n = 4 and ξ = (1, 1, 1). Then B⟨4⟩ξ (t) = T 1 2 ( t11 ) T 2 3 ( t21 ) T 3 4 ( t31 ) + 1 t21 − t11 T 1 3 ( t11 ) T 2 2 ( t21 ) T 3 4 ( t31 ) + 1 t31 − t21 T 1 2 ( t11 ) T 2 4 ( t21 ) T 3 3 ( t31 ) + 1( t21 − t11 )( t31 − t21 )(T 1 4 ( t11 ) T 2 2 ( t21 ) T 3 3 ( t31 ) + T 1 3 ( t11 ) T 2 4 ( t21 ) T 3 2 ( t31 )) + ( t21 − t11 )( t31 − t21 ) + 1( t21 − t11 )( t31 − t11 )( t31 − t21 )T 1 4 ( t11 ) T 2 3 ( t21 ) T 3 2 ( t31 ) . For a weight singular vector v with respect to the action of Y (gln), we call the expression Bξ(t)v the (rational) vector-valued weight function of weight (ξ1, ξ2−ξ1, . . . , ξn−1−ξn−2,−ξn−1) associated with v. From now on, we will consider only the case n = 4. We are interested in writing down the following expansion for a weight function in a evaluation module over the Y (gl4): Bξ(t)v = ∑ m⃗∈Z6 ≥0 Fm⃗(t) · em32 32 em31 31 em42 42 em41 41 em21 21 em43 43 v (3.2) with the functions Fm⃗(t) given by explicit formulae. Various similar expansions for Bξ(t)v were obtained in [25], however, expansion (3.2) is not covered there. 4 Splitting property of the weight functions Let T ⟨2⟩ ab (u) be series (2.3) for the algebra Y (gl2), and R⟨2⟩(u) be the corresponding rational R-matrix, see (2.1). Consider two Y (gl2)-module structures on the vector space C2. The first one, called L(x), is given by the rule π(x) : T ⟨2⟩(u) 7→ R⟨2⟩(u− x), and the second one, called L̄(x), is given by the rule ϖ(x) : T ⟨2⟩(u) 7→ (( R⟨2⟩(x− u) )(21))t2 , where the superscript t2 stands for the matrix transposition in the second tensor factor. Let w1, w2 be the standard basis of the space C2. The module L(x) is a highest weight eval- uation module with gl2 highest weight (1, 0) and highest weight vector w1. The module L̄(x) is a highest weight evaluation module with gl2 highest weight (0,−1) and highest weight vector w2. For any X ∈ End ( C2 ) , set ν(X) = Xw1 and ν̄(X) = Xw2. Recall the coproducts ∆ and ∆̃, see (2.5) and (2.6), and the embeddings ψ2 : Y (gl2) → Y (gl4) and ϕ2 : Y (gl2) → Y (gl4) given by (2.8). For any k, denote by ∆(k) : Y (gl2) → (Y (gl2)) ⊗(k+1) and ∆̃(k) : Y (gl2) → (Y (gl2)) ⊗(k+1) the iterated coproduct and opposite coproduct. Consider the maps ψ2(x1, . . . , xk) : Y (gl2) → ( C2 )⊗k ⊗ Y (gl4), ψ2(x1, . . . , xk) = ( ν⊗k ⊗ id ) ◦ (π(x1)⊗ · · · ⊗ π(xk)⊗ ψ2) ◦∆(k), and ϕ2(x1, . . . , xk) : Y (gl2) → ( C2 )⊗k ⊗ Y (gl4), ϕ2(x1, . . . , xk) = ( ν̄⊗k ⊗ id ) ◦ (ϖ(x1)⊗ · · · ⊗ϖ2(xk)⊗ ϕ2) ◦ ∆̃(k). New Combinatorial Formulae for Nested Bethe Vectors 7 For any element g ∈ ( C2 )⊗k ⊗ Y (gl4), we define its components ga, a = (a1, . . . , ak), by the rule g = 2∑ a1,...,ak=1 wa1 ⊗ · · · ⊗wak ⊗ ga. In the gl4 case, we have ξ = (ξ1, ξ2, ξ3), and formula (3.1) takes the form Bξ(t) = ([1] T ( t1 )[2] T ( t2 )[3] T ( t3 )[32] R ( t3, t2 )[31] R ( t3, t1 )[21] R ( t2, t1 ))1ξ1 ,2ξ2 ,3ξ3 2ξ1 ,3ξ2 ,4ξ3 . Proposition 4.1. Let v be a Y (gl4)-singular vector, ξ1, ξ2, ξ3 be nonnegative integers, and t = ( t11, . . . , t 1 ξ1 ; t21, . . . , t 2 ξ2 ; t31, . . . , t 3 ξ3 ) . Then Bξ(t)v = ∑ a,b ( T ( t2 ))a b ( ϕ2 ( t2 )( B⟨2⟩ξ1 ( t1 )))a( ψ2 ( t2 )( B⟨2⟩ξ3 ( t3 )))b−2 v, (4.1) where the sum is taken over all sequences a = (a1, a2, . . . , aξ2), b = (b1, b2, . . . , bξ2), such that ai ∈ {1, 2}, bi ∈ {3, 4} for all i = 1, . . . , ξ2, b − 2 = (b1 − 2, b2 − 2, . . . , bξ2 − 2), and( T ( t2 ))a b = T ( t21 )a1 b1 T ( t22 )a2 b2 · · ·T ( t2ξ2 )aξ2 bξ2 . Proof. Formula (4.1) follows from the definition of the maps ψ2 ( t2 ) and ϕ2 ( t2 ) and Lemma 4.2 below. ■ Lemma 4.2. One has Bξ(t)v = ∑ a,b ( T ( t2 ))a b ([21] R ( t2, t1 )[1] T ( t1 ))1ξ1 ,2ξ2 ,3ξ3 2ξ1 ,a,3ξ3 ([3] T ( t3 )[32] R ( t3, t2 ))1ξ1 ,b,3ξ3 1ξ1 ,3ξ2 ,4ξ3 v, where the sum over a, b is the same as in formula (4.1). Proof. Using Yang–Baxter equation (2.2), we can write B(t) in the following form: Bξ(t)v = ([21] R ( t2, t1 )[2] T ( t2 )[1] T ( t1 )[3] T ( t3 )[31] R ( t3, t1 )[32] R ( t3, t2 ))1ξ1 ,2ξ2 ,3ξ3 2ξ1 ,3ξ2 ,4ξ3 v. Therefore, Bξ(t)v = ∑ p,q,r,s ([21] R [2] T [1] T )1ξ1 ,2ξ2 ,3ξ3 p,q,3ξ3 ([3] T )p,q,3ξ3 p,q,r ([31] R )p,q,r 2ξ1 ,q,s ([32] R )2ξ1 ,q,s 2ξ1 ,3ξ2 ,4ξ3 v, (4.2) where p = (p1, . . . , pξ1), q = (q1, . . . , qξ2), r = (r1, . . . , rξ3), s = (s1, . . . , sξ3). In (4.2), we omit- ted the arguments t1, t2, t3 since they can be restored from the context. We say that r ≥ 3ξ3 if ri ≥ 3 for all i = 1, . . . , ξ3. Observe that by the definition of a singular vector and the commutation relations T 3 b (w)T 3 d (u) = w − u− 1 w − u T 3 d (u)T 3 b (w) + 1 w − u T 3 d (w)T 3 b (u), we have [3] T ( t3 )3ξ3 r v = 0 unless r ≥ 3ξ3 . Furthermore, for r ≥ 3ξ3 , we have by induction on ξ3 that([31] R )p,q,r 2ξ1 ,q,s = δp,2ξ1 δr,s. 8 M. Kosmakov and V. Tarasov Indeed, for ξ3 = 0, the statement is true. Assume that([31] R )p,q,r 2ξ1 ,q,s = δp,2ξ1 δr,s for r ≥ 3ξ3 if ξ3 = n − 1, and consider the case ξ3 = n. Let r = (r1, . . . , rn), s = (s1, . . . , sn), r̃ = (r1, . . . , rn−1), s̃ = (s1, . . . , sn−1), then we have ([31] R )p,q,r 2ξ1 ,q,s = ∑ x ( →∏ 1≤i≤n−1 ( ←∏ 1≤j≤ξ1 R(ξ2+i,j) ))p,q,r̃,rn x,q,s̃,rn ( ←∏ 1≤k≤ξ1 R(ξ3,k) )x,q,s̃,rn 2ξ1 ,q,s̃,sn . (4.3) Observe that the R-matrix entry Rjlik with i ̸= l is not zero if and only if i = j and k = l, and Rikik = 1. Because of that and since rn ≥ 3, the last factor (∏ R(ξ3,k) )x,q,s̃,rn 2ξ1 ,q,s̃,sn in (4.3) equals δx,2ξ1 δrn,sn , and we get ([31] R )p,q,r 2ξ1 ,q,s = ( →∏ 1≤i≤n−1 ( ←∏ 1≤j≤ξ1 R(ξ2+i,j) ))p,q,r̃,rn 2ξ1 ,q,s̃,rn δrn,sn = δp,2ξ1 δr̃,s̃δrn,sn = δp,2ξ1 δr,s, by the induction assumption. Since([3] T )p,q,3ξ3 p,q,r v = 0 unless r ≥ 3ξ3 and([31] R )p,q,r 2ξ1 ,q,s = δp,2ξ1 δr,s for r ≥ 3, formula (4.2) becomes Bξ(t)v = ∑ p,q,r ([21] R [2] T [1] T )1ξ1 ,2ξ2 ,3ξ3 2ξ1 ,q,3ξ3 ([3] T )2ξ1 ,q,3ξ3 2ξ1 ,q,r ([32] R )2ξ1 ,q,r 2ξ1 ,3ξ2 ,4ξ3 v, and can be further transformed as Bξ(t)v = ∑ a,b,c,r ([2] T )c,a,3ξ3 c,b,3ξ3 ([21] R )1ξ1 ,2ξ2 ,3ξ3 c,a,3ξ3 ([1] T )c,b,3ξ3 2ξ1 ,b,3ξ1 ([3] T )2ξ1 ,b,3ξ3 2ξ1 ,b,r ([32] R )2ξ1 ,b,r 2ξ1 ,3ξ2 ,4ξ3 v, (4.4) where the sum is over all sequences a = (a1. . . . , aξ2), b = (b1. . . . , bξ2), c = (c1, . . . , cξ1), r = (r1, . . . , rξ3) such that ai, bi, ci, ri ∈ {1, 2, 3, 4}. Since ([21] R )1ξ1 ,2ξ2 ,3ξ3 c,a,3ξ3 = 0 if ai ≥ 3 for some i, and([32] R )2ξ1 ,b,r 2ξ1 ,3ξ2 ,4ξ3 = 0 if bi ≤ 2 for some i, terms in the sum in the right-hand side of (4.4) equal zero unless ai ∈ {1, 2} and bi ∈ {3, 4} for all i. Taking the sum over c and r in formula (4.4), we get the statement of Lemma 4.2. ■ New Combinatorial Formulae for Nested Bethe Vectors 9 Example. Here we illustrate the proof of the relation([31] R )p,q,r 2ξ1 ,q,s = δp,2ξ1 δr,s if r ≥ 3ξ3 for ξ1 = ξ3 = 2. In this case, p = (p1, p2), r = (r1, r2), s = (s1, s2), and([31] R )p,q,r 2ξ1 ,q,s = ∑ a,b,c,d Rp2r1ab ( t31 − t12 ) Rp1bcs1 ( t31 − t11 ) Rar22d ( t32 − t12 ) Rcd2s2 ( t32 − t11 ) . For r1 ≥ 3, r2 ≥ 3, we have Rar22d ( t32 − t12 ) = δa,2δr2,d, thus([31] R )p,q,r 2ξ1 ,q,s = ∑ b,c Rp2r12b ( t31 − t12 ) Rp1bcs1 ( t31 − t11 ) Rcr22s2 ( t32 − t11 ) . Then Rcr22s2 ( t32 − t11 ) = δc,2δr2,s2 and Rp2r12b ( t31 − t12 ) = δp2,2δr1,b, so that([31] R )p,q,r 2ξ1 ,q,s = Rp1r12s1 ( t31 − t11 ) δp2,2δr2,s2 = δp2,2δp1,2δr1,s1δr2,s2 = δp,2ξ1 δr,s. 5 Main theorem for the gl4 case The main result of this paper is Theorem 5.7 formulated at the end of this section. We will approach it in several steps. For a nonnegative integer m, set Qm(t1, . . . , tm) = ∏ 1⩽i<j⩽m ti − tj − 1 ti − tj . (5.1) For an expression f(t1, . . . , tm), define Symt f(t1, . . . , tm) = ∑ σ∈Sm f ( tσ(1), . . . , tσ(m) ) , and Symt f(t1, . . . , tm) = Symt(f(t1, . . . , tm)Qm(t1, . . . , tm)). (5.2) To simplify notation, we will write T ⟨2⟩ ij instead of ( T ⟨2⟩ )i j . Proposition 5.1. Let ξ be a nonnegative integer and t = (t1, . . . , tξ). Then ∆ ( B⟨2⟩ξ (t) ) = ξ∑ η=0 1 (ξ − η)!η! ×Symt (( B⟨2⟩η (t1, . . . , tη)⊗ B⟨2⟩ξ−η(tη+1, . . . , tξ) )( ξ∏ i=η+1 T ⟨2⟩ 22 (ti)⊗ η∏ j=1 T ⟨2⟩ 11 (tj) )) . This proposition goes back to [4, 28]. For convenience, we give its proof in Appendix A. Given a subset I of {1, 2, . . . , k} denote by I∗ the complement of I in {1, 2, . . . , k}. Define a vector wI ∈ ( C2 )⊗k by the rule wI = wa1 ⊗wa2 ⊗ · · · ⊗wak , where ai = 2 if i ∈ I, and ai = 1 if i ̸∈ I. 10 M. Kosmakov and V. Tarasov Fix a Y (gl2)-module V and a weight singular vector v ∈ V with respect to the Y (gl2)-action, T ⟨2⟩ 21 (u)v = 0, T ⟨2⟩ 11 (u)v = 〈 T ⟨2⟩ 11 (u)v 〉 v, T ⟨2⟩ 22 (u)v = 〈 T ⟨2⟩ 22 (u)v 〉 v. Here 〈 T ⟨2⟩ 11 (u)v 〉 and 〈 T ⟨2⟩ 22 (u)v 〉 are the corresponding eigenvalues. Given complex numbers z1, . . . , zk, consider the Y (gl2)-module L(z1)⊗· · ·⊗L(zk)⊗V . Observe that w⊗k1 ⊗ v is a weight singular vector with respect to the action of Y (gl2) in this module. Proposition 5.2. For the Y (gl2)-module L(z1)⊗ · · · ⊗ L(zk)⊗ V , we have B⟨2⟩ξ (t) ( w⊗k1 ⊗ v ) = ∑ I 1 (ξ − |I|)! Symt [ FI(t, z) |I|∏ a=1 〈 T ⟨2⟩ 11 (ta)v 〉( wI ⊗ B⟨2⟩ξ−|I| ( t|I|+1, . . . , tξ ) v )] , (5.3) where the sum is over all subsets I ⊂ {1, . . . , k} such that |I| ≤ ξ, and for a given I = {i1 < i2 < · · · < i|I|}, FI(t, z) = |I|∏ a=1 ( 1 ta − zia k∏ m=ia+1 ta − zm + 1 ta − zm ) . (5.4) Proof. Observe that for each Y (gl2)-module L(zi), i = 1, . . . , k, the corresponding vector w1 ∈ L(zi) is a weight singular vector, T ⟨2⟩ 11 (u)w1 = ( 1 + (u− zi) −1)w1, T ⟨2⟩ 22 (u)w1 = w1, T ⟨2⟩ 21 w1 = 0. Moreover, B⟨2⟩1 (u)w1 = T ⟨2⟩ 12 (u)w1 = (u− zi) −1w2 and B⟨2⟩ζ (u1, . . . , uζ)w1 = 0 for ζ ≥ 2. Then formula (5.3) follows from Proposition 5.1 and identity (A.10) by induction on k. ■ Given complex numbers z1, . . . , zk, consider the Y (gl2)-module V ⊗ L̄(zk) ⊗ · · · ⊗ L̄(z1). Observe that v ⊗w⊗k2 is a weight singular vector with respect to the action of Y (gl2) in this module. Proposition 5.3. For the Y (gl2) module V ⊗ L̄(zk)⊗ · · · ⊗ L̄(z1), we have B⟨2⟩ξ (t) ( v ⊗w⊗k2 ) (5.5) = ∑ I 1 (ξ − |I|)! Symt [ F̃I(t, z) |I|∏ i=1 〈 T ⟨2⟩ 22 ( tξ−|I|+i ) v 〉( B⟨2⟩ξ−|I| ( t1, . . . , tξ−|I| ) v ⊗wI∗ )] , where the sum is over all subsets I ⊂ {1, . . . , k} such that |I| ≤ ξ, and for a given I = {i1 < i2 < · · · < i|I|}, F̃I(t, z) = |I|∏ a=1 ( 1 zia − tξ−a+1 k∏ m=ia+1 zm − tξ−a+1 + 1 zm − tξ−a+1 ) . (5.6) Proof. Observe that for each Y (gl2)-module L̄(zi), i = 1, . . . , k, the corresponding vector w2 ∈ L̄(zi) is a weight singular vector, T ⟨2⟩ 11 (u)w2 = w2, T ⟨2⟩ 22 (u)w2 = ( 1 + (zi − u)−1 ) w2, T ⟨2⟩ 21 (u)w2 = 0. Moreover, B⟨2⟩1 (u)w2 = T ⟨2⟩ 12 (u)w2 = (zi − u)−1w1, and B⟨2⟩ζ (u1, . . . , uζ)w2 = 0 for ζ ≥ 2. Then formula (5.5) follows from Proposition 5.1 and identity (A.10) by induction on k. ■ New Combinatorial Formulae for Nested Bethe Vectors 11 For t = (t1, . . . , tξ), z = (z1, . . . .zk), y ∈ C, and a subset I = {i1 < i2 < · · · < i|I|} ⊂ {1, . . . , k}, define the functions VI(t, z, y) = 1 (ξ − |I|)! Symt ( FI(t, z) |I|∏ a=1 (ta − y) ) (5.7) and ṼI(t, z, y) = 1 (ξ − |I|)! Symt ( F̃I(t, z) |I|∏ a=1 (tξ−a+1 − y) ) . (5.8) Consider the collection Sp,q,r,k of pairs of subsets of {1, . . . , k} with given cardinalities of the subsets and their intersection. Namely, Sp,q,r,k = {(I, J) | I, J ⊂ {1, . . . , k}, |I| = p, |J | = q, |I ∩ J | = r}. For I ⊂ {1, . . . , k}, set Ǐ = {k − i+ 1, i ∈ I}. Theorem 5.4. Let V be a gl4-module and v ∈ V a gl4-singular vector of weight ( Λ1,Λ2,Λ3,Λ4 ) . Let ξ1, ξ2, ξ3 be nonnegative integers, t1 = ( t11, . . . , t 1 ξ1 ) , t2 = ( t21, . . . , t 2 ξ2 ) , t3 = ( t31, . . . , t 3 ξ3 ) , and t = ( t1, t2, t3 ) . For every triple (p, q, r), p = 0, . . . ,min(ξ2, ξ3), q = 0, . . . ,min(ξ2, ξ1), r = max(0, p+ q − ξ2), . . . ,min(p, q), fix a pair (Ip,q,r, Jp,q,r) ∈ Sp,q,r,ξ2. Then, (a) In the evaluation Y (gl4)-module V (x), one has Bξ(t)v = 3∏ a=1 ξa∏ i=1 1 tai − x × min(ξ2,ξ3)∑ p=0 min(ξ2,ξ1)∑ q=0 min(p,q)∑ r=max(0,p+q−ξ2) ( Symt2 ( VǏp,q,r ( t3, t2, x− Λ3 ) ṼJp,q,r ( t1, ť 2 , x− Λ2 )) × eξ2−p−q+r32 eq−r31 ep−r42 er41e ξ1−q 21 eξ3−p43 v (p− r)!(q − r)!r!(ξ2 − p− q − r)! ) , (5.9) where ť 2 = ( t2ξ2 , . . . , t 2 1 ) . (b) The function Symt2 ( VǏp,q,r ( t3, t2, x− Λ3 ) ṼJp,q,r ( t1, ť 2 , x− Λ2 )) in (5.9) does not depend on the choice of the pair (Ip,q,r, Jp,q,r). Proof. Item (a) follows from Propositions 5.5 and 5.6 given below. Item (b) is an immediate corollary of Proposition 5.6. Propositions 5.5 and 5.6 are proved in Sections 6 and 7, respectively. ■ Proposition 5.5. In the notation of Theorem 5.4, we have Bξ(t)v = 3∏ a=1 ξa∏ i=1 1 tai − x × min(ξ2,ξ3)∑ p=0 min(ξ2,ξ1)∑ q=0 min(p,q)∑ r=max(0,p+q−ξ2) ( ∑ (I,J)∈Sp,q,r,ξ2 ṼJ ( t1, t2, x− Λ2 ) VI ( t3, t2, x− Λ3 ) × eξ2−p−q+r32 eq−r31 ep−r42 er41e ξ1−q 21 eξ3−p43 v ) . (5.10) 12 M. Kosmakov and V. Tarasov Proposition 5.6. In the notation of Theorem 5.4, we have∑ (I,J)∈Sp,q,r,ξ2 ṼJ ( t1, t2, x− Λ2 ) VI ( t3, t2, x− Λ3 ) = Symt2 ( VǏ0 ( t3, t2, x− Λ3 ) ṼJ0 ( t1, ť 2 , x− Λ2 )) (p− r)!(q − r)!r!(ξ2 − p− q − r)! , (5.11) where (I0, J0) is any pair from Sp,q,r,ξ2. Below we reformulate Theorem 5.4 in a more closed form. Theorem 5.7. Let V be a gl4-module and v ∈ V a gl4-singular vector of weight ( Λ1,Λ2,Λ3,Λ4 ) . Let ξ1, ξ2, ξ3 be nonnegative integers, t1 = ( t11, . . . , t 1 ξ1 ) , t2 = ( t21, . . . , t 2 ξ2 ) , t3 = ( t31, . . . , t 3 ξ3 ) , and t = ( t1, t2, t3 ) . For every triple (p, q, r), p = 0, . . . ,min(ξ2, ξ3), q = 0, . . . ,min(ξ2, ξ1), r = max(0, p+ q − ξ2), . . . ,min(p, q), fix two sequences i = {i1 < · · · < ip} and j = {j1 < · · · < jq}, such that |{i1, . . . , ip} ∩ {j1, . . . , jq}| = r. Then, (a) In the evaluation Y (gl4)-module V (x), one has Bξ(t)v = 3∏ a=1 ξa∏ i=1 1 tai − x × min(ξ2,ξ3)∑ p=0 min(ξ2,ξ1)∑ q=0 min(p,q)∑ r=max(0,p+q−ξ2) Symt1 Symt2 Symt3 Gi,j(t) × eξ2−p−q+r32 eq−r31 ep−r42 er41e ξ1−q 21 eξ3−p43 v (ξ2 − p− q + r)!(q − r)!(p− r)!r!(ξ1 − q)!(ξ3 − p)! , (5.12) where Gi,j(t) = p∏ a=1 ( t3a − x+ Λ3 t3a − t2ia ξ2∏ m=ia+1 t3a − t2m + 1 t3a − t2m ) × q∏ s=1 ( t1ξ1−q+s − x+ Λ2 t2js − t1ξ1−q+s ξ2−js∏ l=1 t2l − t1ξ1−q+s + 1 t2l − t1ξ1−q+s ) . (5.13) (b) The function Symt1 Symt2 Symt3Gi,j(t) does not depend on the choice of the sequences i, j. Proof. Given the pair (Ip,q,r, Jp,q,r) from the formulation of Theorem 5.4, define the sequences i = {i1 < · · · < ip} and j = {j1 < · · · < jq} by the rule Ip,q,r = {ξ2 − i1 + 1, ξ2 − i2 + 1, . . . , ξ2 − ip + 1}, Jp,q,r = {ξ2 − j1 + 1, ξ2 − j2 + 1, . . . , ξ2 − jq + 1}. Notice that {i1, . . . , ip} = Ǐp,q,r, {j1, . . . , jq} = J̌p,q,r, and |{i1, . . . , ip} ∩ {j1, . . . , jq}| = |Ip,q,r ∩ Jp,q,r| = r. Then combining formulae (5.4) and (5.6)–(5.8), we obtain that VǏp,q,r ( t3, t2, x− Λ3 ) = 1 (ξ3 − p)! Symt3 p∏ a=1 ( t3a − x+ Λ3 t3a − t2ia ξ2∏ m=ia+1 t3a − t2m + 1 t3a − t2m ) (5.14) New Combinatorial Formulae for Nested Bethe Vectors 13 and ṼJp,q,r ( t1, ť 2 , x− Λ2 ) = 1 (ξ1 − q)! Symt1 q∏ b=1 ( t1ξ1−b+1 − x+ Λ2 t2jq−b+1 − t1ξ1−b+1 ξ2−jq−b+1∏ l=1 t2l − t1ξ1−b+1 + 1 t2l − t1ξ1−b+1 ) . After substituting b = q + 1− s, the last formula becomes ṼJp,q,r ( t1, ť 2 , x− Λ2 ) = 1 (ξ1 − q)! Symt1 q∏ s=1 ( t1ξ1−q+s − x+ Λ2 t2js − t1ξ1−q+s ξ2−js∏ l=1 t2l − t1ξ1−q+s + 1 t2l − t1ξ1−q+s ) . (5.15) Plugging (5.14) and (5.15) into formula (5.9), we obtain formulae (5.12) and (5.13). Item (b) of Theorem 5.7 is a reformulation of item (b) of Theorem 5.4. ■ Example. Below we give two examples of natural choices of the sequences i, j in Theorem 5.7 and write down the corresponding expressions for the function Gi,j(t), see formula (5.13). (a) i = i1 = {1 < · · · < p}, j = j1 = {p+ 1− r < · · · < p+ q − r}. Then Gi1,j1(t) = p∏ a=1 ( t3a − Λ3 t3a − t2a ξ2∏ m=a+1 t3a − t2m + 1 t3a − t2m ) × q∏ c=1 ( t1ξ1−q+c − Λ2 t2p−r+c − t1ξ1−q+c ξ2−p+r−c∏ l=1 t2l − t1ξ1−q+c + 1 t2l − t1ξ1−q+c ) . (b) i = i2 = {q + 1− r < · · · < q + p− r}, j = j2 = {1 < · · · < q}. Then Gi2,j2(t) = p∏ a=1 ( t3a − Λ3 t3a − t2q−r+a ξ2∏ m=q−r+a+1 t3a − t2m + 1 t3a − t2m ) × q∏ b=1 ( t1ξ1−b+1 − Λ2 t2b − t1ξ1−b+1 ξ2−b∏ l=1 t2l − t1ξ1−b+1 + 1 t2l − t1ξ1−b+1 ) . Notice that the equality Symt1 Symt2 Symt3 Gi1,j1(t) = Symt1 Symt2 Symt3 Gi2,j2(t), stated in item (b) of Theorem 5.7, is not obvious. 6 Proof of Proposition 5.5 Let V be a gl4-module and v ∈ V a gl4-singular vector of weight ( Λ1,Λ2,Λ3,Λ4 ) . Let ξ1, ξ2, ξ3 be nonnegative integers, t1 = ( t11, . . . , t 1 ξ1 ) , t2 = ( t21, . . . , t 2 ξ2 ) , t3 = ( t31, . . . , t 3 ξ3 ) and t = ( t1, t2, t3 ) . Recall that in the evaluation Y (gl4)-module V (x), we have T ab (u) = δab + eba(u− x)−1, thus T aa (u)v = u− x+ Λa u− x v. By Proposition 4.1, Bξ(t)v = ∑ a,b ([2] T ( t2 ))a b ( ϕ2 ( t2 )( B⟨2⟩ξ1 ( t1 )))a( ψ2 ( t2 )( B⟨2⟩ξ3 ( t3 )))b−2 v, (6.1) 14 M. Kosmakov and V. Tarasov where the sum is taken over all sequences a = (a1, a2, . . . , aξ2), b = (b1, b2, . . . , bξ2), such that ai ∈ {1, 2}, and bi ∈ {3, 4} for all i = 1, . . . , ξ2. Let ψV (x) be the Y (gl2)-module obtained by pulling back the module V (x) through the em- bedding ψ2. To compute ( ψ2 ( t2 )( B⟨2⟩ξ3 ( t3 )))b v, we take the weight function B⟨2⟩ξ3 ( t3 )( w⊗ξ21 ⊗ v ) in the Y (gl2)-module L ( t21 ) ⊗ · · · ⊗ L ( t2ξ2 ) ⊗ ψV (x) and apply Proposition 5.2 for k = ξ2. Then we obtain( ψ2 ( t2 )( B⟨2⟩ξ3 ( t3 )))b−2 v = 1 (ξ3 − |I|)! Symt3 [ FI ( t3, t2 ) |I|∏ m=1 t3m − x+ Λ3 t3m − x ξ3∏ r=|I|+1 1 t3r − x ] e ξ3−|I| 43 v, (6.2) where the subset I ⊂ {1, . . . , ξ2} and the sequence b = (b1, . . . , bξ2) are related as follows: bj = 3 if j /∈ I and bj = 4 if j ∈ I. Therefore, by formula (5.8) we have ( ψ2 ( t2 )( B⟨2⟩ξ3 ( t3 )))b−2 v = ξ3∏ r=1 1 t3r − x VI ( t3, t2, x− Λ3 ) e ξ3−|I| 43 v. The next step is to compute ( ϕ2 ( t2 )( B⟨2⟩ξ1 ( t1 )))a e ξ3−|I| 43 v. Notice that for any nonnegative integer m, we have T 2 1 (u)e m 43v = 0, T 2 2 (u)e m 43v = u− x+ Λ2 u− x em43v, T 1 1 (u)e m 43v = u− x+ Λ1 u− x em43v. Let ϕV (x) the Y (gl2)-module obtained by pulling back V (x) through the embedding ϕ2. To compute the ( ϕ2 ( t2 )( B⟨2⟩ξ1 ( t1 )))a e ξ3−|I| 43 v, we take the weight function B⟨2⟩ξ1 ( t1 )( e ξ3−|I| 43 v ⊗w⊗ξ22 ) in the Y (gl2)-module ϕV (x)⊗ L ( t2ξ2 ) ⊗ · · · ⊗ L ( t21 ) and apply Proposition 5.3 for k = ξ2. Then we obtain( ϕ2 ( t2 )( B⟨2⟩ξ1 ( t1 )))a e ξ3−|I| 43 v = 1 (ξ1 − |J |)! Symt1 [ F̃J ( t1, t2 ) |J |∏ m=1 t1m − x+ Λ2 t1m − x ξ1∏ r=|J |+1 1 t1r − x ] e ξ1−|J | 21 e ξ3−|I| 43 v, (6.3) where the subset J ⊂ {1, . . . , ξ2} and the sequence a = (a1, . . . , aξ2) are related as follows: aj = 1 if j ∈ J and aj = 2 if j /∈ J . Therefore, by formula (5.7) we have ( ϕ2 ( t2 )( B⟨2⟩ξ1 ( t1 )))a e ξ3−|I| 43 v = ξ1∏ r=1 1 t1r − x ṼJ ( t1, t2, x− Λ2 ) e ξ1−|J | 21 e ξ3−|I| 43 v. Finally, for the sequences a, b that are related to the sets I, J as above, we have ([2] T ( t2 ))a b = ξ2∏ r=1 1 t2r − x eξ2−p−q+s32 eq−s31 ep−s42 es41, (6.4) where p = |I|, q = |J |, s = |I ∩ J |. Now formula (5.10) follows from formulae (6.1)–(6.4). 7 Proof of Proposition 5.6 Consider the algebra A generated by two commuting copies of the symmetric group Sk and rational functions of z1, . . . , zk subject to relations (7.1) below. We denote the copies of Sk New Combinatorial Formulae for Nested Bethe Vectors 15 in A by Ṡk and S̈k, and mark elements of Ṡk and S̈k by the corresponding dots, keeping the notation Sk without dots for the abstract symmetric group. Let z = (z1, . . . , zk) and zσ = (zσ(1), . . . , zσ(k)). The additional relations in A are σ̇f(z) = f(zσ)σ̇, τ̈ f(z) = f(z)τ̈ . (7.1) For a = 1, . . . , k − 1, let sa ∈ Sk be the transposition of a and a+ 1. Consider the elements ŝ1, . . . , ŝk of A, ŝa = ( za − za+1 za − za+1 − 1 s̈a − 1 za − za+1 − 1 ) ṡa. (7.2) It is straightforward to check that they satisfy the following relations: ŝaŝa+1ŝa = ŝa+1ŝaŝa+1, ŝ2a = 1. Therefore, the assignment sa 7→ ŝa defines an algebra homomorphism CSk → A. For any σ ∈ Sk, we denote by σ̂ the corresponding element of A. Every element σ̂ can be written in the following form: σ̂ = ∑ τ∈Sk Xσ,τ (z)τ̈ σ̇, (7.3) where Xσ,τ (z) are functions of z1, . . . , zk. Let |σ| denote the length of σ ∈ Sk. Lemma 7.1. The functions Xσ,τ (z) have the following properties: Xσ,τ (z) = 0 if |τ | > |σ|, (7.4) Xσ,τ (z) = δσ,τXσ,σ(z) if |τ | = |σ|, (7.5) Xσ,σ(z) = ∏ a<b,σ−1(a)>σ−1(b) za − zb za − zb − 1 . (7.6) Proof. Formulae (7.4) and (7.5) follow from formula (7.2) by inspection. Formula (7.6) can be shown by induction on |σ|. ■ Denote by σ0 the longest element of Sk, σ0(i) = k − i+ 1, i = 1, . . . , k. Let Φ(z) = ∏ a<b za − zb − 1 za − zb . Notice that Φ(z) = 1 Xσ0,σ0(z) . (7.7) Lemma 7.2. One has∑ λ∈Sk Xλ,ρ(z)Φ ( zλσ0 ) Xσ0λ−1,σ0τ−1 ( zλσ0 ) = δρ,τ . (7.8) Proof. Since σ̂τ = σ̂τ̂ , by formula (7.3) we have Xστ,ρ(z) = ∑ π Xσ,π(z)Xτ,π−1ρ(z σ). (7.9) 16 M. Kosmakov and V. Tarasov Taking here ρ = σ0, and using Lemma 7.1 and formula (7.7), we get∑ π Xσ,π(z)Xτ,π−1σ0(z σ) = δστ,σ0 1 Φ(z) . (7.10) Replacing now z by zσ −1 in formula (7.10) and taking there τ = µ−1σ0, we get∑ π Xσ,π ( zσ −1) Xµ−1σ0,π−1σ0(z) = δσ,µ 1 Φ ( zσ−1 ) . (7.11) Formula (7.11) can be understood as the matrix equality AB = C for k!× k! matrices A, B, C with entries labeled by permutations: Aσ,π = Xσ,π ( zσ −1) , Bπ,µ = Xµ−1σ0,π−1σ0(z), Cσ,µ = δσ,µ 1 Φ ( zσ−1 ) . Therefore, the product BC−1A equals the identity matrix, which can be written as follows:∑ µ Xµ−1σ0,π−1σ0(z)Φ ( zµ −1) Xµ,σ ( zµ −1) = δπ,σ. After the substitution λ = µ−1σ0, ρ = π−1σ0, τ = σ−1σ0, we get formula (7.8). ■ Lemma 7.3. One has Xµ,σ(z sa) = za − za+1 za − za+1 + 1 Xsaµ,saσ(z) + 1 za − za+1 + 1 Xsaµ,σ(z). (7.12) Proof. By formulae (7.2) and (7.3), we have Xsa,sa(z) = za − za+1 za − za+1 − 1 , Xsa,id(z) = −1 za − za+1 − 1 , and Xsa,τ (z) = 0, otherwise. Therefore, by formula (7.9) we obtain Xsaπ,σ(z) = za − za+1 za − za+1 − 1 Xπ,saσ(z sa)− 1 za − za+1 − 1 Xπ,σ(z sa). Replacing here z by zsa and making the substitution π = saµ, we get formula (7.12). ■ Lemma 7.4. One has Xµ,σ ( zsaµ −1) = za − za+1 za − za+1 − 1 Xµsa,σsa ( zsaµ −1)− 1 za − za+1 − 1 Xµsa,σ ( zsaµ −1) . (7.13) Proof. By formula (7.9), we have Xµsa,σ(z) = ∑ π Xµ,π(z)Xsa,π−1σ(z µ). Thus Xµsa,σ(z) = ∑ π Xµ,π(z)Xsa,π−1σ(z µ) = Xµ,σ(z)Xsa,id(z µ) +Xµ,σsa(z)Xsa,sa(z µ). Replacing here z by zµ −1 , we get Xµsa,σ ( zµ −1) = Xµ,σ ( zµ −1) Xsa,id(z) +Xµ,σsa ( zµ −1) Xsa,sa(z). Substituting now µ with µsa, we obtain (7.13). ■ New Combinatorial Formulae for Nested Bethe Vectors 17 For σ ∈ Sn and a subset I = {i1, . . . , im} ⊂ {1, . . . , n}, denote σ(I) = {σ(i1), . . . , σ(im)}. Recall the functions VI(t, z, y), ṼJ(t, z, y), see formulae (5.4), (5.7) and (5.6), (5.8). Lemma 7.5. For each a = 1, . . . , k − 1, we have VI(t, z sa, y) = za+1 − za za+1 − za − 1 Vsa(I)(t, z, y)− 1 za+1 − za − 1 VI(t, z, y), (7.14) ṼI(t, z sa, y) = za − za+1 za − za+1 − 1 Ṽsa(I)(t, z, y)− 1 za − za+1 − 1 ṼI(t, z, y). (7.15) Proof. By the structure of formulae (5.4) and (5.7) for the function VI(t, z, y), it is enough to prove formula (7.14) for k = 2. In this case, the statement follows from the identities 1 = z′ − z z′ − z − 1 − 1 z′ − z − 1 , 1 t− z′ · t− z + 1 t− z = z′ − z z′ − z − 1 · 1 t− z′ − 1 z′ − z − 1 · 1 t− z · t− z′ + 1 t− z′ ,( t′ − z )( t− z′ + 1 )( t− t′ − 1 ) − (t− z) ( t′ − z′ + 1 )( t′ − t− 1 ) = ( t′ − z′ ) (t− z + 1) ( t− t′ − 1 ) − ( t− z′ )( t′ − z + 1 )( t′ − t− 1 ) . The proof of (7.15) is similar by using formulae (5.6) and (5.8) for functions ṼJ(t, z, y). ■ The statement of Proposition 5.6 is given by formula (5.11). It can be written as follows:∑ (I,J)∈Sp,q,r,k VI ( t3, z, x− Λ3 ) ṼJ ( t1, z, x− Λ2 ) = 1 Cp,q,r,k ∑ σ∈Sk Vσ0(I0) ( t3, zσ, x− Λ3 ) ṼJ0 ( t1, zσσ0 , x− Λ2 ) Φ(zσ), (7.16) where Sp,q,r,k in the left-hand side is the set of all pairs of subsets I, J of {1, . . . , k}, such that |I| = p, |J | = q, |I ∩ J | = r, and we use k = ξ2, z = t2. In the right-hand side, Cp,q,r,k = (p− r)!(q − r)!r!(k − p− q − r)! and (I0, J0) is any fixed pair from Sp,q,r,k. We also expanded Symt2 according to formulae (5.1) and (5.2), and observed that Ǐ0 = σ0(I0), ť 2 = zσ0 . In the rest of the proof, we will suppress the arguments t1, t3, x− Λ2, x− Λ3 because they are the same in both sides of formula (7.16) and will never be changed in the reasoning. Notice that every pair (I, J) ∈ Sp,q,r,k can be obtained from an arbitrary fixed pair (I0, J0) ∈ Sp,q,r,k by the action of the symmetric group Sk. Therefore, the left-hand side of the for- mula (7.16) can be written in the following way: ∑ (I,J)∈Sp,q,r,k ṼJ(z)VI(z) = 1 Cp,q,r,k ∑ σ∈Sk Ṽσ(J0)(z)Vσ(I0)(z). (7.17) 18 M. Kosmakov and V. Tarasov Using Lemma 7.2, we get∑ σ∈Sk Ṽσ(J0)(z)Vσ(I0)(z) = ∑ σ,π,τ∈Sk Ṽσ(J0)(z)Xπ,σ(z)Φ(z πσ0)Xσ0π−1,σ0τ−1(zπσ0)Vτ(I0)(z), (7.18) since from formula (7.8)∑ π∈Sk Xπ,σ(z)Φ(z πσ0)Xσ0π−1,σ0τ−1(zπσ0) = δσ,τ . Lemma 7.6. We have∑ σ∈Sk Ṽσ(J0)(z)Xπ,σ(z) = ṼJ0(z π). (7.19) Proof. We will use induction on the length of the permutation π. For π = id, formula (7.19) is clear, and for π = sa with some a = 1, . . . , k − 1, formula (7.19) coincides with formula (7.15). For the induction step, we find a such that |saπ| = |π| − 1, and denote ρ = saπ. Then by the induction assumption∑ σ Ṽσ(J0)(z)Xρ,σ(z) = ṼJ0(z ρ). Replacing here z by zsa , we get∑ σ Ṽσ(J0)(z sa)Xρ,σ(z sa) = ṼJ0(z saρ) = ṼJ0(z π). (7.20) Using formulae (7.12) and (7.15), the left-hand side of (7.20) becomes ∑ σ (za − za+1) 2 (za − za+1)2 − 1 Ṽsaσ(J0)(z)Xsaρ,saσ(z) + ∑ σ za − za+1 (za − za+1)2 − 1 Ṽsaσ(J0)(z)Xsaρ,σ(z) − ∑ σ za − za+1 (za − za+1)2 − 1 Ṽσ(J0)(z)Xsaρ,saσ(z) − ∑ σ 1 (za − za+1)2 − 1 Ṽσ(J0)(z)Xsaρ,σ(z). Changing the summation index in the first and second sums from σ to saσ, we observe that the second and third sums cancel each other, while the first and forth sums combine together and simplify to the expression∑ σ Ṽσ(J0)(z)Xsaρ,σ(z) = ∑ σ Ṽσ(J0)(z)Xπ,σ(z), which appears in the left-hand side of formula (7.19). ■ Lemma 7.7. We have∑ τ Vτ(I0)(z)Xσ0π−1,σ0τ−1(zπσ0) = Vσ0(I0)(z πσ0). (7.21) New Combinatorial Formulae for Nested Bethe Vectors 19 Proof. Recall the notation σ0(I0) = Ǐ0. Transform formula (7.21) by making the substitutions µ = σ0π −1, σ = σ0τ −1,∑ σ Vσ−1(Ǐ0) (z)Xµ,σ ( zµ −1) = VǏ0 ( zµ −1) . (7.22) The rest of the proof is analogous to that of Lemma 7.6. To prove formula (7.22), we will use induction on the length of µ. For µ = id, formula (7.22) is clear, and for µ = sa with some a = 1, . . . , k− 1, formula (7.22) coincides with formula (7.14). For the induction step, we find a such that |µsa| = |µ| − 1, and denote ρ = µsa. Then by the induction assumption,∑ σ Vσ−1(Ǐ0) (z)Xρ,σ ( zρ −1) = VǏ0 ( zρ −1) , and replacing here z by zsa , we get∑ σ Vσ−1(Ǐ0) (zsa)Xρ,σ ( zsaρ −1) = VǏ0 ( zµ −1) = VǏ0 ( zsaρ −1) . (7.23) Using formulae (7.13), (7.14), the left-hand of (7.23) side becomes ∑ σ (za+1 − za) 2 (za+1 − za)2 − 1 Vsaσ−1(Ǐ0) (z)Xρsa,σsa ( zsaρ −1) − ∑ σ za − za+1 (za − za+1)2 − 1 Vsaσ−1(Ǐ0) (z)Xρsa,σ ( zsaρ −1) + ∑ σ za − za+1 (za − za+1)2 − 1 Vσ−1(Ǐ0) (z)Xρsa,σsa ( zsaρ −1) − ∑ σ 1 (za+1 − za)2 − 1 Vσ−1(Ǐ0) (z)Xρsa,σ ( zsaρ −1) . Changing the summation index in the first and second sums from σ to σsa, we observe that the second and third sums cancel each other, while the first and the forth sums combine together and simplify to the expression∑ σ Vσ−1(Ǐ0) (z)Xρsa,σ ( zsaρ −1) = ∑ σ Vσ−1(Ǐ0) (z)Xµ,σ ( zµ −1) , which appears in the left-hand side of formula (7.21). ■ Using Lemmas 7.6 and 7.7, we evaluate the sums over σ and τ in the right-hand side of the formula (7.18) and get the equality∑ σ∈Sk Ṽσ(J0)(z)Vσ(I0)(z) = ∑ π Vσ0(I0)(z πσ0)ṼJ0(z π)Φ(zπσ0). (7.24) Using formula (7.17) in the left-hand side and making the substitution π = σσ0 in the right-hand side, we obtain that (7.24) can be written as∑ (I,J)∈Sp,q,r,k ṼJ(z)VI(z) = 1 Cp,q,r,k ∑ σ Vσ0(I0)(z σ)ṼJ0(z σσ0)Φ(zσ), which is formula (7.16). Proposition 5.6 is proved. 20 M. Kosmakov and V. Tarasov A Proof of Proposition 5.1 In this appendix, we will consider only the algebra Y (gl2) and, for convenience, we will not write the superscript ⟨2⟩. We will use the commutation relations T11(u)T11(t) = T11(t)T11(u), T12(u)T12(t) = T12(t)T12(u), T22(u)T22(u) = T22(t)T22(u), (A.1) T11(u)T12(t) = u− t− 1 u− t T12(t)T11(u) + 1 u− t T12(u)T11(t), (A.2) T22(u)T12(t) = u− t+ 1 u− t T12(t)T22(u)− 1 u− t T12(u)T22(t), (A.3) following from the defining relations in Y (gl2), see (2.4). We will also use the next statement. Proposition A.1. One has T11(u)T12(t1) · · ·T12(tk) = k∏ i=1 u− ti − 1 u− ti T12(t1) · · ·T12(tk)T11(u) (A.4) + k∑ l=1 1 u− tl k∏ m=1 m ̸=l tl − tm − 1 tl − tm T12(t1) · · ·T12(tl−1)T12(tl+1) · · ·T12(tk)T12(u)T11(tl), T22(u)T12(t1) · · ·T12(tk) = k∏ i=1 u− ti + 1 u− ti T12(t1) · · ·T12(tk)T22(u) (A.5) − k∑ l=1 1 u− tl k∏ m=1 m ̸=l tl − tm + 1 tl − tm T12(t1) · · ·T12(tl−1)T12(tl+1) · · ·T12(tk)T12(u)T22(tl). Proof. The statement goes back to [23]. We will prove it by induction on k. Consider for- mula (A.4). The statement for k = 1 is given by formula (A.2). We use the induction assumption to move T11(u) through the product T12(t1) · · ·T12(tk−1): T11(u)T12(t1) · · ·T12(tk−1)T12(tk) = k−1∏ i=1 u− ti − 1 u− ti T12(t1) · · ·T12(tk−1)T11(u)T12(tk) (A.6) + k−1∑ l=1 1 u− tl k−1∏ m=1 m̸=l tl − tm − 1 tl − tm T12(t1) · · ·T12(tl−1)T12(tl+1) · · ·T12(tk−1)T12(u)T11(tl)T12(tk). Then we apply (A.2) to the product T11(u)T12(tk) and T11(tl)T12(tk) and the right-hand side of (A.6) becomes k∏ i=1 u− ti − 1 u− ti T12(t1) · · ·T12(tk−1)T12(tk)T11(u) + 1 u− tk k−1∏ i=1 u− ti − 1 u− ti T12(t1) · · ·T12(tk−1)T12(u)T11(tk) + k−1∑ l=1 1 u− tl k∏ m=1 m ̸=l tl − tm − 1 tl − tm × T12(t1) · · ·T12(tl−1)T12(tl+1) · · ·T12(tk−1)T12(u)T12(tk)T11(tl) New Combinatorial Formulae for Nested Bethe Vectors 21 + k−1∑ l=1 1 u− tl 1 tl − tk k−1∏ m=1 m ̸=l tl − tm − 1 tl − tm × T12(t1) · · ·T12(tl−1)T12(tl+1) · · ·T12(tk−1)T12(u)T12(tl)T11(tk). The first term here coincide with the first term in the right-hand side of formula (A.4). The third term here is the second term of (A.4) without l = k summand. We also used that T12(u) and T12(tk) commute, see (A.1). The second and forth summands combine into the product 1 u− tk k−1∏ m=1 tk − tm − 1 tk − tm T12(t1) · · ·T12(tl−1)T12(tl+1) · · ·T12(tk−1)T12(u)T11(tl), (A.7) using the following identity: 1 u− tk k−1∏ i=1 u− ti − 1 u− ti + k−1∑ l=1 1 (u− tl)(tl − tk) k−1∏ m=1 m̸=l tl − tm − 1 tl − tm = 1 u− tk k−1∏ m=1 tk − tm − 1 tk − tm . The product (A.7) is exactly the summand with l = k of the second term in (A.4). Formula (A.4) is proved. The proof of formula (A.5) is similar to that of formula (A.4) with relation (A.3) used instead of (A.2). ■ Recall that for the gl2 case we have Bξ(t) = T12(t1) · · ·T12(tξ), and thus Proposition 5.1 can be rewritten as follows. Proposition A.2. Let ξ be a nonnegative integer and t = (t1, . . . , tξ). Then ∆(T12(t1) · · ·T12(tξ)) (A.8) = ξ∑ η=0 1 (ξ − η)!η! Symt [( η∏ i=1 T12(ti)⊗ ξ∏ j=η+1 T12(tj) )( ξ∏ k=η+1 T22(tk)⊗ η∏ l=1 T11(tl) )] . Remark. Notice that according to (A.1), the factors in each of the large products commute among themselves, so the order of the factors is irrelevant. (A.8). Proof. Consider the summand from the right-hand side of (A.8) with a given η, Fη,ξ−η(t) = Symt [( η∏ i=1 T12(ti)⊗ ξ∏ j=η+1 T12(tj) )( ξ∏ k=η+1 T22(tk)⊗ η∏ l=1 T11(tl) )] . (A.9) Let Pη,ξ−η(t) = ∏ 1≤i≤η<j≤ξ ti − tj − 1 ti − tj × ( η∏ i=1 T12(ti)⊗ ξ∏ j=η+1 T12(tj) )( ξ∏ k=η+1 T22(tk)⊗ η∏ l=1 T11(tl) ) , Uη,ξ−η(t) = ∏ 1≤i<j≤η ti − tj − 1 ti − tj ∏ η+1≤i<j≤ξ ti − tj − 1 ti − tj , tσ = ( tσ(1), . . . , tσ(ξ) ) . 22 M. Kosmakov and V. Tarasov Using this notation, formula (A.9) can be written as Fη,ξ−η(t) = ∑ σ∈Sξ Uη,ξ−η(t σ)Pη,ξ−η(t σ). Observe that Fη,ξ−η(t) is symmetric in t1, . . . , tξ. Denote by Sη × Sξ−η the subgroup of Sξ stabilizing the subsets {1, . . . , η} and {η + 1, . . . , ξ}. We have Fη,ξ−η(t) = 1 η!(ξ − η)! ∑ τ∈Sη×Sξ−η Fη,ξ−η(t τ ) = 1 η!(ξ − η)! ∑ τ∈Sη×Sξ−η ∑ σ∈Sξ Uη,ξ−η(t τσ)Pη,ξ−η(t τσ). Changing the summation variable in the inner sum, σ = τ−1ρτ , and using the fact that Pη,ξ−η(t ρτ ) = Pη,ξ−η(t ρ) for all τ ∈ Sη × Sξ−η, we get Fη,ξ−η(t) = 1 η!(ξ − η)! ∑ τ∈Sη×Sξ−η ∑ ρ∈Sξ Uη,ξ−η(t ρτ )Pη,ξ−η(t ρτ ) = 1 η!(ξ − η)! ∑ ρ∈Sξ Pη,ξ−η(t ρ) ∑ τ∈Sη×Sξ−η Uη,ξ−η(t ρτ ). Furthermore, using the identity∑ τ∈Sn ∏ 1≤i<j≤n xτ(i) − xτ(j) − 1 xτ(i) − xτ(j) = n!, (A.10) we obtain that ∑ τ∈Sη×Sξ−η Uη,ξ−η(t ρτ ) = η!(ξ − η)! and Fη,ξ−η(t) = ∑ ρ∈Sξ Pη,ξ−η(t ρ). (A.11) Using formula (A.11), the statement of Proposition A.2 can be formulated as follows: ∆(T12(t1) · · ·T12(tξ)) = ξ∑ η=0 1 (ξ − η)!η! ∑ ρ∈Sξ Pη,ξ−η(t ρ). (A.12) We will prove this formula using the induction on ξ. The base of induction at ξ = 1 is given by formula (2.5): ∆(T12(t1)) = T12(t1)⊗ T11(t1) + T22(t1)⊗ T12(t1). (A.13) To make the induction step, we use that ∆(Bξ(t)) = ∆ ( T12(t1) ) ∆(T12(t2) · · ·T12(tξ)), (A.14) expand the first factor according to (A.13), and apply the induction assumption to expand the second factor. Denote by S′ξ−1 ⊂ Sξ the subgroup of permutations ρ, such that ρ(1) = 1. Then the right-hand side of formula (A.14) becomes T12(t1)⊗ T11(t1) ξ∑ η=1 1 (ξ − η)!(η − 1)! ∑ τ∈S′ ξ−1 Pη−1,ξ−η ( tτ(2), . . . , tτ(ξ) ) + T22(t1)⊗ T12(t1) ξ−1∑ η=0 1 (ξ − 1− η)!η! ∑ ρ∈S′ ξ−1 Pη,ξ−η−1 ( tρ(2), . . . , tρ(ξ) ) , (A.15) New Combinatorial Formulae for Nested Bethe Vectors 23 where in the first term we shifted the summation variable of the exterior sum. Using the definition of Pη,ξ−1−η(t) and Pη−1,ξ−η(t), we further expand expression (A.15): ξ∑ η=1 1 (ξ − η)!(η − 1)! ∑ τ∈S′ ξ−1 ∏ 1<i≤η<j≤ξ tτ(i) − tτ(j) − 1 tτ(i) − tτ(j) × ( T12(t1) η∏ i=2 T12 ( tτ(i) ) ⊗ T11(t1) ξ∏ j=η+1 T12 ( tτ(j) ))( ξ∏ k=η+1 T22 ( tτ(k) ) ⊗ η∏ l=2 T11 ( tτ(l) )) + ξ−1∑ η=0 1 (ξ − η − 1)!η! ∑ ρ∈S′ ξ−1 ∏ 1<i≤η+1<j≤ξ tρ(i) − tρ(j) − 1 tρ(i) − tρ(j) × ( T22(t1) η+1∏ i=2 T12 ( tρ(i) ) ⊗ T12(t1) ξ∏ j=η+2 T12 ( tρ(j) ))( ξ∏ k=η+2 T22 ( tρ(k) ) ⊗ η+1∏ l=2 T11 ( tρ(l) )) . In the first term, we move T11(t1) through the product ∏ξ j=η+1 T12 ( tτ(j) ) using formula (A.4): T11(t1) ξ∏ j=η+1 T12 ( tτ(j) ) = ( ξ∏ j=η+1 t1 − tτ(j) − 1 t1 − tj T12 ( tτ(j) )) T11(t1) + ξ∑ p=η+1 1 t1 − tτ(p) ( ξ∏ j=η+1 j ̸=p tτ(p) − tτ(j) − 1 tτ(p) − tτ(j) T12 ( tτ(j) )) T12(t1)T11 ( tτ(p) ) . Similarly, in the second term we move T22(t1) through the product ∏η m=2 T12 ( tρ(m) ) using for- mula (A.5): T22(t1) η+1∏ i=2 T12 ( tρ(i) ) = ( η+1∏ i=2 t1 − tρ(i) + 1 t1 − tρ(i) T12 ( tρ(m) )) T22(t1) − η+1∑ s=2 1 t1 − ts ( η+1∏ i=1 i ̸=s tρ(s) − tρ(i) + 1 tρ(s) − tρ(i) T12 ( tρ(i) )) T12(t1)T22 ( tρ(s) ) , After all, the right-hand side of (A.14) becomes a sum of four terms: ∆(Bξ(t)) = Y1(t) + Y2(t) + Y3(t) + Y4(t), where Y1(t) = ξ∑ η=1 1 (ξ − η)!(η − 1)! ∑ τ∈S′ ξ−1 [ ξ∏ l=η+1 t1 − tτ(l) − 1 t1 − tτ(l) ∏ 1<i≤η<j≤ξ tτ(i) − tτ(j) − 1 tτ(i) − tτ(j) × ( T12(t1) η∏ i=2 T12 ( tτ(i) ) ⊗ ξ∏ j=η+1 T12 ( tτ(j) )) × ( ξ∏ k=η+1 T22 ( tτ(k) ) ⊗ T11(t1) η∏ l=2 T11 ( tτ(l) ))] , 24 M. Kosmakov and V. Tarasov Y2(t) = ξ−1∑ η=1 1 (ξ − η)!(η − 1)! × ∑ τ∈S′ ξ−1 ξ∑ l=η+1 [ 1 t1 − tτ(l) ∏ 1<i≤η<j≤ξ tτ(i) − tτ(j) − 1 tτ(i) − tτ(j) ξ∏ m=η+1 m ̸=l tτ(l) − tτ(m) − 1 tτ(l) − tτ(m) × ( T12(t1) η∏ k=2 T12 ( tτ(k) ) ⊗ T12(t1) ξ∏ m=η+1 m ̸=l T12 ( tτ(m) )) × ( ξ∏ i=η+1 T22 ( tτ(i) ) ⊗ T11 ( tτ(l) ) η∏ j=2 T11 ( tτ(j) ))] . Y3(t) = ξ−1∑ η=0 1 (ξ − η − 1)!η! ∑ ρ∈S′ ξ−1 [ η+1∏ m=2 tρ(m) − t1 − 1 tρ(m) − t1 ∏ 1<i≤η+1<j≤ξ tρ(i) − tρ(j) − 1 tρ(i) − tρ(j) × ( η+1∏ m=2 T12 ( tρ(m) ) ⊗ T12(t1) ξ∏ l=η+2 T12 ( tρ(l) )) × ( T22(t1) ξ∏ i=η+2 T22 ( tρ(i) ) ⊗ η+1∏ j=2 T11 ( tρ(j) ))] . Y4(t) = − ξ−1∑ η=1 1 (ξ − η − 1)!η! × ∑ ρ∈S′ ξ−1 [ η+1∑ k=2 1 t1 − tρ(k) ∏ 1<i≤η+1<j≤ξ tρ(i) − tρ(j) − 1 tρ(i) − tρ(j) η+1∏ m=2 m ̸=k tρ(k) − tρ(m) + 1 tρ(k) − tρ(m) × ( T12(t1) η+1∏ m=2 m ̸=k T12 ( tρ(m) ) ⊗ T12(t1) ξ∏ l=η+2 T12 ( tρ(l) )) × ( T22 ( tρ(k) ) ξ∏ i=η+2 T22 ( tρ(i) ) ⊗ η+1∏ j=2 T11 ( tρ(j) ))] . To complete the proof, we will show that Y1(t) + Y3(t) = ξ∑ η=0 1 (ξ − η)!η! ∑ ρ∈Sξ Pη,ξ−η(t ρ) and Y2(t) + Y4(t) = 0. (A.16) We will start with the first equality in (A.16). Observe that Y1(t) = ξ∑ η=1 1 (ξ − η)!(η − 1)! ∑ σ∈Sξ σ(1)=1 Pη,ξ−η(t σ), and Y3(t) = ξ−1∑ η=0 1 (ξ − η − 1)!η! ∑ σ∈Sξ σ(η+1)=1 Pη,ξ−η(t σ). New Combinatorial Formulae for Nested Bethe Vectors 25 On the other hand, we have ξ∑ η=0 1 (ξ − η)!η! ∑ σ∈Sξ Pη,ξ−η(t σ) = ξ∑ η=1 1 (ξ − η)!η! ∑ σ∈Sξ σ−1(1)∈{1,...,η} Pη,ξ−η(t σ) + ξ−1∑ η=0 1 (ξ − η)!η! ∑ σ∈Sξ σ−1(1)∈{η+1,...,ξ} Pη,ξ−η(t σ). Denote by sa,b ∈ Sξ the transposition of a and b. Then we have ∑ σ∈Sξ σ−1(1)∈{1,...,η} Pη,ξ−η(t σ) = η∑ l=1 ∑ τ∈Sξ, τ(1)=1 Pη,ξ−η(t τs1,l) = η ∑ τ∈Sξ, τ(1)=1 Pη,ξ−η(t τ ). For the first step, we used l = σ−1(1) and τ = σs1,σ−1(1), so that τ(1) = 1. For the second step, we used the equality Pη,ξ−η(t τs1,l) = Pη,ξ−η(t τ ). Similarly,∑ σ∈Sξ σ−1(1)∈{η+1,...,ξ} Pη,ξ−η(t σ) = (ξ − η) ∑ ρ∈Sξ, ρ(η+1)=1 Pη,ξ−η(t ρ). Therefore, ξ∑ η=0 1 (ξ − η)!η! ∑ σ∈Sξ Pη,ξ−η(t σ) = ξ∑ η=1 1 (ξ − η)!(η − 1)! ∑ σ∈Sξ σ(1)=1 Pη,ξ−η(t σ) + ξ−1∑ η=0 1 (ξ − 1− η)!η! ∑ σ∈Sξ σ(η+1)=1 Pη,ξ−η(t σ) = Y1(t) + Y3(t). Finally, we show that Y2(t) + Y4(t) = 0. Observe that Y2(t) can be written as Y2(t) = ξ−1∑ η=1 1 (ξ − η)!(η − 1)! × ξ∑ l=η+1 ∑ τ∈S′ ξ−1 [ 1 t1 − tτ(l) ∏ 1<i≤η<j≤ξ tτ(i) − tτ(j) − 1 tτ(i) − tτ(j) ξ∏ m=η+1 m ̸=l tτ(l) − tτ(m) − 1 tτ(l) − tτ(m) × ( T12(t1) η∏ k=2 T12 ( tτ(k) ) ⊗ T12(t1) ξ∏ m=η+1 m ̸=l T12 ( tτ(m) )) × ( ξ∏ i=η+1 T22 ( tτ(i) ) ⊗ T11(tτ(l)) η∏ j=2 T11 ( tτ(j) ))] . 26 M. Kosmakov and V. Tarasov Changing the summation variable in the inner sum, τ = σsl,η+1, we obtain that Y2(t) = ξ−1∑ η=1 1 (ξ − η)!(η − 1)! × ξ∑ l=η+1 ∑ σ∈S′ ξ−1 [ 1 t1 − tσ(η+1) ξ∏ m=η+2 tσ(η+1) − tσ(m) − 1 tσ(η+1) − tσ(m) ∏ 1<i≤η<j≤ξ tσ(i) − tσ(j) − 1 tσ(i) − tσ(j) × ( T12(t1) η∏ k=2 T12 ( tσ(k) ) ⊗ T12(t1) ξ∏ m=η+1 T12 ( tσ(m) )) × ( ξ∏ i=η+2 T22 ( tσ(i) ) ⊗ η+1∏ j=2 T11 ( tσ(j) ))] . The expression under the inner sum over σ does not depend on l and after a redistribution of factors, we get Y2(t) = ξ−1∑ η=1 1 (ξ − η − 1)!(η − 1)! × ∑ σ∈S′ ξ−1 ∑ σ∈S′ ξ−1 [ 1 t1 − tσ(η+1) ξ∏ m=η+2 tσ(η+1) − tσ(m) − 1 tσ(η+1) − tσ(m) η∏ i=2 tσ(i) − tσ(η+1) − 1 tσ(i) − tσ(η+1) × ∏ 1<i<η+1<j≤ξ tσ(i) − tσ(j) − 1 tσ(i) − tσ(j) × ( T12(t1) η∏ k=2 T12 ( tσ(k) ) ⊗ T12(t1) ξ∏ m=η+1 T12 ( tσ(m) )) × ( ξ∏ i=η+2 T22 ( tσ(i) ) ⊗ η+1∏ j=2 T11 ( tσ(j) ))] . (A.17) Similarly, Y4(t) can be written as Y4(t) = ξ−1∑ η=1 1 (ξ − 1− η)!η! × η+1∑ k=2 ∑ ρ∈S′ ξ−1 [ 1 t1 − tρ(k) ∏ 1<i≤η+1<j≤ξ tρ(i) − tρ(j) − 1 tρ(i) − tρ(j) η+1∏ m=2 m ̸=k tρ(k) − tρ(m) + 1 tρ(k) − tρ(m) × ( T12(t1) η+1∏ m=2 m ̸=k T12 ( tρ(m) ) ⊗ T12(t1) ξ∏ l=η+2 T12 ( tρ(l) )) × ( T22 ( tρ(k) ) ξ∏ i=η+2 T22 ( tρ(i) ) ⊗ η+1∏ j=2 T11 ( tρ(j) ))] , and changing the summation variable in the inner sum, ρ = σsk,η+1, we get Y4(t) = − ξ−1∑ η=1 1 (ξ − 1− η)!η! New Combinatorial Formulae for Nested Bethe Vectors 27 × η+1∑ k=2 ∑ σ∈S′ ξ−1 [ 1 t1 − tσ(η+1) η∏ m=2 tσ(η+1) − tσ(m) + 1 tσ(η+1) − tσ(m) ∏ 1<i≤η+1<j≤ξ tσ(i) − tσ(j) − 1 tσ(i) − tσ(j) × ( T12(t1) η∏ m=2 T12 ( tσ(m) ) ⊗ T12(t1) ξ∏ l=η+2 T12 ( tσ(l) )) × ( ξ∏ i=η+1 T22 ( tσ(i) ) ⊗ η+1∏ j=2 T11 ( tσ(j) ))] . The expression under the inner sum over σ does not depend on k and after a redistribution of factors, we get Y4(t) = − ξ−1∑ η=1 1 (ξ − η − 1)!(η − 1)! × ∑ σ∈S′ ξ−1 [ 1 t1 − tσ(η+1) η∏ m=2 tσ(η+1) − tσ(m) + 1 tσ(η+1) − tσ(m) ξ∏ q=η+2 tσ(η+1) − tσ(q) − 1 tσ(η+1) − tσ(q) × ∏ 1<i<η+1<j≤ξ tσ(i) − tσ(j) − 1 tσ(i) − tσ(j) × ( T12(t1) η∏ m=2 T12 ( tσ(m) ) ⊗ T12(t1) ξ∏ l=η+2 T12 ( tσ(l) )) × ( ξ∏ i=η+1 T22 ( tσ(i) ) ⊗ η+1∏ j=2 T11 ( tσ(j) ))] . (A.18) Formulae (A.17) and (A.18) show that Y2(t) +Y4(t) = 0. This completes the proof of for- mula (A.12). 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id nasplib_isofts_kiev_ua-123456789-213516
institution Digital Library of Periodicals of National Academy of Sciences of Ukraine
issn 1815-0659
language English
last_indexed 2026-03-15T03:36:23Z
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publisher Інститут математики НАН України
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spelling Kosmakov, Maksim
Tarasov, Vitaly
2026-02-18T11:22:56Z
2025
New Combinatorial Formulae for Nested Bethe Vectors. Maksim Kosmakov and Vitaly Tarasov. SIGMA 21 (2025), 060, 28 pages
1815-0659
2020 Mathematics Subject Classification: 17B37; 81R50; 82B23
arXiv:2312.00980
https://nasplib.isofts.kiev.ua/handle/123456789/213516
https://doi.org/10.3842/SIGMA.2025.060
We give new combinatorial formulae for vector-valued weight functions (off-shell nested Bethe vectors) for the evaluation modules over the Yangian Y(₄). The case of Y(ₙ) for an arbitrary n is considered in [Lett. Math. Phys. 115 (2025), 12, 20 pages, arXiv:2402.15717].
The authors thank the referees for their very careful reading of this paper and their valuable suggestions. The second author is supported in part by Simons Foundation grants 430235 and 852996.
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Інститут математики НАН України
Symmetry, Integrability and Geometry: Methods and Applications
New Combinatorial Formulae for Nested Bethe Vectors
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published earlier
spellingShingle New Combinatorial Formulae for Nested Bethe Vectors
Kosmakov, Maksim
Tarasov, Vitaly
title New Combinatorial Formulae for Nested Bethe Vectors
title_full New Combinatorial Formulae for Nested Bethe Vectors
title_fullStr New Combinatorial Formulae for Nested Bethe Vectors
title_full_unstemmed New Combinatorial Formulae for Nested Bethe Vectors
title_short New Combinatorial Formulae for Nested Bethe Vectors
title_sort new combinatorial formulae for nested bethe vectors
url https://nasplib.isofts.kiev.ua/handle/123456789/213516
work_keys_str_mv AT kosmakovmaksim newcombinatorialformulaefornestedbethevectors
AT tarasovvitaly newcombinatorialformulaefornestedbethevectors