Two-point boundary value problems for differential-operator equations

We study general two-point boundary value problems for a non-homogeneous differential-operator equation of the second order with an unbounded linear operator in a Banach space. The main classical solvability condition is given in terms of the property of the resolvent of the operator at the points,...

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Datum:2016
Hauptverfasser: Eidelman, Y., Yakubov, Ya.
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Veröffentlicht: Інститут математики НАН України 2016
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Transactions of Institute of Mathematics of NAS of Ukraine
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author Eidelman, Y.
Yakubov, Ya.
Eidelman, Y.
Yakubov, Ya.
author_facet Eidelman, Y.
Yakubov, Ya.
Eidelman, Y.
Yakubov, Ya.
author_institution_txt_mv [ { "author": "Y. Eidelman", "institution": "Tel-Aviv University" }, { "author": "Ya. Yakubov", "institution": "Tel-Aviv University" } ]
author_sort Eidelman, Y.
baseUrl_str https://trim.imath.kiev.ua/index.php/trim/oai
collection OJS
datestamp_date 2018-01-23T01:38:29Z
description We study general two-point boundary value problems for a non-homogeneous differential-operator equation of the second order with an unbounded linear operator in a Banach space. The main classical solvability condition is given in terms of the property of the resolvent of the operator at the points, which are opposite to the eigenvalues of the corresponding ordinary differential operator. At the end of the paper, two particular types of boundary value conditions are treated: periodic and Dirichlet.
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fulltext Збiрник праць Iн-ту математики НАН України 2016, т. 13, № 1, 58–75 Y. Eidelman, Ya. Yakubov (Tel-Aviv University, Israel) Two-point boundary value problems for differential-operator equations eideyu@post.tau.ac.il and yakubov@post.tau.ac.il We study general two-point boundary value problems for a non- homogeneous differential-operator equation of the second order with an unbounded linear operator in a Banach space. The main classical solvability condition is given in terms of the property of the resolvent of the operator at the points, which are opposite to the eigenvalues of the corresponding ordinary differential operator. At the end of the paper, two particular types of boundary value conditions are treated: periodic and Dirichlet. 1. Introduction In this paper, we study general two-point boundary value problems for a non-homogeneous differential-operator equation of the second order with an unbounded linear operator in a Banach space. We impose some restrictions on the right-hand side of the equation. Then, we formulate the conditions of the unique solvability of the problems in terms of the property of the resolvent of the operator at the points, which are opposite to the eigenvalues of the correspondi- ng ordinary differential operator. In fact, we find sufficient conditions for the unique solvability, but some of them are also necessary. At the c© Y. Eidelman, Ya. Yakubov, 2016 Two-point boundary value problems... 59 end of the paper, two particular types of boundary value conditions are treated: periodic and Dirichlet. We represent the solutions of the problems as a series of vector- valued functions which include the eigenfunctions of the correspondi- ng ordinary boundary value problem. To obtain the convergence of the series, we essentially use the Abel transform of the series. Here we use an approach suggested by A. V. Knyazyuk in the paper [8] for the study of the model Dirichlet problem. In the paper, we study classical solutions of the problems. The solutions from the Lp spaces and from the Hölder spaces have been studied by V. Arendt and S. Bu in [1] by using of the technique of Fourier series and Marcinkiewicz multipliers. The types of boundary value conditions, which are covered by our results, are essentially wider than those in the above mentioned papers. In particular, our paper contains a generalization of the main result in [8]. Problems in Lp spaces, with rather general non-local boundary value conditions (multipoint, integro-differential, functional), and for higher order abstract differential-operator equations, have been studied in a series of papers by A. Favini and Ya. Yakubov [2]- [5] (paper [2] is joint with V. Shakhmurov). For the results in the framework of Hilbert spaces, we refer the reader to the monograph by S. Yakubov and Ya. Yakubov [9] and reference therein. Solvability of problems of the form (1)-(2), in some weighted Hölder spaces, has been studied by L. M. Gershtein and P. E. Sobolevskii in [6]. The main solvability condition is given in some implicit form. Moreover, in contrast to our case, the operator A in [6] is assumed to be bounded weakly positive with a compact inverse operator A−1. In [7], the authors continue their study for problems from [6] but with a non-constant operator A = A(t). Some additional restrictions on A(t) are applied. 60 Y. Eidelman, Ya. Yakubov 2. The statement of the problem In a Banach space X, we consider the differential-operator equation d2v dt2 = Av + f(t), 0 < t < T (1) with the boundary value conditions{ L1(v) := α11v(0) + α12v ′(0) + β11v(T ) + β12v ′(T ) = 0, L2(v) := α21v(0) + α22v ′(0) + β21v(T ) + β22v ′(T ) = 0. (2) Here, A ia a closed linear unbounded operator with domain D(A), f(t) is a continuous on [0, T ] vector valued function, the coeffici- ents αij and βij are complex numbers. It is assumed that the forms L1(v), L2(v) are linearly independent. By a solution of the problem (1), (2) we mean a continuously differentiable on [0, T ] function v(t) which takes the values in D(A), has a continuous on (0, T ) second order derivative and satisfies (1), (2). We use the eigenfunctions and eigenvalues of the ordinary di- fferential operator of the second order defined by L(y)(t) = −d 2y dt2 , 0 < t < T, L1(y) = 0, L2(y) = 0. (3) The operator L is defined on continuously differentiable on [0, T ] functions y(t), which have a continuous on (0, T ) second order deri- vative y′′(t), with y′′(t) ∈ L2(0, T ), satisfying the boundary value conditions (2). 3. The conditions Here, we present the main conditions on the data of the problem which are used in the paper. Below, C means a positive constant. The conditions on the ordinary differential operator L in (3) are the Two-point boundary value problems... 61 following: (α1) The operator L, treated as an operator in L2(0, T ), is a symmetric operator. (α2) The operator L has a complete, in L2(0, T ), orthonormal system ϕn(t), n = 1, 2, . . . of eigenfunctions. (α3) The eigenvalues λn, n = 1, 2, . . . of the operator L satisfy the relation lim inf n→∞ |λn| n2 > 0. (α4) There is a sequence of numbers sn, n = 1, 2, . . . such that limn→∞ sn =∞ and |sn − sn+1| ≤ C, ∣∣∣∣λnsn ∣∣∣∣ ≤ Cn, ∣∣∣∣λn+1 sn+1 − λn sn ∣∣∣∣ ≤ C, n = 1, 2, . . . . Note that the typical cases for condition (α4) are λn = s2n or λn = −s2n. The common property of the operators −A and L is that their spectra are disjoint with the following additional condition: (β) All the numbers −λn, n = 1, 2, . . . are regular points of the operator A and, moreover, there exists a constant M > 0 such that the inequalities ‖λn(A+ λnI) −1‖ ≤M, n = 1, 2, . . . hold. To formulate the conditions on the function f(t) in the right hand side in (1), we define the “Fourier coefficients” fn = ∫ T 0 f(t)ϕn(t) dt, n = 1, 2, . . . . (1) The conditions are the following: (γ) The inequalities ‖fnϕn(t)‖ ≤ C, ‖fnϕ′n(t)‖ ≤ C, n = 1, 2, . . . , 0 ≤ t ≤ T (2) 62 Y. Eidelman, Ya. Yakubov and ‖ n∑ k=1 skfkϕk(t)‖ ≤ C(δ, γ), n = 1, 2, . . . , δ ≤ t ≤ γ (3) for any δ, γ, with 0 < δ < γ < T , and with si defined in the condition (α4), hold. In particular cases, presented in two last sections, the condition (γ) turns out to be valid if a more explicit condition holds: (γ0) The function f(t) has, on [0, T ], the derivative which satisfies the Hölder condition, i.e., for some C > 0, 0 < α ≤ 1, ‖f ′(t)− f ′(s)‖ ≤ C|t− s|α, ∀t, s ∈ [0, T ]. Let v(t) be a solution of the problem (1), (2) from section 2, if it exists. Set vn = ∫ T 0 v(t)ϕn(t) dt, n = 1, 2, . . . (4) The following lemma yields the connection between the ”Fourier coefficients” of the function f(t) in the right hand side of the equation and of the solution v(t). Lemma 1. Assume that the condition (α1) holds and that v(t) is a solution of the problem (1), (2) from section 2 with the given function f(t). Then, the equalities (λnI +A)vn = −fn, n = 1, 2, . . . (5) hold with vn, fn as in (1), (4), and λn to be the eigenvalues of the operator L. Proof. Multiplying the equality (1) from section 2 by ϕn(t) and integrating from 0 to T we get∫ T 0 d2v dt2 ϕn(t) dt = Avn + fn, n = 1, 2, . . . . Two-point boundary value problems... 63 Integrating by parts in the left hand side and using the condition (α1) and the fact that ϕn(t) is an eigenfunction of the operator L with the eigenvalue λn, we obtain (5). � 4. The uniqueness theorem At first, we consider the uniqueness criteria for the problem (1), (2) from section 2, i.e., for the homogeneous problem d2v dt2 = Av, 0 < t < T, L1(v) = 0, L2(v) = 0. (1) Theorem 2. Assume that the conditions (α1), (α2) hold. The problem (1) has only a trivial solution if and only if each eigenvalue of the operator L in (3) from section 2 is not an eigenvalue of the operator −A. Proof. Assume that λ is a common eigenvalue of the operators −A and L with the corresponding eigenvector g ∈ X of A and ei- genfunction ϕ(t) of L. Then, the function v(t) = ϕ(t)g is a nontrivial solution of the problem (1). Assume now that the sets of eigenvalues of the operators L and −A are disjoint. Let v(t) be a solution of the problem (1). Using Lemma 1, we get −λnvn = Avn, n = 1, 2, . . . . Since the operators λnI + A, n = 1, 2, . . . are injective, we get vn = 0, n = 1, 2, . . . and, therefore, since the system {ϕn(t)} is complete, we conclude that v(t) = 0, 0 ≤ t ≤ T . � 5. The existence and uniqueness theorems In this section, we present the basic results of the paper. First, we show that the existence of the unique solution of the problem for 64 Y. Eidelman, Ya. Yakubov any admissible function f(t) implies that all the points λn, defined above, are regular points of the operator −A. Theorem 3. Assume that the conditions (α1), (α2) hold and the problem (1), (2) from section 2 has a unique solution for any conti- nuous f(t) satisfying the condition (γ). Then, every eigenvalue λn, n = 1, 2, . . . of the operator L is a regular point of the operator −A. Proof. For any positive integer m and for any x ∈ X take f(t) = ϕm(t)x. Let v(t) be the corresponding solution of the problem. Consi- der the expantion of v(t) in the form v(t) = ∞∑ n=1 vnϕn(t) (1) with coefficients vn defined by (4) from section 3. Using Lemma 1, we obtain the equalities (5) from section 3 with fm = x and fn = 0, n 6= m. From the uniqueness of the solution, using Theorem 2, we conclude that all the numbers λn, n = 1, 2, . . . are not eigenvalues of the operator −A. Hence, we get vn = 0, n 6= m and, moreover, the equation (λmI +A)vm = −x has a unique solution vm. Since this holds for any x ∈ X we conclude that −λm is a regular point of the operator A and vm = −(λmI + A)−1x. Hence, it follows that v(t) = vmϕm(t) = −(λmI +A)−1xϕm(t). � We prove now, under some additional conditions on the resolvent of the operator A at the points −λn, the unique solvability of the problem. Theorem 4. Assume that the conditions (α1)-(α4) and (β) hold. Then, for any continuous f(t), satisfying the condition (γ), the problem (1), (2) from section 2 has a unique solution. Two-point boundary value problems... 65 Proof. Take any f(t) satisfying (γ). We consider the expression v(t) = − ∞∑ n=1 (λnI +A)−1fnϕn(t), 0 ≤ t ≤ T (2) with fn defined in (1) from section 3, and prove that v(t) is the unique solution of the problem (1), (2) from section 2. Formally differentiating, we get v′(t) = − ∞∑ n=1 (λnI +A)−1fnϕ ′ n(t), 0 ≤ t ≤ T. (3) The conditions (α3) and (β) and the inequalities in (2) from section 3 imply that the series in (2), (3) converge uniformly on [0, T ]. Hence, it follows that v(t) is a continuously differentiable on [0, T ] function with the derivative defined in (3). Moreover, since ϕn(t) satisfy the boundary value conditions in (3) from section 2, the formulas (2), (3) imply that the function v(t) satisfy the boundary value conditions (2) from section 2. Formally differentiating (2) twice and using the equality ϕ′′n(t) = −λnϕn(t), we get v′′(t) = ∞∑ n=1 λn(λnI +A)−1fnϕn(t). (4) We now prove that the series in (4) converges uniformly on [δ, γ] for any δ, γ ∈ (0, T ), δ < γ. This will imply that the formula (4) yields the second derivative of the function v(t) in the interval (0, T ). Set an = λn sn (λnI +A)−1, n = 1, 2, . . . . Then, the series in (4) has the form ∑∞ n=1 ansnfnϕn(t). For any δ, γ ∈ (0, T ), δ < γ we prove the uniform convergence of this series, for δ ≤ t ≤ γ, using the Abel transform. To this end, we should 66 Y. Eidelman, Ya. Yakubov check that lim n→∞ (s1f1ϕ1(t) + s2f2ϕ2(t) + · · ·+ snfnϕn(t))an = 0, δ ≤ t ≤ γ. (5) Indeed, by virtue of the condition (β), we get ‖an‖ ≤ C |sn| , n = 1, 2, . . . , which, together with the condition (3) from section 3 and the condi- tion limn→∞ sn =∞, implies (5). Thus, the Abel transform implies that the uniform, on [δ, γ], convergence of the series ∞∑ n=1 ansnfnϕn(t) follows from the uniform convergence of the series ∞∑ n=1 (s1f1ϕ1(t) + s2f2ϕ2(t) + · · ·+ snfnϕn(t))(an − an+1) (6) on the same segment. So, check the uniform convergence of (6). We have an − an+1 = λn sn (λnI +A)−1 − λn+1 sn+1 (λn+1I +A)−1. Hence, it follows that an − an+1 = (λnI +A)−1 ( λn sn − λn+1 sn+1 ) + λn+1 sn+1 ((λnI +A)−1 − (λn+1I +A)−1). The resolvent identity yields (λnI+A) −1−(λn+1I+A) −1 = (λn+1−λn)(λnI+A)−1(λn+1I+A) −1. Two-point boundary value problems... 67 Substituting this into the previous equality, we get an − an+1 = (λnI +A)−1 ( λn sn − λn+1 sn+1 ) + (λn+1 − λn)(λnI +A)−1(λn+1I +A)−1 λn+1 sn+1 . (7) Using (β) and (α3), (α4), and also the equality λn+1 − λn = sn ( λn+1 sn+1 − λn sn ) + λn+1 sn+1 (sn+1 − sn), we get, from (7), ‖an − an+1‖ ≤ C n2 . Hence, using (3) from section 3, we conclude that the series (6) converges uniformly on t in [δ, γ]. Thus, v(t) has a continuous, on (0, T ), second derivative which is defined by (4). Now, using the formula A(λnI +A)−1 = I − λn(λnI +A)−1, we get, from (2), for 0 < t < T , Av(t) = ∞∑ n=1 λn(λnI +A)−1fnϕn(t)− ∞∑ n=1 fnϕn(t) = v′′(t)− f(t), which implies that v(t) is a solution of the equation (1) from section 2. � 6. The periodic boundary value conditions Consider a problem of the form (1), (2) from section 2 with periodic boundary value conditions d2v dt2 = Av + f(t), 0 < t < 2π, v(0)− v(2π) = 0, v′(0)− v′(2π) = 0. (1) 68 Y. Eidelman, Ya. Yakubov The corresponding operator L in (3) from section 2 has a complete, in L2(0, 2π), orthonormal system of eigenfunctions ϕn(t) = 1√ 2π eint, n = 0,±1,±2, . . . with eigenvalues λn = n2. The sequence sn in (α4) is defined by sn = in, n = 0,±1,±2, . . . . Assume that the operator A satisfies the condition (β). This means that the numbers −n2, n = 0, 1, 2, . . . are regular points of the operator A and the inequalities ‖n2(A+ n2I)−1‖ ≤M, n = 0, 1, 2, . . . (2) hold. Assume that the function f(t) in (1) satisfies the condition (γ0). We check that the condition (γ) holds. The inequalities ‖fnϕn(t)‖ ≤ C, n = 0,±1,±2, . . . , 0 ≤ t ≤ 2π are obvious. Integrating by parts in (1) from section 3, we get fn = 1√ 2π ∫ 2π 0 f(t)e−int dt = 1√ 2π ( i f(2π)− f(0) n + 1 in ∫ 2π 0 f ′(t)e−int dt ) . (3) >From here, using the fact that the functions f(t) and f ′(t) are bounded, we obtain the inequalities ‖fnϕ′n(t)‖ ≤ C, n = 0,±1,±2, . . . , 0 ≤ t ≤ 2π. So, (2) from section 3 has been proved. It remains to check (3) from section 3, i.e.,∥∥∥∥∥ n∑ k=−n ikfke ikt ∥∥∥∥∥ ≤ C, n = 0, 1, 2, . . . , 0 < δ ≤ t ≤ γ < 2π. (4) Set g(t) = f ′(t). The Fourier coefficients of the function g(t) are gk = 1√ 2π ∫ 2π 0 f ′(t)e−ikt dt, k = 0,±1,±2, . . . . Two-point boundary value problems... 69 The formula (3) implies ikfk = gk − f(2π)− f(0)√ 2π , k = 0,±1,±2, . . . and, therefore, n∑ k=−n ikfke ikt = n∑ k=−n gke ikt+ f(0)− f(2π)√ 2π n∑ k=−n eikt, n = 0, 1, 2, . . . . or ‖ n∑ k=−n ikfke ikt‖ ≤ ‖ n∑ k=−n gke ikt‖+ ‖f(0)− f(2π)‖√ 2π ∣∣∣∣∣ n∑ k=−n eikt ∣∣∣∣∣ . (5) The condition (γ0) implies that the Fourier series of the function g(t) converges to g(t), uniformly on any [δ, γ] ⊂ (0, 2π). Hence,∥∥∥∥∥ n∑ k=−n gke ikt ∥∥∥∥∥ ≤ C, 0 < δ ≤ t ≤ γ < 2π, n = 0, 1, 2, . . . . (6) Further, we have n∑ k=−n eikt = sin (2n+1)t 2 sin t 2 and, therefore,∣∣∣∣∣ n∑ k=−n eikt ∣∣∣∣∣ ≤ C, 0 < δ ≤ t ≤ γ < 2π. (7) >From the relations (5)-(7), the relations in (4) follow. Thus, for any operator A, satisfying the condition (2), and for any f(t), satisfying the condition (γ0), the problem (1), by Theorem 4, has a unique solution. 70 Y. Eidelman, Ya. Yakubov 7. The Dirichlet boundary value conditions Consider now a problem of the form (1), (2) from section 2 with Dirichlet boundary value conditions d2v dt2 = Av + f(t), 0 < t < π, v(0) = 0, v(π) = 0. (1) The corresponding operator L in (3) from section 2 has a complete, in L2(0, π), orthonormal system of eigenfunctions ϕn(t) =√ 2 π sinnt, n = 1, 2, . . . with eigenvalues λn = n2. The sequence sn in (α4) is defined by sn = n, n = 1, 2, . . . . Assume that the operator A satisfies the condition (β). This means that the numbers −n2, n = 1, 2, . . . are regular points of the operator A and the inequalities ‖n2(A+ n2I)−1‖ ≤M, n = 1, 2, . . . (2) hold. Assume that the function f(t) in (1) satisfies the condition (γ0). We check that the condition (γ) holds. Integrating by parts in (1) from section 3, we get fn = √ 2 π ∫ π 0 f(t) sinnt dt = √ 2 π (−f(π) cos(nπ) + f(0) n + 1 n ∫ π 0 f ′(t) cosnt dt ) . (3) >From (3), using the fact that the functions f(t) and f ′(t) are bounded, we obtain (2) from section 3. It remains to check (3) from section 3, i.e.,∥∥∥∥∥ n∑ k=1 kfkϕk(t) ∥∥∥∥∥ ≤ C, n = 1, 2, . . . , 0 < δ ≤ t ≤ γ < π. (4) Two-point boundary value problems... 71 The relation (3) implies that n∑ k=1 kfkϕk(t) = 2 π n∑ k=1 ( f(0)− f(π) cos kπ + ∫ π 0 f ′(s) cos ks ds ) sin kt, i.e., n∑ k=1 kfkϕk(t) = 2 π n∑ k=1 f(0) sin kt+ 2 π n∑ k=1 f(π)(−1)k+1 sin kt + 2 π ∫ π 0 f ′(s) n∑ k=1 sin kt cos ks ds. (5) Set Dn(t) = n∑ k=1 sin kt. (6) The formula n∑ k=1 sin kt = hn(t) sin t 2 , (7) with hn(t) = sin n+1 2 t sin nt 2 , implies |Dn(t)| ≤ C | sin t 2 | . (8) The first entry in (5) has the form 2 π n∑ k=1 f(0) sin kt = 2 π f(0)Dn(t) and, hence, the uniform boundedness of this entry on t ∈ [δ, γ] ⊂ (0, π), n = 1, 2, . . . follows from (8). The second entry in (5) has the 72 Y. Eidelman, Ya. Yakubov form 2 π n∑ k=1 f(π)(−1)k+1 sin kt = − 2 π f(π) n∑ k=1 sin(kt+ kπ) = − 2 π f(π)Dn(t+ π) and, using (8), we get ‖ 2 π n∑ k=1 f(π)(−1)k+1 sin kt‖ ≤ C | sin t+π 2 | = C | cos t2 | and, hence, the uniform boundedness of this entry on t ∈ [δ, γ], n = 1, 2, . . . follows. Finally, consider the third term in (5). We have 2 π ∫ π 0 f ′(s) n∑ k=1 sin kt cos ks ds = 1 π ∫ π 0 f ′(s)Dn(t+ s) ds + 1 π ∫ π 0 f ′(s)Dn(t− s) ds. (9) Using formula (7), we get Dn(t+ s) = hn(t+ s) sin t+s 2 . Here, it is clear that |hn(t+ s)| ≤ 1 and that 1/| sin t+ s 2 | ≤ C, 0 ≤ s ≤ π, 0 < δ ≤ t ≤ γ < π. Since f ′(t) is a bounded function, we conclude that the first term in (9) is uniformly bounded on t ∈ [δ, γ], n = 1, 2, . . . . Now, consider the second term. We have 1 π ∫ π 0 f ′(s)Dn(t− s) ds = 1 π ∫ π 0 (f ′(s)− f ′(t))Dn(t− s) ds + 1 π f ′(t) ∫ π 0 Dn(t− s) ds. (10) Two-point boundary value problems... 73 By the condition (γ0), we have ‖f ′(s)− f ′(t)‖ ≤ C|t− s|α, ∀t, s ∈ [0, π]. Using (8), we get |Dn(t− s)| ≤ C | t−s2 | , t 6= s. Thus, we conclude that ‖ 1 π ∫ π 0 (f ′(s)− f ′(t))Dn(t− s) ds‖ ≤ C. Since f ′(t) is bounded, it is enough to check the boundedness of the last integral in (10). Using (6), we get∫ π 0 Dn(t− s) ds = n∑ k=1 ∫ π 0 sin k(t− s) ds = n∑ k=1 cos(kt− kπ)− cos kt k = −2 p∑ m=0 cos(2m+ 1)t 2m+ 1 . On the other hand, ∑n−1 m=0 cos(2m + 1)t = sin 2nt 2 sin t . Then, limn→∞ ∑n−1 m=0 cos(2m+1)t· 1 2n−1 = 0, 0 < δ ≤ t ≤ γ < π. Therefore, by the Abel transform, the uniform convergence of ∑∞ m=0 cos(2m+1)t 2m+1 , 0 < δ ≤ t ≤ γ < π, follows from uniform convergence (on the same segment) of ∞∑ n=1 n−1∑ m=0 cos(2m+1)t· ( 1 2n− 1 − 1 2n+ 1 ) = ∞∑ n=1 sin 2nt (2n− 1)(2n+ 1) sin t which is true by the Weierstrass M -test. Thus, we conclude that ‖ ∫ π 0 Dn(t− s) ds‖ ≤ C, n = 1, 2, . . . , 0 < δ ≤ t ≤ γ < π, 74 Y. Eidelman, Ya. Yakubov which completes the proof of (4). So, for any operator A, satisfying the condition (2), and for any f(t), satisfying the condition (γ0), the problem (1), by Theorem 4, has a unique solution. Consider now the Dirichlet problem for the homogeneous equation with non-homogeneous boundary value conditions d2v dt2 = Av, 0 < t < π, v(0) = x0, v(π) = x1 (11) with x0, x1 ∈ D(A). By a standard way, the problem (11) is reduced to the problem (1) with f(t) = π−t π Ax0+ t πAx1. Obviously, the linear function f(t) satisfies condition (γ0). Лiтература [1] Arendt V., Bu S. The operator-valued Marcinkiewicz multiplier theorem and maximal regularity // Mathematische Zeitschrift. — 2002. — 240.— P. 311–343. [2] Favini A., Shakhmurov V., Yakubov Ya. Regular boundary value problems for complete second order elliptic differential-operator equations in UMD Banach spaces // Semigroup Forum. — 2009. — 79. — P. 22–54. [3] Favini A., Yakubov Ya. Regular boundary value problems for elliptic differential-operator equations of the fourth order in UMD Banach spaces// Scientiae Mathematicae Japonicae. — 2009. — 70. — P. 183– 204. [4] Favini A., Yakubov Ya. Irregular boundary value problems for second order elliptic differential-operator equations in UMD Banach spaces // Mathematische Annalen. — 2010. — 348. — P. 601–632. [5] Favini A., Yakubov Ya. Regular boundary value problems for ordi- nary differential-operator equations of higher order in UMD Banach spaces // Discrete and Continuous Dynamical Systems. — 2011. — 4, No. 3. — P. 595–614. Two-point boundary value problems... 75 [6] Gershtein L. M., Sobolevskii P. E. Coercive solvability of general boundary-value problems for second-order elliptic equations in Banach space // Differentsial’nye Uravneniya. — 1974. — 10, No. 11. — P. 2059–2061. [7] Gershtein L. M., Sobolevskii P. E. Coercive solvability of general boundary-value problems for second-order elliptic equations in Banach space. II // Differentsial’nye Uravneniya. —1975 — 11, No. 7. — P. 1335–1337. [8] Knyazyuk A. V. The Dirichlet problem for second-order differential equations with operator coefficients// Ukrain. Math. Zh. — 1985. — 37, No. 2. — P. 256–260. [9] Yakubov S., Yakubov Ya. Differential-Operator Equations. Ordinary and Partial Differential Equations. — Boca Raton: Chapman and Hall/CRC, 2000. — 568 p.
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spelling oai:trim.imath.kiev.ua:article-2072018-01-23T01:38:29Z Two-point boundary value problems for differential-operator equations Two-point boundary value problems for differential-operator equations Eidelman, Y. Yakubov, Ya. Eidelman, Y. Yakubov, Ya. We study general two-point boundary value problems for a non-homogeneous differential-operator equation of the second order with an unbounded linear operator in a Banach space. The main classical solvability condition is given in terms of the property of the resolvent of the operator at the points, which are opposite to the eigenvalues of the corresponding ordinary differential operator. At the end of the paper, two particular types of boundary value conditions are treated: periodic and Dirichlet. We study general two-point boundary value problems for a non-homogeneous differential-operator equation of the second order with an unbounded linear operator in a Banach space. The main classical solvability condition is given in terms of the property of the resolvent of the operator at the points, which are opposite to the eigenvalues of the corresponding ordinary differential operator. At the end of the paper, two particular types of boundary value conditions are treated: periodic and Dirichlet. Інститут математики НАН України 2016-05-16 Article Article application/pdf https://trim.imath.kiev.ua/index.php/trim/article/view/207 Transactions of Institute of Mathematics, the NAS of Ukraine; Vol. 13 No. 1 (2016): Differential equations and related problems of analysis; 58-75 Сборник Трудов Института математики НАН Украины; Том 13 № 1 (2016): Диференціальні рівняння і суміжні питання аналізу; 58-75 Збірник Праць Інституту математики НАН України; Том 13 № 1 (2016): Диференціальні рівняння і суміжні питання аналізу; 58-75 3083-7529 1815-2910 uk en https://trim.imath.kiev.ua/index.php/trim/article/view/207/184 Авторське право (c) 2016 Y. Eidelman, Ya. Yakubov
spellingShingle Eidelman, Y.
Yakubov, Ya.
Eidelman, Y.
Yakubov, Ya.
Two-point boundary value problems for differential-operator equations
title Two-point boundary value problems for differential-operator equations
title_alt Two-point boundary value problems for differential-operator equations
title_full Two-point boundary value problems for differential-operator equations
title_fullStr Two-point boundary value problems for differential-operator equations
title_full_unstemmed Two-point boundary value problems for differential-operator equations
title_short Two-point boundary value problems for differential-operator equations
title_sort two-point boundary value problems for differential-operator equations
url https://trim.imath.kiev.ua/index.php/trim/article/view/207
work_keys_str_mv AT eidelmany twopointboundaryvalueproblemsfordifferentialoperatorequations
AT yakubovya twopointboundaryvalueproblemsfordifferentialoperatorequations
AT eidelmany twopointboundaryvalueproblemsfordifferentialoperatorequations
AT yakubovya twopointboundaryvalueproblemsfordifferentialoperatorequations