On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)

On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)

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Bibliographic Details
Date:2016
Main Authors: D. Şimşek, F. Abdullayev
Format: Article
Language:English
Published: 2016
Series:Ukrainian Mathematical Bulletin
Online Access:http://jnas.nbuv.gov.ua/article/UJRN-0000743713
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Journal Title:Library portal of National Academy of Sciences of Ukraine | LibNAS

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Library portal of National Academy of Sciences of Ukraine | LibNAS
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spelling open-sciencenbuvgovua-528332024-02-29T13:08:31Z On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0) D. Şimşek F. Abdullayev 1810-3200 2016 en Ukrainian Mathematical Bulletin http://jnas.nbuv.gov.ua/article/UJRN-0000743713 Article
institution Library portal of National Academy of Sciences of Ukraine | LibNAS
collection Open-Science
language English
series Ukrainian Mathematical Bulletin
spellingShingle Ukrainian Mathematical Bulletin
D. Şimşek
F. Abdullayev
On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)
format Article
author D. Şimşek
F. Abdullayev
author_facet D. Şimşek
F. Abdullayev
author_sort D. Şimşek
title On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)
title_short On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)
title_full On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)
title_fullStr On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)
title_full_unstemmed On the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)
title_sort on the recursive sequence x_(n+1)=(x_(n-(4k+3)))(1+_(t=0)
publishDate 2016
url http://jnas.nbuv.gov.ua/article/UJRN-0000743713
work_keys_str_mv AT dsimsek ontherecursivesequencexn1xn4k31t0
AT fabdullayev ontherecursivesequencexn1xn4k31t0
first_indexed 2025-07-17T23:12:51Z
last_indexed 2025-07-17T23:12:51Z
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