New Inequalities for the $p$-Angular Distance in Normed Spaces with Applications

For nonzero vectors $x$ and $y$ in the normed linear space $(X, ‖ ⋅ ‖)$, we can define the $p$-angular distance by $${\alpha}_p\left[x,y\right]:=\left\Vert {\left\Vert x\right\Vert}^{p-1}x-{\left\Vert y\right\Vert}^{p-1}y\right\Vert .$$ We show (among other results) that, for $p ≥ 2$, $$\begin{array...

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Datum:2015
Hauptverfasser: Dragomir, S. S., Драгомир, С. С.
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Veröffentlicht: Institute of Mathematics, NAS of Ukraine 2015
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Ukrains’kyi Matematychnyi Zhurnal
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author Dragomir, S. S.
Драгомир, С. С.
author_facet Dragomir, S. S.
Драгомир, С. С.
author_sort Dragomir, S. S.
baseUrl_str https://umj.imath.kiev.ua/index.php/umj/oai
collection OJS
datestamp_date 2019-12-05T09:47:39Z
description For nonzero vectors $x$ and $y$ in the normed linear space $(X, ‖ ⋅ ‖)$, we can define the $p$-angular distance by $${\alpha}_p\left[x,y\right]:=\left\Vert {\left\Vert x\right\Vert}^{p-1}x-{\left\Vert y\right\Vert}^{p-1}y\right\Vert .$$ We show (among other results) that, for $p ≥ 2$, $$\begin{array}{l}{\alpha}_p\left[x,y\right]\le p\left\Vert y-x\right\Vert {\displaystyle \underset{0}{\overset{1}{\int }}{\left\Vert \left(1-t\right)x+ty\right\Vert}^{p-1}dt}\hfill \\ {}\kern3.36em \le p\left\Vert y-x\right\Vert \left[\frac{{\left\Vert x\right\Vert}^{p-1}+{\left\Vert y\right\Vert}^{p-1}}{2}+{\left\Vert \frac{x+y}{2}\right\Vert}^{p-1}\right]\hfill \\ {}\kern3.36em \le p\left\Vert y-x\right\Vert \frac{{\left\Vert x\right\Vert}^{p-1}+{\left\Vert y\right\Vert}^{p-1}}{2}\le p\left\Vert y-x\right\Vert {\left[ \max \left\{\left\Vert x\right\Vert, \left\Vert y\right\Vert \right\}\right]}^{p-1},\hfill \end{array}$$, for any $x, y ∈ X$. This improves a result of Maligranda from [“Simple norm inequalities,” Amer. Math. Month., 113, 256–260 (2006)] who proved the inequality between the first and last terms in the estimation presented above. The applications to functions f defined by power series in estimating a more general “distance” $‖f(‖x‖)x − f(‖y‖)y‖$ for some $x, y ∈ X$ are also presented.
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fulltext UDC 517.5 S. S. Dragomir (College Eng. and Sci., Victoria Univ., Melbourne City, Australia; School Comput. and Appl. Math., Univ. Witwatersrand, Johannesburg, South Africa) NEW INEQUALITIES FOR THE p-ANGULAR DISTANCE IN NORMED SPACES WITH APPLICATIONS НОВI НЕРIВНОСТI ДЛЯ p-КУТОВОЇ ВIДСТАНI В НОРМОВАНИХ ПРОСТОРАХ ТА ЇХ ЗАСТОСУВАННЯ For nonzero vectors x and y in the normed linear space (X, ‖ · ‖) , we can define the p-angular distance by αp[x, y] := ∥∥‖x‖p−1x− ‖y‖p−1y ∥∥ . We show (among other results) that, for p ≥ 2, αp[x, y] ≤ p‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖p−1 dt ≤ ≤ p‖y − x‖ [ ‖x‖p−1 + ‖y‖p−1 2 + ∥∥∥x+ y 2 ∥∥∥p−1 ] ≤ ≤ p‖y − x‖‖x‖ p−1 + ‖y‖p−1 2 ≤ p‖y − x‖ [max {‖x‖, ‖y‖}]p−1 , for any x, y ∈ X. This improves a result of Maligranda from [Simple norm inequalities // Amer. Math. Month. – 2006. – 113. – P. 256 – 260] who proved the inequality between the first and last terms in the estimation presented above. The applications to functions f defined by power series in estimating a more general “distance” ‖f (‖x‖)x− f (‖y‖) y‖ for some x, y ∈ X are also presented. Для ненульових векторiв x та y в лiнiйному нормованому просторi (X, ‖ · ‖) можна визначити p-кутову вiдстань таким чином: αp[x, y] := ∥∥‖x‖p−1x− ‖y‖p−1y ∥∥ . У роботi, зокрема, показано, що αp[x, y] ≤ p‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖p−1 dt ≤ ≤ p‖y − x‖ [ ‖x‖p−1 + ‖y‖p−1 2 + ∥∥∥x+ y 2 ∥∥∥p−1 ] ≤ ≤ p‖y − x‖‖x‖ p−1 + ‖y‖p−1 2 ≤ p‖y − x‖ [max {‖x‖, ‖y‖}]p−1 для p ≥ 2 i будь-яких x, y ∈ X. Це покращує результат Малiгранди [Simple norm inequalities // Amer. Math. Month. – 2006. – 113. – P. 256 – 260], який встановив нерiвнiсть мiж першим та останнiм членами вказаної оцiнки. Також наведено застосування для функцiй f, визначених степеневими рядами при оцiнюваннi бiльш загальної „вiдстанi” ‖f (‖x‖)x− f (‖y‖) y‖ для деяких x, y ∈ X. 1. Introduction. Following [3, p. 403] or [12], for nonzero vectors x and y in the normed linear space (X, ‖ · ‖) we define the angular distance α[x, y] between x and y by α[x, y] := ∥∥∥∥ x ‖x‖ − y ‖y‖ ∥∥∥∥ . c© S. S. DRAGOMIR, 2015 ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 19 20 S. S. DRAGOMIR In 1958, Massera and Schäffer [12] (Lemma 5.1) showed that α[x, y] ≤ 2‖x− y‖ max {‖x‖, ‖y‖} , (1.1) which is better than the Dunkl – Williams inequality [7] α[x, y] ≤ 4‖x− y‖ ‖x‖+ ‖y‖ . (1.2) We notice that the Massera – Schäffer inequality was rediscovered by Gurarĭı in [8] (see also [13, p. 516]). In [11], Maligranda obtained the double inequality ‖x− y‖ − |‖x‖ − ‖y‖| min {‖x‖, ‖y‖} ≤ α[x, y] ≤ ‖x− y‖+ |‖x‖ − ‖y‖| max {‖x‖, ‖y‖} . (1.3) The second inequality in (1.3) is better than Massera – Schäffer’s inequality (1.1). In the recent paper [11], L. Maligranda has also considered the p-angular distance αp[x, y] := ∥∥‖x‖p−1x− ‖y‖p−1y∥∥ between the vectors x and y in the normed linear space (X, ‖ · ‖) over the real or complex number field K and showed that αp[x, y] ≤ ‖x− y‖  (2− p) max {‖x‖p, ‖y‖p} max {‖x‖ , ‖y‖} if p ∈ (−∞, 0) and x, y 6= 0, (2− p) 1 [max {‖x‖, ‖y‖}]1−p if p ∈ [0, 1] and x, y 6= 0, p [max {‖x‖, ‖y‖}]p−1 if p ∈ (1,∞). (1.4) The constants 2− p and p in (1.1) are best possible in the sense that they cannot be replaced by smaller quantities. As pointed out in [11], the inequality (1.1) for p ∈ [1,∞) is better than the Bourbaki inequality obtained in 1965 [2, p. 257] (see also [13, p. 516]): αp[x, y] ≤ 3p‖x− y‖ [‖x‖+ ‖y‖]p−1 , x, y ∈ X. (1.5) The following results concerning upper bounds for the p-angular distance have been obtained by the author in [5]: αp[x, y] ≤ ≤  ‖x− y‖ [ max{‖x‖, ‖y‖} ]p−1 + ∣∣‖x‖p−1 − ‖y‖p−1∣∣min{‖x‖, ‖y‖} if p ∈ (1,∞), ‖x− y‖ [min {‖x‖ , ‖y‖}]1−p + ∣∣‖x‖1−p − ‖y‖1−p∣∣min { ‖x‖p ‖y‖1−p , ‖y‖p ‖x‖1−p } if p ∈ [0, 1], ‖x− y‖ [min {‖x‖ , ‖y‖}]1−p + ∣∣‖x‖1−p − ‖y‖1−p∣∣ max { ‖x‖−p ‖y‖1−p , ‖y‖−p‖x‖1−p } if p ∈ (−∞, 0), (1.6) ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 NEW INEQUALITIES FOR THE p-ANGULAR DISTANCE IN NORMED SPACES WITH APPLICATIONS 21 and αp[x, y] ≤ ≤  ‖x− y‖ [ min {‖x‖, ‖y‖} ]p−1 + ∣∣∣‖x‖p−1 − ‖y‖p−1∣∣∣max {‖x‖, ‖y‖} if p ∈ (1,∞), ‖x− y‖ [max {‖x‖ , ‖y‖}]1−p + ∣∣‖x‖1−p − ‖y‖1−p∣∣max { ‖x‖p ‖y‖1−p , ‖y‖p ‖x‖1−p } if p ∈ [0, 1], ‖x− y‖ [max {‖x‖, ‖y‖}]1−p + ∣∣‖x‖1−p − ‖y‖1−p∣∣ min {‖x‖−p‖y‖1−p, ‖y‖−p‖x‖1−p} if p ∈ (−∞, 0), (1.7) for any two nonzero vectors x, y in the normed linear space (X, ‖ · ‖). The upper bounds for αp[x, y] provided by (1.4), (1.6) and (1.7) have been compared in [5] to conclude that some of the later ones are better in certain cases. The details are omitted here. The following result which provides a lower bound for the p-angular distance was stated without a proof by Gurarĭı in [8] (see also [13, p. 516]): 2−p‖x− y‖p ≤ αp[x, y], (1.8) where p ∈ [1,∞) and x, y ∈ X. The proof of the inequality (1.8) is still an open question for the author. Finally, we recall the results of G. N. Hile from [4]: αp[x, y] ≤ ‖x‖ p − ‖y‖p ‖x‖ − ‖y‖ ‖x− y‖, (1.9) for p ∈ [1,∞) and x, y ∈ X with ‖x‖ 6= ‖y‖, and α−p−1[x, y] ≤ ‖x‖ p − ‖y‖p ‖x‖ − ‖y‖ ‖x− y‖ ‖x‖p ‖y‖p , (1.10) for p ∈ [1,∞) and x, y ∈ X \ {0} with ‖x‖ 6= ‖y‖. 2. Integral bounds for p-angular distance. The following result holds. Theorem 2.1. Let (X; ‖ · ‖) be a normed linear space and p ≥ 1. Then for any x, y ∈ X we have the inequality αp[x, y] ≤ p‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖p−1 dt. (2.1) If the vectors x, y ∈ X are linearly independent and p < 1, then we have the inequality αp[x, y] ≤ (2− p) ‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖p−1 dt. (2.2) ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 22 S. S. DRAGOMIR Proof. Assume that x 6= y. For p ≥ 2, consider the function fp : [0, 1] → [0,∞) given by fp(t) = ‖(1− t)x+ ty‖p−1 . The function fp is convex on the interval [0, 1] for all p ≥ 2. Therefore the lateral derivatives f ′p+ and f ′p− exist on each point of the interval [0, 1) and (0, 1], respectively, and they are equal except a countably number of points in the interval (0, 1). The function fp is absolutely continuos on [0, 1], the derivative f ′p exists almost everywhere on [0, 1] and (see, for instance, [14], Chapter IV) f ′p(t) = (p− 1) ‖(1− t)x+ ty‖p−2 τ+(−) ((1− t)x+ ty, y − x) (2.3) almost everywhere on [0, 1], where the tangent functional τ+(−) is defined by τ+(−) (u, v) :=  lims→0+(−) ‖u+ sv‖ − ‖u‖ s if u 6= 0, + (−) ‖v‖ if u = 0. (2.4) Now, if we consider the vector valued function gp : [0, 1]→ X given by gp(t) := fp(t) [(1− t)x+ ty] then we observe that gp is strongly differentiable almost everywhere on [0, 1] and (see, for instance, [1], Chapter 1) g′p(t) = f ′p(t) [(1− t)x+ ty] + fp(t) (y − x) = = (p− 1) ‖(1− t)x+ ty‖p−2 τ+(−) ((1− t)x+ ty, y − x)× × [(1− t)x+ ty] + ‖(1− t)x+ ty‖p−1 (y − x) for almost every t ∈ [0, 1]. Since for any u, v ∈ H with u 6= 0 we have∣∣τ+(−) (u, v) ∣∣ ≤ ‖v‖ , then ∥∥g′p(t)∥∥ ≤ (p− 1) ‖(1− t)x+ ty‖p−1 ∣∣τ+(−) ((1− t)x+ ty, y − x) ∣∣+ + ‖(1− t)x+ ty‖p−1 ‖y − x‖ ≤ ≤ (p− 1) ‖(1− t)x+ ty‖p−1 ‖y − x‖+ ‖(1− t)x+ ty‖p−1 ‖y − x‖ = = p ‖(1− t)x+ ty‖p−1 ‖y − x‖ for almost every t ∈ [0, 1]. By the norm inequality for the vector-valued integral we have (see, for instance, [1], Chapter 1)∥∥‖y‖p−1y − ‖x‖p−1x∥∥ = ‖gp (1)− gp (0)‖ = ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 NEW INEQUALITIES FOR THE p-ANGULAR DISTANCE IN NORMED SPACES WITH APPLICATIONS 23 = ∥∥∥∥∥∥ 1∫ 0 g′p(t)dt ∥∥∥∥∥∥ ≤ 1∫ 0 ∥∥g′p(t)∥∥ dt ≤ ≤ p‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖p−1 dt and the proof of (2.1) is complete. Let p ∈ (1, 2). The function fp : [0, 1] → [0,∞) given by fp(t) = ‖(1− t)x+ ty‖p−1 is absolutely continuous on [0, 1] and the equality (2.3) also holds almost everywhere on [0, 1]. The above argument can then be extended to this case as well and the inequality (2.1) also holds. If the vectors x, y ∈ X are linearly independent and p < 1, then ‖(1− t)x+ ty‖ > 0 for any t ∈ [0, 1] and the function hp : [0, 1] → [0,∞) given by hp(t) = ‖(1− t)x+ ty‖p−1 is absolutely continuous on [0, 1] and h′p(t) = (p− 1) ‖(1− t)x+ ty‖p−2 τ+(−) ((1− t)x+ ty, y − x) (2.5) almost everywhere on [0, 1]. If we consider the vector valued function mp : [0, 1]→ X given by mp(t) := hp(t) [ (1− t)x+ ty ] , then we observe that mp is strongly differentiable almost everywhere on [0, 1] and m′p(t) = h′p(t) [(1− t)x+ ty] + hp(t) (y − x) = = (p− 1) ‖(1− t)x+ ty‖p−2 τ+(−) ((1− t)x+ ty, y − x)× × [(1− t)x+ ty] + ‖(1− t)x+ ty‖p−1 (y − x) for almost every t ∈ [0, 1]. As above we have∥∥m′p(t)∥∥ ≤ (1− p) ‖(1− t)x+ ty‖p−1 ‖y − x‖+ ‖(1− t)x+ ty‖p−1 ‖y − x‖ = = (2− p) ‖(1− t)x+ ty‖p−1 ‖y − x‖ for almost every t ∈ [0, 1], which implies the desired inequality (2.2). Theorem 2.1 is proved. Remark 2.1. If the vectors x and y are linearly dependent and y = λx with λ ∈ K, then the p-angular distance between x and y reduces to αp[x, y] = ‖x‖p ∣∣∣1− |λ|p−1 λ∣∣∣ = ‖x‖pβp [1, λ] . The study of βp [1, λ] = ∣∣1− |λ∣∣p−1λ∣∣ with λ ∈ K may be done in a similar way, however the details are omitted. ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 24 S. S. DRAGOMIR Remark 2.2. If p ≥ 2, then the function fp : [0, 1]→ [0,∞) given by fp(t) = ‖(1− t)x+ ty‖p−1 is convex and by the Hermite – Hadamard type inequality for the convex function g : [a, b]→ R 1 b− a b∫ a g (s) ds ≤ 1 2 [ g (a) + g (b) 2 + g ( a+ b 2 )] ≤ ≤ g (a) + g (b) 2 ≤ max {g (a) , g (b)} (2.6) we have the following chain of inequalities: αp[x, y] ≤ p‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖p−1 dt ≤ ≤ p‖y − x‖ [ ‖x‖p−1 + ‖y‖p−1 2 + ∥∥∥∥x+ y 2 ∥∥∥∥p−1 ] ≤ ≤ p‖y − x‖‖x‖ p−1 + ‖y‖p−1 2 ≤ p‖y − x‖ [max {‖x‖, ‖y‖}]p−1 , (2.7) which provides a refinement of Maligranda’s inequality (1.4). If p ≥ 1 and since, by the triangle inequality we have ‖(1− t)x+ ty‖ ≤ (1− t)‖x‖+ t‖y‖, then ‖(1− t)x+ ty‖p−1 ≤ [(1− t)‖x‖+ t‖y‖]p−1 for any t ∈ [0, 1]. Integrating on [0, 1] we get 1∫ 0 ‖(1− t)x+ ty‖p−1 dt ≤ 1∫ 0 [(1− t)‖x‖+ t ‖y‖]p−1 dt = 1 p ‖y‖p − ‖x‖p ‖y‖ − ‖x‖ if ‖y‖ 6= ‖x‖, and by (2.1) we obtain the chain of inequalities αp[x, y] ≤ p‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖p−1 dt ≤ ‖y‖ p − ‖x‖p ‖y‖ − ‖x‖ ‖y − x‖, (2.8) which provides a refinement of Hile’s inequality (1.9). For p ≥ 2, by the Hermite – Hadamard’s type inequalities (2.6) we also have 1 p ‖y‖p − ‖x‖p ‖y‖ − ‖x‖ = 1∫ 0 [(1− t)‖x‖+ t‖y‖]p−1 dt ≤ ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 NEW INEQUALITIES FOR THE p-ANGULAR DISTANCE IN NORMED SPACES WITH APPLICATIONS 25 ≤ 1 2 [( ‖x‖+ ‖y‖ 2 )p−1 + ‖x‖p−1 + ‖y‖p−1 2 ] ≤ ≤ ‖x‖ p−1 + ‖y‖p−1 2 ≤ [max {‖x‖, ‖y‖}]p−1 which implies the following sequence of inequalities: αp[x, y] ≤ p‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖p−1 dt ≤ ≤ ‖y‖ p − ‖x‖p ‖y‖ − ‖x‖ ‖y − x‖ ≤ ≤ 1 2 p‖y − x‖ [( ‖x‖+ ‖y‖ 2 )p−1 + ‖x‖p−1 + ‖y‖p−1 2 ] ≤ ≤ p‖y − x‖‖x‖ p−1 + ‖y‖p−1 2 ≤ p‖y − x‖[max {‖x‖, ‖y‖}]p−1 (2.9) for ‖y‖ 6= ‖x‖ and p ≥ 2. In particular, the inequality (2.9) shows that in the case p ≥ 2, Hile’s inequality (1.9) is better than Maligranda’s inequality (1.4). Remark 2.3. The case p = 0 is of interest, since by (2.2) we have the following upper bound for the angular distance α[x, y]: α[x, y] ≤ 2‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖−1 dt, (2.10) provided the vectors x and y are linearly independent. Since for any t ∈ [0, 1] ‖(1− t)x+ ty‖ = ‖x− t (x− y)‖ ≥ |‖x‖ − t ‖x− y‖| ≥ ‖x‖ − t‖x− y‖ ≥ ‖x‖ and similarly ‖(1− t)x+ ty‖ ≥ ‖y‖, then we have ‖(1− t)x+ ty‖ ≥ max {‖x‖, ‖y‖} , which implies that 1∫ 0 ‖(1− t)x+ ty‖−1 dt ≤ 1 max {‖x‖, ‖y‖} . (2.11) Therefore, we have the following refinement of the Massera – Schäffer’s inequality (1.1): α[x, y] ≤ 2‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖−1 dt ≤ 2‖y − x‖ max {‖x‖, ‖y‖} . ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 26 S. S. DRAGOMIR Remark 2.4. In [9], the authors introduced the concept of p-HH-norm on the Cartesian product of two copies of a normed space, namely ‖(x, y)‖p−HH :=  1∫ 0 ‖(1− t)x+ ty‖p dt 1/p , where (x, y) ∈ X ×X := X2 and p ≥ 1. They showed that ‖ · ‖p−HH is a norm on X2 equivalent with the usual p-norms ‖(x, y)‖p := (‖x‖p + ‖y‖p)1/p . They also showed that completeness, reflexivity, smoothness, strict convexity etc. is inherited by X2 with this norm. In [10] the authors proved the following interesting lower bound for ‖(x, y)‖p−HH : ( ‖x‖p + ‖y‖p 2(p+ 1) )1/p ≤ ‖(x, y)‖p−HH (2.12) for any (x, y) ∈ X2 and p ≥ 1. Now, we observe that, by (2.1) we also have αp+1[x, y] ≤ (p+ 1) ‖y − x‖ ‖(x, y)‖pp−HH (2.13) for any (x, y) ∈ X2 and p ≥ 1. For x 6= y this is equivalent with ( ‖‖x‖px− ‖y‖p y‖ (p+ 1)‖y − x‖ )1/p ≤ ‖(x, y)‖p−HH , (2.14) where p ≥ 1. It is natural to ask which lower bound from (2.12) and (2.14) for the p-HH-norm is better? If we take X = C, ‖ · ‖ = |·| and p = 2, then by plotting the difference d given by d(x, y) :=  ∣∣∣|x|2 x− |y|2 y∣∣∣ 3 |y − x| 1/2 −( |x|2 + |y|2 6 )1/2 for x, y ∈ R and x 6= y, we observe that d is nonnegative, showing that the new bound (2.14) is better than (2.12). The plot is depicted in Figure as follows: ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 NEW INEQUALITIES FOR THE p-ANGULAR DISTANCE IN NORMED SPACES WITH APPLICATIONS 27 8 S.S. DRAGOMIR 1;2 y 0.0-2-4 -2 -4 0 0 x 4 42 2 z 1.0 0.5 1.5 2.0 Figure 1: The variation of d in the box (x; y) 2 [4; 4] [4; 4] : Problem 1. Is the inequality (2.15) kxkp + kykp 2  kkxkp x kykp yk ky  xk true for any (x; y) 2 X2 with x 6= y and p  1? 3. Applications for Power Series For power series f (z) = P1 n=0 anz n with complex coe¢cients we can naturally construct another power series which have as coe¢cients the absolute values of the coe¢cient of the original series, namely, fa (z) := P1 n=0 janj z n . It is obvious that this new power series have the same radius of convergence as the original series, and that if all coe¢cients an  0; then fa = f . As some natural examples that are useful for applications, we can point out that, if f (z) = 1X n=1 (1)n n zn = ln 1 1 + z ; z 2 D (0; 1) ;(3.1) g (z) = 1X n=0 (1)n (2n)! z2n = cos z; z 2 C; h (z) = 1X n=0 (1)n (2n+ 1)! z2n+1 = sin z; z 2 C; l (z) = 1X n=0 (1)n zn = 1 1 + z ; z 2 D (0; 1) ; The variation of d in the box (x, y) ∈ [−4, 4]× [−4, 4]. Problem 2.1. Is the inequality ‖x‖p + ‖y‖p 2 ≤ ∥∥‖x‖px− ‖y‖py∥∥ ‖y − x‖ (2.15) true for any (x, y) ∈ X2 with x 6= y and p ≥ 1? 3. Applications for power series. For power series f(z) = ∑∞ n=0 anz n with complex coefficients we can naturally construct another power series which have as coefficients the absolute values of the coefficient of the original series, namely, fa(z) := ∑∞ n=0 |an| zn. It is obvious that this new power series have the same radius of convergence as the original series, and that if all coefficients an ≥ 0, then fa = f . As some natural examples that are useful for applications, we can point out that, if f(z) = ∞∑ n=1 (−1)n n zn = ln 1 1 + z , z ∈ D(0, 1), g(z) = ∞∑ n=0 (−1)n (2n)! z2n = cos z, z ∈ C, h(z) = ∞∑ n=0 (−1)n (2n+ 1)! z2n+1 = sin z, z ∈ C, l(z) = ∞∑ n=0 (−1)nzn = 1 1 + z , z ∈ D(0, 1), (3.1) then the corresponding functions constructed by the use of the absolute values of the coefficients are ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 28 S. S. DRAGOMIR fa(z) = ∞∑ n=1 1 n zn = ln 1 1− z , z ∈ D(0, 1), ga(z) = ∞∑ n=0 1 (2n)! z2n = cosh z, z ∈ C, ha(z) = ∞∑ n=0 1 (2n+ 1)! z2n+1 = sinh z, z ∈ C, la(z) = ∞∑ n=0 zn = 1 1− z , z ∈ D(0, 1). (3.2) Other important examples of functions as power series representations with nonnegative coefficients are: exp(z) = ∞∑ n=0 1 n! zn, z ∈ C, 1 2 ln ( 1 + z 1− z ) = ∞∑ n=1 1 2n− 1 z2n−1, z ∈ D(0, 1), sin−1(z) = ∞∑ n=0 Γ ( n+ 1 2 ) √ π(2n+ 1)n! z2n+1, z ∈ D (0, 1) , tanh−1(z) = ∞∑ n=1 1 2n− 1 z2n−1, z ∈ D(0, 1), 2F1(α, β, γ, z) = ∞∑ n=0 Γ (n+ α) Γ(n+ β)Γ(γ) n!Γ(α)Γ(β)Γ(n+ γ) zn, α, β, γ > 0, z ∈ D(0, 1), (3.3) where Γ is Gamma function. Theorem 3.1. Let f(z) = ∑∞ n=0 anz n be a function defined by power series with complex coefficients and convergent on the open disk D(0, R) ⊂ C, R > 0. If (X; ‖ · ‖) is a normed linear space and x, y ∈ X with ‖x‖, ‖y‖ < R, then ‖f (‖x‖)x− f (‖y‖) y‖ ≤ ≤ ‖y − x‖ 1∫ 0 [ fa (‖(1− t)x+ ty‖) + ‖(1− t)x+ ty‖ f ′a (‖(1− t)x+ ty‖) ] dt. (3.4) Proof. From the inequality (2.1) for p = n+ 1, n a natural number with n ≥ 1, we have ‖‖x‖nx− ‖y‖ny‖ ≤ (n+ 1)‖y − x‖ 1∫ 0 ‖(1− t)x+ ty‖n dt. (3.5) ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 NEW INEQUALITIES FOR THE p-ANGULAR DISTANCE IN NORMED SPACES WITH APPLICATIONS 29 We notice that the above inequality also holds for n = 0, reducing to an equality. Let m ≥ 1. Then we have, by the generalized triangle inequality and by (3.5), that∥∥∥∥∥ ( m∑ n=0 an‖x‖n ) x− ( m∑ n=0 an‖y‖n ) y ∥∥∥∥∥ ≤ ≤ m∑ n=0 |an| ‖‖x‖n x− ‖y‖ny‖ ≤ ≤ ‖y − x‖ m∑ n=0 (n+ 1) |an| 1∫ 0 ‖(1− t)x+ ty‖n dt = = ‖y − x‖ 1∫ 0 ( m∑ n=0 (n+ 1) |an| ‖(1− t)x+ ty‖n ) dt. (3.6) Since ‖x‖, ‖y‖ < R the series ∞∑ n=0 an‖x‖n, ∞∑ n=0 an‖y‖n and ∞∑ n=0 (n+ 1) |an| ‖(1− t)x+ ty‖n are convergent. Moreover, we obtain ∞∑ n=0 an‖x‖n = f (‖x‖) , ∞∑ n=0 an‖y‖n = f (‖y‖) and ∞∑ n=0 (n+ 1) |an| ‖(1− t)x+ ty‖n = = ∞∑ n=0 |an| ‖(1− t)x+ ty‖n + ∞∑ n=0 n |an| ‖(1− t)x+ ty‖n = = fa (‖(1− t)x+ ty‖) + ‖(1− t)x+ ty‖ f ′a (‖(1− t)x+ ty‖) for any ‖x‖, ‖y‖ < R. Taking the limit over m→∞ in (3.6) we get the desired result (3.4). Theorem 3.1 is proved. Remark 3.1. If we take f(z) := exp(z) = ∑∞ n=0 1 n! zn then we have from (3.4) the following inequality: ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 30 S. S. DRAGOMIR ‖exp (‖x‖)x− exp (‖y‖)y‖ ≤ ≤ ‖y − x‖ 1∫ 0 exp (‖(1− t)x+ ty‖) (1 + ‖(1− t)x+ ty‖) dt (3.7) for any x, y ∈ X. If we apply the inequality (3.4) for the functions f(z) := 1 1− z = ∑∞ n=0 zn and f(z) := := 1 1 + z = ∑∞ n=0 (−1)nzn, then we have ∥∥∥∥ x 1± ‖x‖ − y 1± ‖y‖ ∥∥∥∥ ≤ ‖y − x‖ 1∫ 0 dt (1− ‖(1− t)x+ ty‖)2 (3.8) for any x, y ∈ X with ‖x‖, ‖y‖ < 1. Utilising the Hile’s inequality, we can also prove the following divided difference inequality: Proposition 3.1. Let f(z) = ∑∞ n=0 anz n be a function defined by power series with complex coefficients and convergent on the open disk D(0, R) ⊂ C, R > 0. If (X; ‖ · ‖) is a normed linear space and x, y ∈ X with ‖x‖, ‖y‖ < R and ‖x‖ 6= ‖y‖, then ‖f (‖x‖)x− f (‖y‖) y‖ ‖y − x‖ ≤ fa (‖x‖) ‖x‖ − fa (‖y‖) ‖y‖ ‖x‖ − ‖y‖ . (3.9) Proof. The proof goes along the line of the one from Theorem 3.1 by utilizing Hile’s inequal- ity (1.9) ‖‖x‖nx− ‖y‖ny‖ ‖y − x‖ ≤ ‖x‖ n+1 − ‖y‖n+1 ‖x‖ − ‖y‖ for any n a natural number. Remark 3.2. If we write the inequality (3.9) for the exponential function, then we get ‖exp (‖x‖)x− exp (‖y‖) y‖ ‖y − x‖ ≤ exp (‖x‖) ‖x‖ − exp (‖y‖) ‖y‖ ‖x‖ − ‖y‖ for any x, y ∈ X with ‖x‖ 6= ‖y‖ . If we apply the inequality (3.9) for the functions f(z) := 1 1− z and f(z) := 1 1 + z , then we get∥∥∥∥ x 1± ‖x‖ − y 1± ‖y‖ ∥∥∥∥ ≤ ‖y − x‖ (1− ‖x‖) (1− ‖y‖) for any x, y ∈ X with ‖x‖ 6= ‖y‖ and ‖x‖, ‖y‖ < 1. 1. Arendt W., Batty C. J. K., Hieber M., Neubrander F. Vector-valued Laplace transforms and Cauchy problems. – Second ed. // Monogr. Math. – Basel: Birkhäuser / Springer Basel AG, 2011. – 96. – xii+539 p. 2. Bourbaki N. Integration. – Paris: Herman, 1965. 3. Clarkson J. A. Uniform convex spaces // Trans. Amer. Math. Soc. – 1936. – 40. – P. 396 – 414. 4. Hile G. N. Entire solutions of linear elliptic equations with Laplacian principal part // Pacif. J. Math. – 1976. – 62. – P. 124 – 140. ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1 NEW INEQUALITIES FOR THE p-ANGULAR DISTANCE IN NORMED SPACES WITH APPLICATIONS 31 5. Dragomir S. S. Inequalities for the p-angular distance in normed linear spaces // Math. Inequal. Appl. – 2009. – 12, № 2. – P. 391 – 401. 6. Dragomir S. S., Pearce C. E. M. Selected topics on Hermite – Hadamard inequalities and applications // RGMIA Monogr. – 2000. [Online http://rgmia.org/monographs/hermite_hadamard.html]. 7. Dunkl C. F., Williams K. S. A simple norm inequality // Amer. Math. Month. – 1964. – 71. – P. 53 – 54. 8. Gurariı̆ V. I. Strengthening the Dunkl – Williams inequality on the norms of elements of Banach spaces (in Ukrainian) // Dop. Akad. Nauk Ukrain. RSR. – 1966. – 1966. – P. 35 – 38. 9. Kikianty E., Dragomir S. S. Hermite – Hadamard’s inequality and the p-HH-norm on the Cartesian product of two copies of a normed space // Math. Inequal. Appl. – 2010. – 13, № 1. – P. 1 – 32. 10. Kikianty E., Sinnamon G. The p-HH norms on Cartesian powers and sequence spaces // J. Math. Anal. and Appl. – 2009. – 359, № 2. – P. 765 – 779. 11. Maligranda L. Simple norm inequalities // Amer. Math. Month. – 2006. – 113. – P. 256 – 260. 12. Massera J. L., Schäffer J. J. Linear differential equations and functional analysis. I // Ann. Math. – 1958. – 67. – P. 517 – 573. 13. Mitrinović D. S., Pečarić J. E., Fink A. M. Classical and new inequalities in analysis. – Dordrecht: Kluwer, 1993. 14. Roberts A. W., Varberg D. E. Convex functions // Pure and Appl. Math. – 1973. – 57. – xx+300 p. Received 20.11.13 ISSN 1027-3190. Укр. мат. журн., 2015, т. 67, № 1
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spelling umjimathkievua-article-19602019-12-05T09:47:39Z New Inequalities for the $p$-Angular Distance in Normed Spaces with Applications Нові нерівності для $p$-кутової відстані в нормованих просторах та їх застосування Dragomir, S. S. Драгомир, С. С. For nonzero vectors $x$ and $y$ in the normed linear space $(X, ‖ ⋅ ‖)$, we can define the $p$-angular distance by $${\alpha}_p\left[x,y\right]:=\left\Vert {\left\Vert x\right\Vert}^{p-1}x-{\left\Vert y\right\Vert}^{p-1}y\right\Vert .$$ We show (among other results) that, for $p ≥ 2$, $$\begin{array}{l}{\alpha}_p\left[x,y\right]\le p\left\Vert y-x\right\Vert {\displaystyle \underset{0}{\overset{1}{\int }}{\left\Vert \left(1-t\right)x+ty\right\Vert}^{p-1}dt}\hfill \\ {}\kern3.36em \le p\left\Vert y-x\right\Vert \left[\frac{{\left\Vert x\right\Vert}^{p-1}+{\left\Vert y\right\Vert}^{p-1}}{2}+{\left\Vert \frac{x+y}{2}\right\Vert}^{p-1}\right]\hfill \\ {}\kern3.36em \le p\left\Vert y-x\right\Vert \frac{{\left\Vert x\right\Vert}^{p-1}+{\left\Vert y\right\Vert}^{p-1}}{2}\le p\left\Vert y-x\right\Vert {\left[ \max \left\{\left\Vert x\right\Vert, \left\Vert y\right\Vert \right\}\right]}^{p-1},\hfill \end{array}$$, for any $x, y ∈ X$. This improves a result of Maligranda from [“Simple norm inequalities,” Amer. Math. Month., 113, 256–260 (2006)] who proved the inequality between the first and last terms in the estimation presented above. The applications to functions f defined by power series in estimating a more general “distance” $‖f(‖x‖)x − f(‖y‖)y‖$ for some $x, y ∈ X$ are also presented. Для ненульових векторів $x$ та $y$ в лінійному нормованому просторі $(X, ‖ ⋅ ‖)$ можна визначити $p$-кутову відстань таким чином: $${\alpha}_p\left[x,y\right]:=\left\Vert {\left\Vert x\right\Vert}^{p-1}x-{\left\Vert y\right\Vert}^{p-1}y\right\Vert .$$ У роботі, зокрема, показано, що $$\begin{array}{l}{\alpha}_p\left[x,y\right]\le p\left\Vert y-x\right\Vert {\displaystyle \underset{0}{\overset{1}{\int }}{\left\Vert \left(1-t\right)x+ty\right\Vert}^{p-1}dt}\hfill \\ {}\kern3.36em \le p\left\Vert y-x\right\Vert \left[\frac{{\left\Vert x\right\Vert}^{p-1}+{\left\Vert y\right\Vert}^{p-1}}{2}+{\left\Vert \frac{x+y}{2}\right\Vert}^{p-1}\right]\hfill \\ {}\kern3.36em \le p\left\Vert y-x\right\Vert \frac{{\left\Vert x\right\Vert}^{p-1}+{\left\Vert y\right\Vert}^{p-1}}{2}\le p\left\Vert y-x\right\Vert {\left[ \max \left\{\left\Vert x\right\Vert, \left\Vert y\right\Vert \right\}\right]}^{p-1},\hfill \end{array}$$ для $p ≥ 2$ i будь-яких $x, y ∈ X$. Це покращує результат Малігранди [Simple norm inequalities // Amer. Math. Month. -2006. - 113. - P. 256-260], який встановив нерівність між першим та останнім членами вказаної оцінки. Також наведено застосування для функцій f, визначених степеневими рядами при оцінюванні більш загальної „відстані&quot; $‖f(‖x‖)x − f(‖y‖)y‖$ для деяких $x, y ∈ X$. Institute of Mathematics, NAS of Ukraine 2015-01-25 Article Article application/pdf https://umj.imath.kiev.ua/index.php/umj/article/view/1960 Ukrains’kyi Matematychnyi Zhurnal; Vol. 67 No. 1 (2015); 19–31 Український математичний журнал; Том 67 № 1 (2015); 19–31 1027-3190 en https://umj.imath.kiev.ua/index.php/umj/article/view/1960/943 https://umj.imath.kiev.ua/index.php/umj/article/view/1960/944 Copyright (c) 2015 Dragomir S. S.
spellingShingle Dragomir, S. S.
Драгомир, С. С.
New Inequalities for the $p$-Angular Distance in Normed Spaces with Applications
title New Inequalities for the $p$-Angular Distance in Normed Spaces with Applications
title_alt Нові нерівності для $p$-кутової відстані в нормованих просторах та їх застосування
title_full New Inequalities for the $p$-Angular Distance in Normed Spaces with Applications
title_fullStr New Inequalities for the $p$-Angular Distance in Normed Spaces with Applications
title_full_unstemmed New Inequalities for the $p$-Angular Distance in Normed Spaces with Applications
title_short New Inequalities for the $p$-Angular Distance in Normed Spaces with Applications
title_sort new inequalities for the $p$-angular distance in normed spaces with applications
url https://umj.imath.kiev.ua/index.php/umj/article/view/1960
work_keys_str_mv AT dragomirss newinequalitiesforthepangulardistanceinnormedspaceswithapplications
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AT dragomirss novínerívnostídlâpkutovoívídstanívnormovanihprostorahtaíhzastosuvannâ