Estimates for $\lambda$-spirallike function of complex order on the boundary

UDC 517.5 We give some results for $\lambda$ -spirallike function of complex order at the boundary of the unit disc $U$. The sharpness of these results is also proved. Furthermore, three examples for our results are considered.  

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Datum:2022
Hauptverfasser: Akyel, T., .
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Veröffentlicht: Institute of Mathematics, NAS of Ukraine 2022
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Ukrains’kyi Matematychnyi Zhurnal
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author Akyel, T.
.
Akyel, T.
author_facet Akyel, T.
.
Akyel, T.
author_sort Akyel, T.
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datestamp_date 2022-03-27T15:39:11Z
description UDC 517.5 We give some results for $\lambda$ -spirallike function of complex order at the boundary of the unit disc $U$. The sharpness of these results is also proved. Furthermore, three examples for our results are considered.  
doi_str_mv 10.37863/umzh.v74i1.2375
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fulltext DOI: 10.37863/umzh.v74i1.2375 UDC 517.5 T. Akyel (Maltepe Univ., Istanbul, Turkey) ESTIMATES FOR \bfitlambda -SPIRALLIKE FUNCTION OF COMPLEX ORDER ON THE BOUNDARY ОЦIНКИ ДЛЯ СПIРАЛЕПОДIБНОЇ \bfitlambda -ФУНКЦIЇ КОМПЛЕКСНОГО ПОРЯДКУ НА ГРАНИЦI We give some results for \lambda -spirallike function of complex order at the boundary of the unit disc U . The sharpness of these results is also proved. Furthermore, three examples for our results are considered. Наведено деякi результати для спiралеподiбної \lambda -функцiї комплексного порядку на границi одиничного диска U, а також доведено точнiсть цих результатiв. Крiм того, розглянуто три приклади для iлюстрацiї цих результатiв. 1. Introduction. Let f be a holomorphic function in the unit disc U = \bigl\{ z : | z| < 1 \bigr\} , f(0) = 0 and | f(z)| < 1 for | z| < 1. In accordance with the classical Schwarz lemma, for any point z in the disc U, we have | f(z)| \leq | z| and | f \prime (0)| \leq 1. Equality in these inequalities (in the first one, for z \not = 0) occurs only if f(z) = zei\theta , where \theta is a real number [7, p. 329]. The study of generalizations and variations of Schwarz’s lemma as well as Littlewood’s theorem is of fundamental significance in the area of geometric function theory and attracts many authors’ interest during the last years (see, for example, [3, 7, 20] and the references therein). The generalization of the Schwarz lemma as follows: | f(z)| \leq | z| | z| + | f \prime (0)| 1 + | z| | f \prime (0)| , z \in U. (1.1) Inequality (1.1) and its generalizations have important applications in geometric theory of functions (see, e.g., [7, 16, 19]). Therefore, the interest in such type results has also continued in recent years (see, e.g., [2, 3, 5, 6, 11, 12, 16 – 19] and references therein). Let \scrA denote the class of functions f(z) = z + c2z 2 + c3z 3 + . . . which are holomorphic in the unit disc U . Let \scrM denote the class of bounded holomorphic functions h(z) in U, satisfying the condition h(0) = 0 and | h(z)| \leq | z| for z \in U . For a function belonging to the class \scrA we say that f(z) is \lambda -spirallike function of complex order in U if and only if \Re \biggl( 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda zf \prime (z) f(z) - (1 - b) \mathrm{c}\mathrm{o}\mathrm{s}\lambda - i \mathrm{s}\mathrm{i}\mathrm{n}\lambda \biggr] \biggr) > 0, (1.2) for some real \lambda , | \lambda | < \pi 2 , b \not = 0, complex.We denote this class by \scrN (\lambda ). It was introduced and studied by Al-Oboudi and Haidan [1]. It is easy to show that f(z) \in \scrN (\lambda ) if and only if there is an h \in \scrM such that \mathrm{s}\mathrm{e}\mathrm{c}\lambda ei\lambda zf \prime (z) f(z) - i \mathrm{t}\mathrm{a}\mathrm{n}\lambda = 1 + (2b - 1)h(z) 1 - h(z) (1.3) for z \in U and for some \lambda , | \lambda | < \pi 2 . c\bigcirc T. AKYEL, 2022 ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 3 4 T. AKYEL Therefore, from (1.3), we take h(z) = ei\lambda zf \prime (z) f(z) - 1 ei\lambda \biggl( zf \prime (z) f(z) - 1 \biggr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda . Since h(z) \in \scrM , from Schwarz lemma, we obtain h(z) = ei\lambda c2z + \bigl( 2c3 - c22 \bigr) z2 + . . . ei\lambda \bigl( c2z + \bigl( 2c3 - c22 \bigr) z2 + . . . \bigr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda , h(z) z = ei\lambda c2 + \bigl( 2c3 - c22 \bigr) z + . . . ei\lambda \bigl( c2z + \bigl( 2c3 - c22 \bigr) z2 + . . . \bigr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda , | h\prime (0)| = | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \leq 1 and | c2| \leq 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda . (1.4) Moreover, the equality in (1.4) occurs for the function f(z) = z (1 - z)2be - i\lambda cos\lambda . It is an elementary consequence of Schwarz lemma that if f extends continuously to some boundary point c with | c| = 1, and if | f(c)| = 1 and f \prime (c) exists, then | f \prime (c)| \geq 1, which is known as the Schwarz lemma on the boundary. Passing to the angular limit in (1.1), we obtain the boundary Schwarz lemma [16] | f \prime (c)| \geq 2 1 + | f \prime (0)| . (1.5) For c = 1, the equality in (1.5) occurs for the function f(z) = z z + a 1 + az , where 0 \leq a \leq 1. It follow that | f \prime (c)| \geq 1 (1.6) with equality only if f is of the form f(z) = zei\theta , \theta is real. V. N. Dubinin has continued this line and has made a refinement on the boundary Schwarz lemma by considering the function f(z) = cpz p + cp+1z p+1 + . . . with a zero set \{ zk\} (see [5]). S. G. Krantz and D. M. Burns [10] and D. Chelst [4] has studied the uniqueness part of the Schwarz lemma. P. R. Mercer [11] has proved a version of the Schwarz lemma where the images of two points are known. Also, he has considered some Schwarz and Carathéodory inequalities at the boundary, as consequences of a lemma due to Rogosinski [12]. For more general results and related estimates, we refer to the papers [13 – 15]. Also, M. Jeong [9] has obtained some inequalities at a boundary point for different form of holo- morphic functions and has found the condition for equality and also in [8], has defined a holomorphic self map on the closed unit disc with fixed points only on the boundary of the unit disc. In the proofs of our main results, we will resort to the following lemma due to Julia – Wolff [19]. ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 ESTIMATES FOR \lambda -SPIRALLIKE FUNCTION OF COMPLEX ORDER ON THE BOUNDARY 5 Lemma 1 (Julia – Wolff lemma). Let f be a holomorphic function in U, f(0) = 0 and f(U) \subset \subset U. If , in addition, the function f has an angular limit f(c) at c \in \partial U, | f(c)| = 1, then the angular derivative f \prime (c) exists and 1 \leq | f \prime (c)| \leq \infty . Corollary 1. The holomorphic function f has a finite angular derivative f \prime (c) if and only if f \prime has the finite angular limit f \prime (c) at c \in \partial U. 2. Main results. In this section, for holomorphic function f(z) = z + c2z 2 + c3z 3 + . . . belonging to the class of \scrN (\lambda ), the modulus of the angular derivative of the function zf \prime (z) f(z) will be estimated from below on the boundary point of the unit disc. The sharpness of these results is also proved. Furthermore, examples will be presented for the inequalities obtained. Theorem 1. Let f(z) \in \scrN (\lambda ). Assume that, for some c \in \partial U, f has angular limit f(c) at c and cf \prime (c) f(c) = 1 - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ei\lambda . Then we have the inequality \bigm| \bigm| \bigm| \bigm| \biggl( zf \prime (z) f(z) \biggr) \prime z=c \bigm| \bigm| \bigm| \bigm| \geq | b| 2 \mathrm{c}\mathrm{o}\mathrm{s}\lambda . (2.1) The equality in (2.1) occurs for the function f(z) = z (1 - z)2be - i\lambda cos\lambda . Proof. Since f(z) \in \scrN (\lambda ), we write \mathrm{s}\mathrm{e}\mathrm{c}\lambda ei\lambda zf \prime (z) f(z) - i \mathrm{t}\mathrm{a}\mathrm{n}\lambda = 1 + (2b - 1)h(z) 1 - h(z) for z \in U and for some \lambda , | \lambda | < \pi 2 and h(z) \in \scrM . Thus, we get h(z) = ei\lambda zf \prime (z) f(z) - 1 ei\lambda \biggl( zf \prime (z) f(z) - 1 \biggr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ; h(z) is a holomorphic function in the unit disc U, | h(z)| < 1 for | z| < 1 and h(0) = 0. For c \in \partial U and cf \prime (c) f(c) = 1 - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ei\lambda , we take | h(c)| = \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| e i\lambda cf \prime (c) f(c) - 1 ei\lambda \biggl( cf \prime (c) f(c) - 1 \biggr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| = \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| 1 - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ei\lambda - 1 ei\lambda \biggl( 1 - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ei\lambda - 1 \biggr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| = = \bigm| \bigm| \bigm| \bigm| - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \bigm| \bigm| \bigm| \bigm| = \bigm| \bigm| \bigm| \bigm| b \mathrm{c}\mathrm{o}\mathrm{s}\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \bigm| \bigm| \bigm| \bigm| = 1. Let g(z) = zf \prime (z) f(z) . ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 6 T. AKYEL So, h(z) = ei\lambda g(z) - 1 ei\lambda (g(z) - 1) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda . From (1.6), we obtain 1 \leq | h\prime (c)| = \bigm| \bigm| \bigm| \bigm| \bigm| ei\lambda 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda g\prime (c) (ei\lambda (g(c) - 1) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ) 2 \bigm| \bigm| \bigm| \bigm| \bigm| = = \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda g\prime (c)\biggl( ei\lambda \biggl( 1 - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ei\lambda - 1 \biggr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) 2 \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| \bigm| = = \bigm| \bigm| \bigm| \bigm| 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda g\prime (c) ( - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda )2 \bigm| \bigm| \bigm| \bigm| = \bigm| \bigm| \bigm| \bigm| 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda g\prime (c)(b \mathrm{c}\mathrm{o}\mathrm{s}\lambda )2 \bigm| \bigm| \bigm| \bigm| = 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda and | g\prime (c)| \geq | b| 2 \mathrm{c}\mathrm{o}\mathrm{s}\lambda . Now, we shall show that inequality (2.1) is sharp. Let f(z) = z (1 - z)2be - i\lambda cos\lambda . (2.2) Differentiating (2.2) logarithmically, we have \mathrm{l}\mathrm{n} f(z) = \mathrm{l}\mathrm{n} z (1 - z)2be - i\lambda cos\lambda , f \prime (z) f(z) = 1 z + 2be - i\lambda \mathrm{c}\mathrm{o}\mathrm{s}\lambda 1 - z and g(z) = zf \prime (z) f(z) = 1 + 2be - i\lambda \mathrm{c}\mathrm{o}\mathrm{s}\lambda z 1 - z . Therefore, we take g\prime (z) = 1 (1 - z)2 2be - i\lambda \mathrm{c}\mathrm{o}\mathrm{s}\lambda and \bigm| \bigm| g\prime ( - 1) \bigm| \bigm| = | b| 2 \mathrm{c}\mathrm{o}\mathrm{s}\lambda . Theorem 1 is proved. Inequality (2.1) can be strengthened as below by taking into account c2 which is the second coefficient in the expansion of the function f(z). Theorem 2. Under the same assumptions as in Theorem 1, we have the inequality\bigm| \bigm| \bigm| \bigm| \biggl( zf \prime (z) f(z) \biggr) \prime z=c \bigm| \bigm| \bigm| \bigm| \geq 2| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda + | c2| . (2.3) ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 ESTIMATES FOR \lambda -SPIRALLIKE FUNCTION OF COMPLEX ORDER ON THE BOUNDARY 7 Inequality (2.3) is sharp with equality for the function f(z) = z\bigl( z2 + 2dz + 1 \bigr) e - i\lambda b cos\lambda , where d = | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda is an arbitrary number on [0, 1] (see (1.4)). Proof. Let h(z) be as in the proof of Theorem 1. By using inequality (1.5) for the function h(z), we obtain 2 1 + | h\prime (0)| \leq | h\prime (c)| = \bigm| \bigm| \bigm| \bigm| \bigm| ei\lambda 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda g\prime (c) (ei\lambda (g(c) - 1) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ) 2 \bigm| \bigm| \bigm| \bigm| \bigm| = 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda , where g(z) = \biggl( zf \prime (z) f(z) \biggr) . Since h\prime (z) = ei\lambda 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda g\prime (z) (ei\lambda (g(z) - 1) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ) 2 , h\prime (0) = ei\lambda 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda g\prime (0) (ei\lambda (g(0) - 1) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ) 2 and \bigm| \bigm| h\prime (0)\bigm| \bigm| = | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda , we take 2 1 + | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \leq 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda . Thus, we obtain inequality (2.3). Now, we shall show that inequality (2.3) is sharp. Choose arbitrary d \in [0, 1]. Let f(z) = z\bigl( z2 + 2dz + 1 \bigr) e - i\lambda b cos\lambda . (2.4) Differentiating (2.4) logarithmically, we get \mathrm{l}\mathrm{n} f(z) = \mathrm{l}\mathrm{n} z\bigl( z2 + 2dz + 1 \bigr) e - i\lambda b cos\lambda , f \prime (z) f(z) = 1 z - 2e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda z + d z2 + 2dz + 1 and g(z) = zf \prime (z) f(z) = 1 - 2e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda z2 + dz z2 + 2dz + 1 . Thus, since d = | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda , we obtain ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 8 T. AKYEL | g\prime (1)| = 2| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda + | c2| . Theorem 2 is proved. Now, inequality (2.3) can be strengthened as below by taking into account c3 which is the third coefficient in the expansion of the function f(z). Theorem 3. Let f(z) belong to \scrN (\lambda ). Assume that, for some c \in \partial U, f has angular limit f(c) at c and cf \prime (c) f(c) = 1 - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ei\lambda . Then we have the inequality \bigm| \bigm| \bigm| \bigm| \biggl( zf \prime (z) f(z) \biggr) \prime z=c \bigm| \bigm| \bigm| \bigm| \geq | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda 2 \Biggl( 1 + 2 \bigl( 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda - | c2| \bigr) 2 4| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda - | c2| 2 + | (2c3 - c22)2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22| \Biggr) . (2.5) Inequality (2.5) is sharp with equality for the function f(z) = z (1 - z2)e - i\lambda b cos\lambda . Proof. Let h(z) be as in the proof of Theorem 1 and \eta (z) = z. By the maximum principle for each z \in U, we have | h(z)| \leq | \eta (z)| . So, p(z) = h(z) \eta (z) is a holomorphic function in U and | p(z)| < 1 for | z| < 1. Since h(z) = ei\lambda c2z + \bigl( 2c3 - c22 \bigr) z2 + . . . ei\lambda \bigl( c2z + \bigl( 2c3 - c22 \bigr) z2 + . . . \bigr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda and p(z) = h(z) z = ei\lambda z \bigl( c2 + \bigl( 2c3 - c22 \bigr) z + . . . \bigr) \bigl( ei\lambda \bigl( c2z + \bigl( 2c3 - c22 \bigr) z2 + . . . \bigr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \bigr) z = = ei\lambda \bigl( c2 + \bigl( 2c3 - c22 \bigr) z + . . . \bigr) \bigl( ei\lambda \bigl( c2z + \bigl( 2c3 - c22 \bigr) z2 + . . . \bigr) + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \bigr) , in particular, we have | p(0)| = | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \leq 1 (2.6) and | p\prime (0)| = \bigm| \bigm| (2c3 - c22)2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22 \bigm| \bigm| 4| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda . Moreover, it can be seen that ch\prime (c) h(c) = | h\prime (c)| \geq | \eta \prime (c)| = c\eta \prime (c) \eta (c) . The function ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 ESTIMATES FOR \lambda -SPIRALLIKE FUNCTION OF COMPLEX ORDER ON THE BOUNDARY 9 \Gamma (z) = p(z) - p(0) 1 - p(0)p(z) is holomorphic in the unit disc U, | \Gamma (z)| < 1 for | z| < 1, \Gamma (0) = 0 and | \Gamma (c)| = 1 for c \in \partial U. From (1.5), we obtain 2 1 + | \Gamma \prime (0)| \leq \bigm| \bigm| \Gamma \prime (c) \bigm| \bigm| = 1 - | p(0)| 2 | 1 - p(0)p(c)| 2 | p\prime (c)| \leq 1 + | p(0)| 1 - | p(0)| | p\prime (c)| = = 1 + | p(0)| 1 - | p(0)| \bigl\{ | h\prime (c)| - 1 \bigr\} . Since \Gamma \prime (z) = 1 - | p(0)| 2\Bigl( 1 - p(0)p(z) \Bigr) 2 p\prime (z), | \Gamma \prime (0)| = | p\prime (0)| 1 - | p(0)| 2 = \bigm| \bigm| \bigl( 2c3 - c22 \bigr) 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22 \bigm| \bigm| 4| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda 1 - \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) 2 = \bigm| \bigm| \bigl( 2c3 - c22 \bigr) 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22 \bigm| \bigm| 4| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda - | c2| 2 , we take 2 1 + \bigm| \bigm| \bigl( 2c3 - c22 \bigr) 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22 \bigm| \bigm| 4| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda - | c2| 2 \leq 1 + | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda 1 - | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl\{ 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda - 1 \biggr\} = = 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda + | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda - | c2| \biggl\{ 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda - 1 \biggr\} . Therefore, we get 1 + 2 \bigl( 4| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda - | c2| 2 \bigr) 4| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda - | c2| 2 + | \bigl( 2c3 - c22 \bigr) 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda - | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda + | c2| \leq 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda and | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda 2 \Biggl( 1 + 2 \bigl( 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda - | c2| \bigr) 2 4| b| 2 \mathrm{c}\mathrm{o}\mathrm{s}2 \lambda - | c2| 2 + \bigm| \bigm| \bigl( 2c3 - c22 \bigr) 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22 \bigm| \bigm| \Biggr) \leq \bigm| \bigm| g\prime (c)\bigm| \bigm| . So, we obtain inequality (2.5). To show that inequality (2.5) is sharp, take the holomorphic function f(z) = z (1 - z2)e - i\lambda b cos\lambda . (2.7) Differentiating (2.7) logarithmically, we obtain \mathrm{l}\mathrm{n} f(z) = \mathrm{l}\mathrm{n} z (1 - z2)e - i\lambda b cos\lambda , ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 10 T. AKYEL f \prime (z) f(z) = 1 z + e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda 2z 1 - z2 and g(z) = zf \prime (z) f(z) = 1 + e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda 2z2 1 - z2 . Therefore, we take g\prime (z) = e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda 4z (1 - z2)2 and | g\prime (i)| = | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda . Since | c2| = 0 and | c3| = | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda , (2.5) is satisfied with equality. Theorem 3 is proved. If f(z) - z has no zeros different from z = 0 in Theorem 3, inequality (2.5) can be further strengthened. This is given by the following theorem. Theorem 4. Let f(z) \in \scrN (\lambda ), f(z) - z has no zeros in U except z = 0 and c2 > 0. Suppose that, for some c \in \partial U, f has angular limit f(c) at c and cf \prime (c) f(c) = 1 - b \mathrm{c}\mathrm{o}\mathrm{s}\lambda ei\lambda . Then we have the inequality \bigm| \bigm| \bigm| \bigm| \biggl( zf \prime (z) f(z) \biggr) \prime z=c \bigm| \bigm| \bigm| \bigm| \geq | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda 2 \left( 1 - 4| c2| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \mathrm{l}\mathrm{n}2 \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) 4| c2| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \mathrm{l}\mathrm{n} \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) - | \bigl( 2c3 - c22 \bigr) 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22| \right) . (2.8) Proof. Let c2 > 0 in the expression of the function f(z). Having in mind inequality (2.6) and the function f(z) - z has no zeros in U except z = 0, we denote by \mathrm{l}\mathrm{n} p(z) the holomorphic branch of the logarithm normed by the condition \mathrm{l}\mathrm{n} p(0) = \mathrm{l}\mathrm{n} \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) < 0. The auxiliary function \Upsilon (z) = \mathrm{l}\mathrm{n} p(z) - \mathrm{l}\mathrm{n} p(0) \mathrm{l}\mathrm{n} p(z) + \mathrm{l}\mathrm{n} p(0) is holomorphic in the unit disc U, | \Upsilon (z)| < 1, \Upsilon (0) = 0 and | \Upsilon (c)| = 1 for c \in \partial U. From (1.5), we get 2 1 + | \Upsilon \prime (0)| \leq | \Upsilon \prime (c)| = | 2 \mathrm{l}\mathrm{n} p(0)| | \mathrm{l}\mathrm{n} p(c) + \mathrm{l}\mathrm{n} p(0)| 2 \bigm| \bigm| \bigm| \bigm| p\prime (c)p(c) \bigm| \bigm| \bigm| \bigm| = - 2 \mathrm{l}\mathrm{n} p(0) \mathrm{l}\mathrm{n}2 p(0) + \mathrm{a}\mathrm{r}\mathrm{g}2 p(c) \bigl\{ | h\prime (c)| - 1 \bigr\} . Replacing \mathrm{a}\mathrm{r}\mathrm{g}2 p(c) by zero, then 1 1 - 1 2 \mathrm{l}\mathrm{n} \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) | \bigl( 2c3 - c22 \bigr) 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22| 2| c2| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \leq - 1 \mathrm{l}\mathrm{n} \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) \biggl\{ 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda - 1 \biggr\} ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 ESTIMATES FOR \lambda -SPIRALLIKE FUNCTION OF COMPLEX ORDER ON THE BOUNDARY 11 and 1 - 4| c2| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \mathrm{l}\mathrm{n}2 \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) 4| c2| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \mathrm{l}\mathrm{n} \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) - | \bigl( 2c3 - c22 \bigr) 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - ei\lambda c22| \leq 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda . Thus, we obtain inequality (2.8). The following inequality (2.9) is weaker, but is simpler than (2.8) and does not contain the coefficient c3. Theorem 5. Under the same assumptions as in Theorem 4, we have the inequality\bigm| \bigm| \bigm| \bigm| \biggl( zf \prime (z) f(z) \biggr) \prime z=c \bigm| \bigm| \bigm| \bigm| \geq | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda 2 \biggl( 1 - 1 2 \mathrm{l}\mathrm{n} \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) \biggr) . (2.9) Proof. Let c2 > 0. Using inequality (1.6) for the function \Gamma (z), we obtain 1 \leq | \Upsilon \prime (c)| = | 2 \mathrm{l}\mathrm{n} p(0)| | \mathrm{l}\mathrm{n} p(c) + \mathrm{l}\mathrm{n} p(0)| 2 \bigm| \bigm| \bigm| \bigm| p\prime (c)p(c) \bigm| \bigm| \bigm| \bigm| = - 2 \mathrm{l}\mathrm{n} p(0) \mathrm{l}\mathrm{n}2 p(0) + \mathrm{a}\mathrm{r}\mathrm{g}2 p(c) \bigl\{ | h\prime (c)| - 1 \bigr\} . Replacing \mathrm{a}\mathrm{r}\mathrm{g}2 p(c) by zero, then 1 \leq | \Upsilon \prime (c)| \leq - 2 \mathrm{l}\mathrm{n} \biggl( | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr) \biggl\{ 2| g\prime (c)| | b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda - 1 \biggr\} . Therefore, we obtain inequality (2.9). Theorem 4 is proved. 3. Examples. Example 1. Let us consider the function f(z) defined by f(z) = z (1 - z)2be - i\lambda cos\lambda . From here, we have zf \prime (z) f(z) = 1 + 2be - i\lambda \mathrm{c}\mathrm{o}\mathrm{s}\lambda z 1 - z . So, we take 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda zf \prime (z) f(z) - (1 - b) \mathrm{c}\mathrm{o}\mathrm{s}\lambda - i \mathrm{s}\mathrm{i}\mathrm{n}\lambda \biggr] = = 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda \biggl( 1 + 2be - i\lambda \mathrm{c}\mathrm{o}\mathrm{s}\lambda z 1 - z \biggr) - (1 - b) \mathrm{c}\mathrm{o}\mathrm{s}\lambda - i \mathrm{s}\mathrm{i}\mathrm{n}\lambda \biggr] = = 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda z 1 - z - \mathrm{c}\mathrm{o}\mathrm{s}\lambda + b \mathrm{c}\mathrm{o}\mathrm{s}\lambda - i \mathrm{s}\mathrm{i}\mathrm{n}\lambda \biggr] = = 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda + 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda z 1 - z - ei\lambda + b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr] = = 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl( 2z 1 - z + 1 \biggr) \biggr] = 1 + z 1 - z . ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 12 T. AKYEL Obviously, the function k(z) = 1 + z 1 - z maps the unit disc U to the right half plane and, hence, the real part of the function k(z) is nonne- gative. Therefore, we obtain \Re \biggl( 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda zf \prime (z) f(z) - (1 - b) \mathrm{c}\mathrm{o}\mathrm{s}\lambda - i \mathrm{s}\mathrm{i}\mathrm{n}\lambda \biggr] \biggr) = \Re \biggl( 1 + z 1 - z \biggr) > 0. Thus, the function f(z) satisfies condition (1.2) and Theorem 1. That is, f(z) = z (1 - z)2be - i\lambda cos\lambda and, for some c \in \partial U, we have ( - 1)f \prime ( - 1) f( - 1) = 1 + 2be - i\lambda \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl( - 1 1 - ( - 1) \biggr) = 1 + 2be - i\lambda \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl( - 1 2 \biggr) and ( - 1)f \prime ( - 1) f( - 1) = 1 - be - i\lambda \mathrm{c}\mathrm{o}\mathrm{s}\lambda . Example 2. Let us consider the function f(z) defined by f(z) = z\bigl( z2 + 2dz + 1 \bigr) e - i\lambda b cos\lambda , where d = | c2| 2| b| \mathrm{c}\mathrm{o}\mathrm{s}\lambda is an arbitrary number from [0, 1] (see (1.4)). Hence, we get zf \prime (z) f(z) = 1 - 2e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda z2 + dz z2 + 2dz + 1 . Therefore, we obtain 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda zf \prime (z) f(z) - (1 - b) \mathrm{c}\mathrm{o}\mathrm{s}\lambda - i \mathrm{s}\mathrm{i}\mathrm{n}\lambda \biggr] = = 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda \biggl( 1 - e - i\lambda 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda z2 + dz z2 + 2dz + 1 \biggr) - (1 - b) \mathrm{c}\mathrm{o}\mathrm{s}\lambda - i \mathrm{s}\mathrm{i}\mathrm{n}\lambda \biggr] = = 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda - 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda z2 + dz z2 + 2dz + 1 - ei\lambda + b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr] = = 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ - 2b \mathrm{c}\mathrm{o}\mathrm{s}\lambda z2 + dz z2 + 2dz + 1 + b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggr] = = 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl( - 2 z2 + dz z2 + 2dz + 1 + 1 \biggr) \biggr] = 1 - z2 z2 + 2dz + 1 . Since d \in [0, 1], we see that ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1 ESTIMATES FOR \lambda -SPIRALLIKE FUNCTION OF COMPLEX ORDER ON THE BOUNDARY 13 \Re \biggl( 1 b \mathrm{c}\mathrm{o}\mathrm{s}\lambda \biggl[ ei\lambda zf \prime (z) f(z) - (1 - b) \mathrm{c}\mathrm{o}\mathrm{s}\lambda - i \mathrm{s}\mathrm{i}\mathrm{n}\lambda \biggr] \biggr) = \Re \biggl( 1 - z2 z2 + 2dz + 1 \biggr) > 0. Thus, the function f(z) satisfies condition (1.2) and Theorem 2. That is, f(z) = z\bigl( z2 + 2dz + 1 \bigr) e - i\lambda b cos\lambda , for some c \in \partial U, we have f \prime (1) f(1) = 1 - 2e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda 1 + d 1 + 2d+ 1 = 1 - 2e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda 1 + d 2(1 + d) and f \prime (1) f(1) = 1 - e - i\lambda b \mathrm{c}\mathrm{o}\mathrm{s}\lambda . Example 3. Let us consider the function f(z) given by f(z) = z (1 - z2)e - i\lambda b cos\lambda . Similar to other examples, it can be easily shown that the function f(z) provides the properties of class \scrN (\lambda ). References 1. F. M. Al-Oboudi, M. M. Haidan, Spirallike functions of complex order, J. Nat. Geom., 19, 53 – 72 (2000). 2. T. A. Azeroğlu, B. N. Örnek, A refined Schwarz inequality on the boundary, Complex Var. and Elliptic Equat., 58, 571 – 577 (2013). 3. H. P. Boas, Julius and Julia: mastering the art of the Schwarz lemma, Amer. Math. Monthly, 117, 770 – 785 (2010). 4. D. Chelst, A generalized Schwarz lemma at the boundary, Proc. Amer. Math. Soc., 129, 3275 – 3278 (2001). 5. V. N. Dubinin, The Schwarz inequality on the boundary for functions regular in the disc, J. Math. Sci., 122, 3623 – 3629 (2004). 6. V. N. Dubinin, Bounded holomorphic functions covering no concentric circles, J. Math. Sci., 207, 825 – 831 (2015). 7. G. M. Golusin, Geometric theory of functions of complex variable (in Russian), 2nd ed., Moscow (1966). 8. M. Jeong, The Schwarz lemma and its applications at a boundary point, J. Korean Soc. Math. Educ. Ser. B. Pure and Appl. Math., 21, 275 – 284 (2014). 9. M. Jeong, The Schwarz lemma and boundary fixed points, J. Korean Soc. Math. Educ. Ser. B. Pure and Appl. Math., 18, 219 – 227 (2011). 10. S. G. Krantz, D. M. Burns, Rigidity of holomorphic mappings and a new Schwarz lemma at the boundary, J. Amer. Math. Soc., 7, 661 – 676 (1994). 11. P. R. Mercer, Sharpened versions of the Schwarz lemma, J. Math. Anal. and Appl., 205, 508 – 511 (1997). 12. P. R. Mercer, Boundary Schwarz inequalities arising from Rogosinski’s lemma, J. Class. Anal., 12, 93 – 97 (2018). 13. M. Mateljević, The lower bound for the modulus of the derivatives and Jacobian of harmonic injective mappings, Filomat, 29, 221 – 244 (2015). 14. M. Mateljević, Distortion of harmonic functions and harmonic quasiconformal quasi-isometry, Rev. Roum. Math. Pures et Appl., 51, 711 – 722 (2006). 15. M. Mateljević, Ahlfors – Schwarz lemma and curvature, Kragujevac J. Math., 25, 155 – 164 (2003). 16. R. Osserman, A sharp Schwarz inequality on the boundary, Proc. Amer. Math. Soc., 128, 3513 – 3517 (2000). 17. B. N. Örnek, Sharpened forms of the Schwarz lemma on the boundary, Bull. Korean Math. Soc., 50, 2053 – 2059 (2013). 18. B. N. Örnek, T. Akyel, Sharpened forms of the generalized Schwarz inequality on the boundary, Proc. Indian Acad. Sci. (Math. Sci.), 126, 69 – 78 (2016). 19. Ch. Pommerenke, Boundary behaviour of conformal maps, Springer-Verlag, Berlin (1992). 20. D. Shoikhet, M. Elin, F. Jacobzon, M. Levenshtein, The Schwarz lemma: rigidity and dynamics, harmonic and complex analysis and its applications, Springer Int. Publ., 135 – 230 (2014). Received 16.02.20 ISSN 1027-3190. Укр. мат. журн., 2022, т. 74, № 1
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spelling umjimathkievua-article-23752022-03-27T15:39:11Z Estimates for $\lambda$-spirallike function of complex order on the boundary Estimates for $\lambda$-spirallike function of complex order on the boundary Akyel, T. . Akyel, T. Schwarz lemma on the boundary Julia-Wolff lemma lambda-spirallikefunction UDC 517.5 We give some results for $\lambda$ -spirallike function of complex order at the boundary of the unit disc $U$. The sharpness of these results is also proved. Furthermore, three examples for our results are considered. &amp;nbsp; УДК 517.5Оцiнки для спiралеподiбної $\lambda$ -функцiї комплексного порядку на границi Наведено деякі результати для спіралеподібної $\lambda$-функції комплексного порядку на границі одиничного диска $U,$ а також доведено точність цих результатів.&amp;nbsp;Крім того, розглянуто три приклади для ілюстрації цих результатів.&amp;nbsp; Institute of Mathematics, NAS of Ukraine 2022-01-24 Article Article application/pdf https://umj.imath.kiev.ua/index.php/umj/article/view/2375 10.37863/umzh.v74i1.2375 Ukrains’kyi Matematychnyi Zhurnal; Vol. 74 No. 1 (2022); 3 - 13 Український математичний журнал; Том 74 № 1 (2022); 3 - 13 1027-3190 en https://umj.imath.kiev.ua/index.php/umj/article/view/2375/9171 Copyright (c) 2022 Tuğba AKYEL
spellingShingle Akyel, T.
.
Akyel, T.
Estimates for $\lambda$-spirallike function of complex order on the boundary
title Estimates for $\lambda$-spirallike function of complex order on the boundary
title_alt Estimates for $\lambda$-spirallike function of complex order on the boundary
title_full Estimates for $\lambda$-spirallike function of complex order on the boundary
title_fullStr Estimates for $\lambda$-spirallike function of complex order on the boundary
title_full_unstemmed Estimates for $\lambda$-spirallike function of complex order on the boundary
title_short Estimates for $\lambda$-spirallike function of complex order on the boundary
title_sort estimates for $\lambda$-spirallike function of complex order on the boundary
topic_facet Schwarz lemma on the boundary
Julia-Wolff lemma
lambda-spirallikefunction
url https://umj.imath.kiev.ua/index.php/umj/article/view/2375
work_keys_str_mv AT akyelt estimatesforlambdaspirallikefunctionofcomplexorderontheboundary
AT estimatesforlambdaspirallikefunctionofcomplexorderontheboundary
AT akyelt estimatesforlambdaspirallikefunctionofcomplexorderontheboundary