Congruences of a Permutable Inverse Semigroup of Finite Rank

We describe the structure of any congruence of a permutable inverse semigroup of finite rank.

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Datum:2005
Hauptverfasser: Derech, V. D., Дереч, В. Д.
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Sprache:Ukrainisch
Englisch
Veröffentlicht: Institute of Mathematics, NAS of Ukraine 2005
Online Zugang:https://umj.imath.kiev.ua/index.php/umj/article/view/3613
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Ukrains’kyi Matematychnyi Zhurnal
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author Derech, V. D.
Дереч, В. Д.
author_facet Derech, V. D.
Дереч, В. Д.
author_sort Derech, V. D.
baseUrl_str https://umj.imath.kiev.ua/index.php/umj/oai
collection OJS
datestamp_date 2020-03-18T20:00:05Z
description We describe the structure of any congruence of a permutable inverse semigroup of finite rank.
first_indexed 2026-03-24T02:45:47Z
format Article
fulltext UDK 512.534.5 V. D. Dereç (Vinnyc. nac. texn. un-t) KONHRUENCI} PERESTAVNO} INVERSNO} NAPIVHRUPY SKINÇENNOHO RANHU The structure of any congruence of a permutable inverse semigroup of a finite rank is described. Opysano budovu bud\-qko] konhruenci] perestavno] inversno] napivhrupy skinçennoho ranhu. Qk vidomo, bud\-qki dvi konhruenci] na hrupi perestavni vidnosno zvyçajno] ope- raci] superpozyci] binarnyx vidnoßen\. Oçevydno, wo vidpovidna vlastyvist\ ma[ misce i dlq tyx alhebra]çnyx struktur, do skladu qkyx vxodyt\ hrupova struk- tura (kil\cq, moduli ta inße). Do klasu binarnyx alhebr z perestavnymy kon- hruenciqmy takoΩ naleΩat\ ekvazihrupy i skinçenni kvazihrupy. Wo stosu[t\sq teori] napivhrup, to tut vidomi xiba wo klasy napivhrup z perestavnymy konhru- enciqmy (napivhrupy Brandta, vsi vydy skinçennyx symetryçnyx napivhrup, na- pivhrupy endomorfizmiv, a takoΩ çastkovyx avtomorfizmiv skinçenno] linijno vporqdkovano] mnoΩyny ta inßi). U statti [1] znajdeno neobxidni i dostatni umovy dlq toho, wob antyhrupa skinçennoho ranhu bula perestavnog (oznaçennq dyv. v p.41). Dana stattq [ sutt[vym uzahal\nennqm rezul\tatu roboty [1]. U nij (p.44, teorema44) z’qsovu[t\sq budova bud\-qko] konhruenci] perestavno] inversno] napivhrupy z nulem skinçennoho ranhu. 1. Osnovna terminolohiq i poznaçennq. Napivreßitku S nazyvagt\ napiv- reßitkog skinçenno] dovΩyny, qkwo isnu[ natural\ne çyslo n take, wo dov- Ωyna bud\-qkoho lancgΩka z S ne perevywu[ n. Nexaj P — vporqdkovana mnoΩyna skinçenno] dovΩyny z najmenßym ele- mentom 0. Toçna verxnq meΩa dovΩyn lancgΩkiv, wo z’[dnugt\ 0 i element x, nazyva[t\sq vysotog elementa x i poznaça[t\sq çerez h ( x ) . Nexaj S — dovil\na napivhrupa, a N0 — mnoΩyna vsix nevid’[mnyx cilyx çy- sel. Funkcig rank : S → N0 nazyvagt\ ranhovog na napivhrupi S, qkwo dlq bud\-qkyx elementiv a i b ∈ S vykonu[t\sq nerivnist\ rank ( a ⋅ b ) ≤ min { rank ( a ) , rank ( b ) } . Çyslo rank ( a ) nazyva[t\sq ranhom elementa a. Napivhrupu nazyvagt\ perestavnog, qkwo bud\-qki dvi konhruenci] na nij perestavni vidnosno zvyçajno] operaci] superpozyci] binarnyx vidnoßen\. Vsi inßi neobxidni ponqttq z teori] napivhrup i teori] inversnyx napivhrup moΩna znajty vidpovidno v monohrafiqx [2, 3]. 2. Ranhova funkciq i ]] osnovni vlastyvosti. V c\omu punkti vvedemo ran- hovu funkcig na inversnij napivhrupi, napivreßitka idempotentiv qko] ma[ skin- çennu dovΩynu, i vstanovymo osnovni ]] vlastyvosti. Dlq c\oho spoçatku damo vyznaçennq ranhu elementa napivreßitky skinçenno] dovΩyny. OtΩe, nexaj P — napivreßitka skinçenno] dovΩyny. Za oznaçennqm rank ( a ) = h ( a ) (de h ( a ) — vysota elementa a ). Lema.1. Wojno vyznaçena funkciq rank : P → N0 [ ranhovog. Ce lehko pereviryty. Lema.2. Qkwo a < b , to rank ( a ) < rank ( b ) . Dovedennq. Lehko perevirq[t\sq. Dali, nexaj S — inversna napivhrupa, napivreßitka idempotentiv qko] ma[ skinçennu dovΩynu. Oznaçennq. Nexaj a — dovil\nyj element napivhrupy S , todi (za ozna- çennqm) rank ( a ) = rank ( a ⋅ a – 1 ) . © V. D. DEREÇ, 2005 ISSN 0041-6053. Ukr. mat. Ωurn., 2005, t. 57, # 4 469 470 V. D. DEREÇ Teper nam potribno dovesty, wo rank : S → N0 dijsno [ ranhovog funkci[g na inversnij napivhrupi S. Dlq c\oho dovedemo kil\ka lem. Lema.3. Nexaj A i B — napivreßitky skinçenno] dovΩyny, f : A → B — sgr’[ktyvnyj homomorfizm. Todi dlq bud\-qkoho b ∈ B pidnapivreßitka f – 1 ( b ) ma[ najmenßyj element. Dovedennq. Nexaj a1 < a2 < … < ak — maksymal\nyj (oçevydno, wo takyj isnu[) lancgΩok, qkyj vklgça[t\sq v f b−1( ). Todi a1 — minimal\nyj element v f b−1( ), a otΩe, a1 — najmenßyj element v f b−1( ). Lema.4. Nexaj A i B — napivreßitky skinçenno] dovΩyny, f : A → B — sgr’[ktyvnyj homomorfizm. Qkwo b b1 2< (de b B1 ∈ i b B2 ∈ ), to isnugt\ a A1 ∈ i a A2 ∈ taki, wo a a1 2< i f a b( )1 1= , f a b( )2 2= . Dovedennq. Za poperedn\og lemog v pidnapivreßitci f b−1 1( ) [ najmen- ßyj element. Poznaçymo joho çerez a1. Nexaj a2 — dovil\nyj element z mnoΩyny f b−1 2( ) . Oskil\ky f a a( )1 2⋅ = f a f a( ) ( )1 2⋅ = b b1 2⋅ = b1, to a a1 2⋅ ∈ ∈ f b−1 1( ). Element a1 [ najmenßym u f b−1 1( ), tomu a1 ≤ a a1 2⋅ . Z ostann\o] nerivnosti lehko vyplyva[ a1 ≤ a2 . Oskil\ky a1 ≠ a2 , to a1 < a2 . Lema.5. Nexaj A i B — napivreßitky skinçenno] dovΩyny, f : A → B — sgr’[ktyvnyj homomorfizm. Todi dlq bud\-qkoho a ∈ A vykonu[t\sq nerivnist\ rank ( f ( a )) ≤ rank ( a ) . Dovedennq. Oskil\ky B — napivreßitka skinçenno] dovΩyny, to v nij [ najmenßyj element 0. Nexaj 0 < b1 < b 2 < … < bn – 1 < f ( a ) = bn — maksymal\nyj (za kil\kistg elementiv) lancgΩok, wo z’[dnu[ 0 i f ( a ) . U pid- napivreßitkax f −1 0( ), f b−1 1( ), f b−1 2( ), … , f bn − − 1 1( ) vybyra[mo najmenßi ele- menty, vidpovidno 0, a1, a2, a3, … , an – 1 . Za lemog44 ce lancgΩok 0 < a1 < < a2 < … < an – 1 , dovΩyna qkoho dorivng[ n – 1. Tomu lancgΩok 0 < a1 < < a2 < … < an – 1 < a ma[ dovΩynu n. OtΩe, rank ( f ( a )) ≤ rank ( a ) . Teorema.1. Nexaj S — inversna napivhrupa, napivreßitka idempotentiv qko] ma[ skinçennu dovΩynu. Todi funkciq rank : S → N0 (vona vyznaçena v p. 2) [ ranhovog. Dovedennq. Nexaj a i b — dovil\ni elementy, wo naleΩat\ S. Spoçatku dovedemo, wo rank ( a ⋅ b ) ≤ rank ( a ) . Dijsno, za oznaçennqm rank ( )ab = rank(a bb a− −1 1) . Oskil\ky abb a− −1 1 ≤ aa−1, to (za lemog42) rank ( )abb a− −1 1 ≤ rank ( )aa−1 . OtΩe, rank ( )ab = rank ( )abb a− −1 1 ≤ rank ( )aa−1 = rank ( a ) . Teper dovedemo, wo rank ( )ab ≤ rank ( b ) . Za oznaçennqm rank ( )ab = rank ( )abb a− −1 1 . Vidomo (i ce lehko pereviryty), wo funkciq f e aeaa : � −1 [ endomorfizmom napivreßitky E — idempotentiv napivhrupy S. Zokrema, f bb E abb a Ea : − − −1 1 1� — sgr’[ktyvnyj homomorfizm z idealu bb E−1 na ideal abb a E− −1 1 , pryçomu f bba( )−1 = abb a− −1 1. Za le- mog45 rank( )( )f bba −1 ≤ rank ( )bb−1 abo rank ( )abb a− −1 1 ≤ rank ( )bb−1 . OtΩe, rank ( )ab = rank ( )abb a− −1 1 ≤ rank ( )bb−1 = rank ( b ) . Takym çynom, funkciq rank [ ranhovog. Teper vidmitymo kil\ka osnovnyx vlastyvostej ranhovo] funkci]. Lema.6. Dlq bud\-qkoho a S∈ rank rank( ) ( )a a= −1 . ISSN 0041-6053. Ukr. mat. Ωurn., 2005, t. 57, # 4 KONHRUENCI} PERESTAVNO} INVERSNO} NAPIVHRUPY SKINÇENNOHO RANHU 471 Dovedennq. Ma[mo rank ( a ) = rank ( )aa a−1 ≤ rank ( )aa−1 ≤ rank ( )a−1 . Z inßoho boku, rank ( )a−1 = rank ( )a aa− −1 1 ≤ rank ( )aa−1 ≤ rank ( a ) . Takym çynom, rank ( a ) = rank ( )a−1 . Lema.7. Dlq bud\-qkoho a S∈ rank ( a ) = rank ( )a a−1 . Dovedennq. Spravdi, rank ( a ) = rank ( )a−1 = rank ( )a a−1 . Lema.8. Qkwo a < b ( a ∈ S, b ∈ S ) , to rank ( a ) < rank ( b ) . Dovedennq. PokaΩemo spoçatku, wo aa−1 < bb−1. Po-perße, zrozumilo, wo aa−1 ≤ bb−1. Oskil\ky za umovog a < b , to a ba− −1 1 = a−1 . Zvidsy a ba b− −1 1 = a b−1 , tobto a b−1 — idempotent. Prypustymo, wo aa−1 = bb−1, todi b = aa b−1 . Oskil\ky a b−1 — idempotent, to b ≤ a. Supereçnist\. Takym çynom, aa−1 < bb−1. Dali, rank ( a ) = rank ( )aa−1 < rank ( )bb−1 = rank ( b ) . OtΩe, rank ( a ) < rank ( b ) . 3. Neobxidna i dostatnq umova linijno] vporqdkovanosti idealiv. Vidomo [4] (teorema44), wo idealy perestavno] napivhrupy utvorggt\ lancgΩok vidnos- no vklgçennq. Oskil\ky dali mova jtyme pro perestavni inversni napivhrupy, to dlq nas vaΩlyvo vstanovyty neobxidni i dostatni umovy dlq toho, wob idealy tako] napivhrupy buly linijno vporqdkovanymy. Spoçatku domovymosq pro terminolohig. Nexaj S — inversna napivhrupa, napivreßitka idempotentiv qko] ma[ skinçen- nu dovΩynu. Oçevydno, wo pidmnoΩyna Ik = { }( )x S x k∈ ≤rank napivhrupy S [ idealom. Nazvemo takyj ideal ranhovym. Budemo hovoryty, wo napivhrupa S zadovol\nq[ umovu L, qkwo dlq bud\- qkyx a, b ∈ S z umovy rank ( a ) = rank ( b ) vyplyva[ SaS = SbS. Teorema.2. Nexaj S — inversna napivhrupa, napivreßitka idempotentiv qko] ma[ skinçennu dovΩynu. Nastupni umovy [ ekvivalentnymy: 1) idealy napivhrupy S linijno vporqdkovani; 2) holovni idealy napivhrupy S linijno vporqdkovani; 3) koΩnyj ideal napivhrupy S [ holovnym; 4) napivhrupa S zadovol\nq[ umovu L; 5) koΩnyj ideal napivhrupy S [ ranhovym. Dovedennq. Implikaciq (1) → (2) oçevydna. Implikaci] (2) → (1) i (3) → (2) magt\ misce dlq bud\-qko] napivhrupy i ce lehko dovesty. Dovedemo implikacig (1) → (4). OtΩe, nexaj a S∈ i b S∈ taki, wo rank ( a ) = rank ( b ) = k. Potribno dovesty, wo SaS = SbS. Prypustymo proty- leΩne, tobto SaS ≠ SbS. Idempotenty aa−1 i bb−1 poznaçymo vidpovidno çerez e i w, a mnoΩynu { }x S SxS SeS∈ = — çerez De . Rozhlqnemo I Dk e−1 ∪ . Dovedemo, wo I Dk e−1 ∪ [ idealom napivhrupy S. Rozhlqnemo moΩlyvi vypadky. 1. Nexaj x Ik∈ −1. Todi dlq bud\-qkoho y S∈ ma[mo xy Ik∈ −1 i yx Ik∈ −1. 2. Nexaj teper x De∈ . Todi SxS = SeS. Nexaj c S∈ — dovil\nyj element napivhrupy S. Qkwo rank ( xc ) < k – 1, to xc Ik∈ −1, a otΩe, xc I Dk e∈ −1 ∪ . ISSN 0041-6053. Ukr. mat. Ωurn., 2005, t. 57, # 4 472 V. D. DEREÇ Nexaj teper rank ( xc ) = k . Todi rank ( )xcc x− −1 1 = k . Lehko pereviryty, wo xcc x− −1 1 ≤ xx−1. Qkwo prypustyty, wo xcc x− −1 1 < xx−1, to za lemog48 rank ( )x cc x− −1 1 < rank ( )x x −1 . Oskil\ky rank ( )x cc x− −1 1 = k i rank ( )x x −1 = k, to pryxodymo do supereçnosti. OtΩe, xcc x− −1 1 = xx−1. Takym çynom, SaS = Saa S−1 = SeS = SxS = Sxx S−1 = Sxcc x S− −1 1 = SxcS, tobto xc De∈ . Analohiçno moΩna dovesty, wo cx I Dk e∈ −1 ∪ . Takym çynom, I Dk e−1 ∪ — ideal napihrupy S. Zrozumilo, wo I Dk w−1 ∪ — teΩ ideal napivhrupy S. Za umovog idealy napivhrupy S linijno vporqdkovani, otΩe, I Dk e−1 ∪ ⊆ I Dk w−1 ∪ abo I Dk w−1 ∪ ⊆ I Dk e−1 ∪ . A. Qkwo prypustyty, wo I Dk e−1 ∪ ⊆ I Dk w−1 ∪ , to e I Dk w∈ −1 ∪ . Oskil\- ky rank ( e ) = k, to e Dw∈ . Zvidsy vyplyva[ SeS = SwS. Supereçnist\. V. Qkwo Ω I Dk w−1 ∪ ⊆ I Dk e−1 ∪ , to w I Dk e∈ −1 ∪ . Zvidsy vyplyva[, wo SeS = SwS. Supereçnist\. Dovedemo spravedlyvist\ implikaci] (4) → (5). OtΩe, nexaj napivhrupa S zadovol\nq[ umovu L. PokaΩemo, wo koΩnyj ideal napivhrupy S [ ranhovym. Nexaj I — dovil\nyj ideal. Poznaçymo çerez a element najbil\ßoho ranhu sered usix elementiv idealu I. Nexaj rank ( a ) = k , a element b takyj, wo rank ( b ) = k . Oskil\ky rank ( b ) = rank ( a ) , to SaS = SbS. Ale SaS ⊆ I, tomu b ∈ I. Dali, ideal I mistyt\ idempotent ranhu k, a otΩe (ce lehko ob©runtu- vaty), dlq bud\-qkoho nevid’[mnoho çysla m ( )m k< isnu[ idempotent, ranh qko- ho dorivng[ m, pryçomu cej idempotent naleΩyt\ I. Mirkugçy tak samo, qk i vywe, oderΩu[mo, wo vsi elementy ranhu m naleΩat\ idealu I. OtΩe, Ik = I. Implikaciq (5) → (1) [ oçevydnog. Dovedemo spravedlyvist\ implikaci] (5) → (3). Nexaj I — dovil\nyj ideal napivhrupy S. Za umovog vin [ ranhovym, tobto Ik = I dlq deqkoho k N∈ 0 . Dovedemo, wo vin [ holovnym. Nexaj a I∈ , pryçomu rank ( a ) = k . Rozhlqnemo holovnyj ideal SaS. Za umovog vin [ ranhovym. OtΩe, SaS = Im dlq deqkoho m N∈ 0 . Ale a SaS∈ , tomu rank ( a ) ≤ ≤ m , tobto k ≤ m . Oskil\ky k ≤ m , to I Ik m⊆ . Krim c\oho, SaS I Ik⊆ = . Z ostannix dvox vklgçen\ vyplyva[, wo I I SaSk m= = . Dovedenyx implikacij dostatn\o, wob stverdΩuvaty poparnu ekvivalentnist\ umov (1) – (5). 4. Budova bud\-qko] konhruenci] perestavno] inversno] napivhrupy skin- çennoho ranhu. V c\omu punkti dovedemo osnovnu teoremu statti (teoremu44). Spoçatku sformulg[mo potribnyj rezul\tat (dyv. [1], p. 4). Teorema.3. Nexaj S — napivhrupa, I1 i I 2 — ]] idealy, pryçomu I 1 ⊆ I2 . Nexaj Θ1 ta Θ2 — konhruenci] na napivhrupi S taki, wo Θ1 = I I1 1× ∪ Ω i Θ2 = I I2 2× ∪ σ , de Ω ⊆ H i σ ⊆ H, a H — vidnoßennq Hrina. Todi Θ Θ1 2� = Θ Θ2 1� . Teper sformulg[mo osnovnyj rezul\tat statti. Teorema.4. Nexaj S — inversna napivhrupa z nulem 0, napivreßitka idem- potentiv qko] ma[ skinçennu dovΩynu. Bud\-qki dvi konhruenci] napivhrupy S perestavni todi i til\ky todi, koly ]] idealy linijno vporqdkovani i koΩna konhruenciq Θ ma[ formu Θ = I I× ∪ Ω , de I — ideal napivhrupy S, Ω ⊆ H ( H — vidnoßennq Hrina). ISSN 0041-6053. Ukr. mat. Ωurn., 2005, t. 57, # 4 KONHRUENCI} PERESTAVNO} INVERSNO} NAPIVHRUPY SKINÇENNOHO RANHU 473 Dovedennq. U teoremi43 v zahal\nij formi dovedeno dostatnist\. Dove- demo teper neobxidnist\. OtΩe, nexaj bud\-qki dvi konhruenci] na napivhrupi S [ perestavnymy. Todi, qk vidomo [4] (teorema44), ]] idealy linijno vporqdkovani, a otΩe, za teoremog42 koΩnyj ideal napivhrupy S [ ranhovym. Dali, nexaj Θ — dovil\na konhruenciq napivhrupy S. Lehko pereviryty, wo IΘ = { },x S x∈ 〈 〉 ∈0 Θ — ideal napivhru- py S, otΩe, isnu[ çyslo k take, wo IΘ = Ik = { }( )x S x k∈ ≤rank . Nexaj 〈 〉 ∈a b, Θ, pryçomu rank ( a ) > k . PokaΩemo, wo i rank ( b ) > k . Dijs- no, qkwo prypustyty protyleΩne, tobto rank ( b ) ≤ k , to b Ik∈ , a tomu i a Ik∈ . OtΩe, rank ( a ) ≤ k . Supereçnist\. Teper pokaΩemo, wo rank ( a ) = rank ( b ) . Prypustymo protyleΩne, tobto rank ( a ) ≠ rank ( b ) . Dlq konkretnosti budemo vvaΩaty, wo rank ( a ) = m , rank ( b ) = r , pryçomu k < m < r . Poznaçymo çerez Σ konhruencig Risa I Im m× ∪ ∆ . Nexaj c S∈ takyj, wo rank ( c ) = k . Oskil\ky 〈 〉 ∈c a, Σ i 〈 〉 ∈a b, Θ, to 〈 〉 ∈c b, Σ Θ� . Za umovog Θ Σ� = Σ Θ� , tomu 〈 〉 ∈c b, Θ Σ� . Ce oznaça[, wo isnu[ element d takyj, wo 〈 〉 ∈c d, Θ i 〈 〉 ∈d b, Σ . Oskil\ky 〈 〉 ∈c d, Θ i c Ik∈ , to d Ik∈ . Dali, oskil\ky 〈 〉 ∈d b, Σ , to d = b abo 〈 〉 ∈ ×d b I Im m, . Qkwo d = b , to rank ( b ) ≤ k . Supereçnist\. Qkwo Ω 〈 〉 ∈ ×d b I Im m, , to rank ( b ) ≤ m . Supereçnist\. Takym çynom, rank ( a ) = rank ( b ) . Teper pokaΩemo, wo 〈 〉 ∈a b H, , tobto aa−1 = bb−1 i a a−1 = b b−1 . Oskil\- ky 〈 〉 ∈a b, Θ, to 〈 〉 ∈−a aa b, 1 Θ . Dlq bud\-qko] inversno] napivhrupy vykonu[t\- sq nerivnist\ aa b−1 ≤ b. Qkwo prypustyty, wo aa b−1 < b, to za lemog48 rank ( )aa b−1 < rank ( b ) . Z inßoho boku, 〈 〉 ∈−b aa b, 1 Θ , tomu rank ( )aa b−1 = = rank ( b ). Supereçnist\. OtΩe, aa b−1 = b . Zvidsy aa bb− −1 1 = bb−1. Takym çynom, bb−1 ≤ aa−1. Qkwo prypustyty, wo bb−1 < aa−1, to rank ( b ) < < rank ( a ) . Supereçnist\. OtΩe, aa−1 = bb−1. Analohiçno moΩna dovesty, wo a a−1 = b b−1 . Takym çynom, 〈 〉 ∈a b H, . 1. Dereç V. D. Pro perestavni konhruenci] na antyhrupax skinçennoho ranhu // Ukr. mat. Ωurn. – 2004. – 56, # 3. – S. 346 – 351. 2. Klyfford A., Preston H. Alhebrayçeskaq teoryq poluhrupp: V 2 t. – M.: Myr, 1972. – T.1. – 286 s. 3. Petrich M. Inverse semigroups. – New York etc.: John Willey and Sons, 1984. – 674 p. 4. Hamilton H. Permutability of congruences on commutative semigroups // Semigroup Forum. – 1975. – 10, # 1. – P. 55 – 66. OderΩano 16.03.2004 ISSN 0041-6053. Ukr. mat. Ωurn., 2005, t. 57, # 4
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spelling umjimathkievua-article-36132020-03-18T20:00:05Z Congruences of a Permutable Inverse Semigroup of Finite Rank Конгруенції переставної інверсної напівгрупи скінченного рангу Derech, V. D. Дереч, В. Д. We describe the structure of any congruence of a permutable inverse semigroup of finite rank. Описано будову будь-якої конгруенції переставної інверсної напівгрупи скінченного рангу. Institute of Mathematics, NAS of Ukraine 2005-04-25 Article Article application/pdf https://umj.imath.kiev.ua/index.php/umj/article/view/3613 Ukrains’kyi Matematychnyi Zhurnal; Vol. 57 No. 4 (2005); 469–473 Український математичний журнал; Том 57 № 4 (2005); 469–473 1027-3190 uk en https://umj.imath.kiev.ua/index.php/umj/article/view/3613/3957 https://umj.imath.kiev.ua/index.php/umj/article/view/3613/3958 Copyright (c) 2005 Derech V. D.
spellingShingle Derech, V. D.
Дереч, В. Д.
Congruences of a Permutable Inverse Semigroup of Finite Rank
title Congruences of a Permutable Inverse Semigroup of Finite Rank
title_alt Конгруенції переставної інверсної напівгрупи скінченного рангу
title_full Congruences of a Permutable Inverse Semigroup of Finite Rank
title_fullStr Congruences of a Permutable Inverse Semigroup of Finite Rank
title_full_unstemmed Congruences of a Permutable Inverse Semigroup of Finite Rank
title_short Congruences of a Permutable Inverse Semigroup of Finite Rank
title_sort congruences of a permutable inverse semigroup of finite rank
url https://umj.imath.kiev.ua/index.php/umj/article/view/3613
work_keys_str_mv AT derechvd congruencesofapermutableinversesemigroupoffiniterank
AT derečvd congruencesofapermutableinversesemigroupoffiniterank
AT derechvd kongruencííperestavnoíínversnoínapívgrupiskínčennogorangu
AT derečvd kongruencííperestavnoíínversnoínapívgrupiskínčennogorangu