On the Relation between Curvature, Diameter, and Volume of a Complete Riemannian Manifold

In this note, we prove that if N is a compact totally geodesic submanifold of a complete Riemannian manifold M, g whose sectional curvature K satisfies the relation K ≥ k > 0, then \(d(m,N) \leqslant \frac{\pi }{{2\sqrt k }}\) for any point m ∈ M. In the case where dim M = 2, the Gaussian...

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Date:2004
Main Authors: Nguyen, Doan Tuan, Si, Duc Quang, Нгуєн, Доан Туан, Сі, Дук Куанг
Format: Article
Language:English
Published: Institute of Mathematics, NAS of Ukraine 2004
Online Access:https://umj.imath.kiev.ua/index.php/umj/article/view/3867
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Journal Title:Ukrains’kyi Matematychnyi Zhurnal
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Ukrains’kyi Matematychnyi Zhurnal
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author Nguyen, Doan Tuan
Si, Duc Quang
Нгуєн, Доан Туан
Сі, Дук Куанг
author_facet Nguyen, Doan Tuan
Si, Duc Quang
Нгуєн, Доан Туан
Сі, Дук Куанг
author_sort Nguyen, Doan Tuan
baseUrl_str https://umj.imath.kiev.ua/index.php/umj/oai
collection OJS
datestamp_date 2020-03-18T20:12:48Z
description In this note, we prove that if N is a compact totally geodesic submanifold of a complete Riemannian manifold M, g whose sectional curvature K satisfies the relation K ≥ k > 0, then \(d(m,N) \leqslant \frac{\pi }{{2\sqrt k }}\) for any point m ∈ M. In the case where dim M = 2, the Gaussian curvature K satisfies the relation K ≥ k ≥ 0, and γ is of length l, we get Vol (M, g) ≤ \(\frac{{2l}}{{\sqrt k }}\) if k ≠ 0 and Vol (M, g ≤ 2ldiam (M) if k = 0.
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spelling umjimathkievua-article-38672020-03-18T20:12:48Z On the Relation between Curvature, Diameter, and Volume of a Complete Riemannian Manifold Про співвідношення між кривизною, діаметром та об'ємом повного ріманового многовиду Nguyen, Doan Tuan Si, Duc Quang Нгуєн, Доан Туан Сі, Дук Куанг In this note, we prove that if N is a compact totally geodesic submanifold of a complete Riemannian manifold M, g whose sectional curvature K satisfies the relation K ≥ k > 0, then \(d(m,N) \leqslant \frac{\pi }{{2\sqrt k }}\) for any point m ∈ M. In the case where dim M = 2, the Gaussian curvature K satisfies the relation K ≥ k ≥ 0, and γ is of length l, we get Vol (M, g) ≤ \(\frac{{2l}}{{\sqrt k }}\) if k ≠ 0 and Vol (M, g ≤ 2ldiam (M) if k = 0. Доведено, що якщо $N$ — компактний цілком геодезичний підмноговид повного ріманового многовиду $(M, g)$ із секційною кривизною $K$, що задовольняє умову $K ≥ k > 0$, то для будь- якої точки $m ∈ M$ виконується нерівність $d(m,N) \leqslant \frac{\pi }{{2\sqrt k }}$. У випадку, коли $\dim M = 2$, гауссова кривизна К многовиду задовольняй умову $K ≥ k > 0$ та $γ$ мак довжину $l$, отримано 21 співвідношення $\text{Vol} (M, g) ≤ \frac{{2l}}{{\sqrt k }}$ для $k ≠ 0$ та $\text{Vol} (M, g) ≤ 2l \text{diam } (M)$ для $k = 0$. Institute of Mathematics, NAS of Ukraine 2004-11-25 Article Article application/pdf https://umj.imath.kiev.ua/index.php/umj/article/view/3867 Ukrains’kyi Matematychnyi Zhurnal; Vol. 56 No. 11 (2004); 1576–1583 Український математичний журнал; Том 56 № 11 (2004); 1576–1583 1027-3190 en https://umj.imath.kiev.ua/index.php/umj/article/view/3867/4453 https://umj.imath.kiev.ua/index.php/umj/article/view/3867/4454 Copyright (c) 2004 Nguyen Doan Tuan; Si Duc Quang
spellingShingle Nguyen, Doan Tuan
Si, Duc Quang
Нгуєн, Доан Туан
Сі, Дук Куанг
On the Relation between Curvature, Diameter, and Volume of a Complete Riemannian Manifold
title On the Relation between Curvature, Diameter, and Volume of a Complete Riemannian Manifold
title_alt Про співвідношення між кривизною, діаметром та об'ємом повного ріманового многовиду
title_full On the Relation between Curvature, Diameter, and Volume of a Complete Riemannian Manifold
title_fullStr On the Relation between Curvature, Diameter, and Volume of a Complete Riemannian Manifold
title_full_unstemmed On the Relation between Curvature, Diameter, and Volume of a Complete Riemannian Manifold
title_short On the Relation between Curvature, Diameter, and Volume of a Complete Riemannian Manifold
title_sort on the relation between curvature, diameter, and volume of a complete riemannian manifold
url https://umj.imath.kiev.ua/index.php/umj/article/view/3867
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