Some simplest integral equalities equivalent to the Riemann hypothesis
UDC 511.3 We show that the following integral equalities are equivalent to the Riemann hypothesis for any real $a>0$ and any real $0<\epsilon<1,$ $\epsilon \neq 1$:\begin{gather*}\int\limits_{-\infty}^{\infty}\frac{\ln\left(\zeta\left(\dfrac{1}{2}+it\right)\rig...
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| Date: | 2022 |
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| Main Authors: | , |
| Format: | Article |
| Language: | English |
| Published: |
Institute of Mathematics, NAS of Ukraine
2022
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| Online Access: | https://umj.imath.kiev.ua/index.php/umj/article/view/6222 |
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| Journal Title: | Ukrains’kyi Matematychnyi Zhurnal |
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Ukrains’kyi Matematychnyi Zhurnal| Summary: | UDC 511.3
We show that the following integral equalities are equivalent to the Riemann hypothesis for any real $a>0$ and any real $0<\epsilon<1,$ $\epsilon \neq 1$:\begin{gather*}\int\limits_{-\infty}^{\infty}\frac{\ln\left(\zeta\left(\dfrac{1}{2}+it\right)\right)}{a+it}\,dt=-2\pi\ln\frac{a+\dfrac{1}{2}}{a}, \\ \int\limits_{-\infty}^{\infty}\frac{\ln\left(\zeta\left(\dfrac{1}{2}+it\right)\right)}{(a+it)^\epsilon}\,dt=-\frac{2\pi}{1-\epsilon}\left(\left(a+\frac{1}{2}\right)^{1-\epsilon}-a^{1-\epsilon}\right).\end{gather*} |
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| DOI: | 10.37863/umzh.v74i9.6222 |